/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 119 Heat transfer is not an intuitiv... [FREE SOLUTION] | 91Ó°ÊÓ

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Heat transfer is not an intuitive process muses the Curious Cock. Does doubling the thickness of a hamburger approximately double the cooking time? What effect does the initial temperature have on cooking time? To answer these questions, develop a model to do virtual cooking of meat of thickness \(2 L\) in a doublesided grill. The meat is initially at \(20 \% \mathrm{C}\) when it is placed in the grill and both sides experience convection heat transfer characterized by an ambient temperature of \(100^{\circ} \mathrm{C}\) and a convection coefficient of 5000 W/m \({ }^{2} \cdot \mathrm{K}\). Assume the meat to have the properties of liquid water at \(300 \mathrm{~K}\) and to be properly cooked when the center temperature is \(605 \mathrm{C}\). (a) For hamburgers of thickness \(2 L=10,20\), and 30 \(\mathrm{mm}\), calculate the time for the center to reach the required cooking temperature of \(60 \mathrm{C}\). Determine a relationship between the cooking time and the thickness. For your solution, use the finite-element method of FEHT, the ready-to-solve model in the ModelSTransient Conduction/Plane Wall section of \(I H T\), or a numerical procedure of your choice. For one of the thicknesses, use an appropriate anaIytical solution to validate your numerical results. (b) Without performing a detailed numerical solution, but drawing on the recults of part (a), what can you say about the effect on the cooking time of changing the initial temperature of the meat from \(20{ }^{\circ} \mathrm{C}\) to \(5^{\circ} \mathrm{C}\) ? You may use your numerical model from part (a) to confirm your assessment.

Short Answer

Expert verified
Doubling thickness more than doubles cooking time; lower initial temperature likely increases it.

Step by step solution

01

Understand the Problem

We're asked to determine if doubling hamburger thickness doubles cooking time and how initial temperature affects cooking time. We model this process assuming meat properties like water at 300K, ambient temperature of 100°C, required center cooking temperature of 60°C, and using convection heat transfer. Thicknesses to consider are 10mm, 20mm, and 30mm.
02

Setup Mathematical Model

The model uses the heat equation and boundary conditions to simulate the cooking process. Meat properties equivalent to liquid water are assumed, implying a thermal conductivity, density, and specific heat resembling water at 300K. We'll need computational tools like numerical methods (finite-element method or other) to solve the temperature distribution.
03

Perform Numerical Simulations

Using a numerical method, simulate for each thickness (10mm, 20mm, 30mm) and calculate the time required for the center to reach 60°C. The model should simulate how heat transfers from the grill surface with a convection coefficient of 5000 W/m²·K to the initially 20°C meat.
04

Analysis and Derive Relationship

After simulations, compare cooking times for different thicknesses. Analyze results to establish a relationship between thickness ( 2L=10, 20, and 30 mm ) and cooking time. Typically, thicker meat takes longer due to the increased distance for heat to conduct.
05

Analytical Solution Verification

For the 10mm thickness, apply an analytical solution to the heat conduction equation (assuming infinite plate approximation) to validate the numerical results. The time to reach 60°C at the center should closely match the numerically obtained time.
06

Initial Temperature Effect

Examine the effect of changing initial meat temperature to 5°C on cooking time. Estimate how longer the meat would take to reach 60°C based on part (a) simulations and consider repeating a simulation if needed to confirm results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Heat Transfer
Convection heat transfer is a fundamental concept in understanding how heat moves through fluids and gases, such as the air surrounding a cooking hamburger. It occurs when molecules in a fluid or gas get heated, causing them to move and transfer energy to an object. In our model, the hamburger experiences convection heat transfer on both sides from the grill, which heats the meat by transferring thermal energy from the ambient air set at 100°C.
The convection process depends largely on two main factors:
  • The convection coefficient, which influences the rate of heat transfer.
  • The temperature difference between the grill and meat.
This thermal interaction is crucial as it impacts how quickly the meat cooks from the outside in. In this scenario, a high convection coefficient of 5000 W/m²·K is used, signifying a rapid heat transfer condition, which is typical in cooking situations involving grills or ovens.
Numerical Simulation
Numerical simulations in this context refer to solving heat transfer equations that cannot be easily solved by hand. In analyzing the cooking time of meat, simulations help to visualize how heat penetrates the meat and reaches the center. We utilize computational tools, such as the finite element method (FEM), to approximate solutions to the heat distribution equations governing the problem.
By discretizing the meat into smaller regions, the FEM allows us to calculate temperature changes over time across these regions. This simulation is crucial when dealing with non-trivial shapes and conditions, as it adapts to various thicknesses and initial temperatures of hamburgers. Through these simulations, students can grasp the mechanics of heat transfer and observe the effect of different cooking conditions, such as varying thicknesses and starting temperatures, on cooking time.
Cooking Time Analysis
Analyzing cooking time involves observing how long it takes for heat to travel from the surface to the center of the meat and raise it to the desired temperature. For this analysis, it was noted that as the thickness of the hamburger increases, the cooking time also increases.
  • Thicker meat means more material for the heat to penetrate, thus requiring more time.
  • The center of the meat is seen to heat slower as it remains insulated from the quick heat transfer at the surface.
Our study also examined the influence of initial temperature. Lowering the initial temperature of the hamburger prolongs the cooking time because there is a greater difference between the initial and final temperature that needs to be achieved.
Finite Element Method
The finite element method (FEM) used here is a versatile computational tool in modeling complex physical systems, like heat transfer in cooking. FEM works by breaking down a large problem into smaller, simpler parts called finite elements. These simpler parts are then solved individually and collectively, which provides an accurate approximation of the solution to the entire problem.
In the case of our hamburger model, FEM divided the meat into discrete elements, allowing us to simulate how heat flows through it over time. This method is particularly advantageous as it can adapt to different configurations, such as changes in meat thickness and initial temperature conditions. By leveraging FEM, we can obtain detailed insights into the temperature distribution within the burger throughout the cooking process, thereby understanding the intricacies of heat transfer and aiding in making informed predictions about cooking times.

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Most popular questions from this chapter

Two large blocks of different materials, such as copper and concrete, have been sitting in a room \(\left(23^{\circ} \mathrm{C}\right)\) for a very lone time. Which of the two blocks, if either, will feel colder to the touch? Assume the blocks to be seminfinite solids and your hand to be at a temperaturt of \(37^{\circ} \mathrm{C}\).

A solid steel sphere (AISI 1010), \(300 \mathrm{~mm}\) in diameter, is couted with a dielectric material layer of thickness \(2 \mathrm{~mm}\) and thermal conductivity \(0.04 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The couted sphere is initially at a uniform temperabure of \(500^{7} \mathrm{C}\) and is suddenly quenched in a large oil bath for which \(T_{x}=100^{\circ} \mathrm{C}\) and \(h=3300 \mathrm{~W} / \mathrm{m}^{2}-\mathrm{K}\). Estimate the time required for the coated sphere temperature to reach \(140^{\circ} \mathrm{C}\). Hint: Neglect the effect of energy storage in the dielectric material, since its thermal capocitance \((\rho \in V)\) is small compared to that of the steel sphere.

Annealing is a process by which steel is reheated and then cooled to make it less brittle. Consider the reheat stage for a 100 -mm-thick steel plute \(\left(\rho=7830 \mathrm{~kg} / \mathrm{m}^{3}\right.\), \(c=550 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\), which is initially at a uniform temperature of \(T_{i}=200^{2} \mathrm{C}\) and is to be heated to a minimum temperature of \(550^{+} \mathrm{C}\). Heating is effected in a gas-fired furnace, where products of combustion at \(T_{\mathrm{a}}=800^{\circ} \mathrm{C}\) maintain a convection coefficient of \(h=250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) on both surfaces of the plate. How long should the plate be left in the furnace?

A chip that is of length \(L=5 \mathrm{~mm}\) on a side and thick. ness \(t=I \mathrm{~mm}\) is encased in a ceramic substrate, and its exposed surface is convectively cooled by a diefectric liquid for which \(h=150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(T_{\mathrm{z}}=20^{\circ} \mathrm{C}\). In the off-mode the chip is in thermal equilibrium with the coolant \(\left(T_{i}=T_{*}\right)\). When the chip is energized, however, its Icmperafure increases until a new steady-state is established. For purpeises of analysis, the cnergized chip is characterized by uniform volumetric heating with \(q=9 \times 10^{6} \mathrm{~W} / \mathrm{m}^{3}\). Assuming an infinite contacl resistance between the chip and substrate and negligible conduction resistance within the chip. determine the steady-state chip temperature \(T_{f}\). Following activation of the chip, how long does it take to come within \(1^{-1} C\) of this temperature? The chip density and specific heat are \(\rho=2000 \mathrm{~kg} / \mathrm{m}^{3}\) and \(c=700 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), respectively.

It is well known that, although two materials are at the same temperature, one may feel cooler to the touch than the other. Consider thick plates of copper and glass, each at an initial temperature of \(300 \mathrm{~K}\). Assuming your finger to be at an initial temperature of \(310 \mathrm{~K}\) and to have thermophysical properties of \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(k=0.625 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), determine whether the copper or the glass will feel cooler to the touch.

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