/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A 100 -mm-long, hollow iron cyli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 100 -mm-long, hollow iron cylinder is exposed to a \(1000^{\circ} \mathrm{C}\) carburizing gas (a mixture of \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\) ) at its inner and outer surfaces of radii \(4.30\) and \(5.70 \mathrm{~mm}\), respectively. Consider steady-state conditions for which carbon diffuses from the inner surface of the iron wall to the outer surface and the total transport amounts to \(3.6 \times 10^{-3} \mathrm{~kg}\) of carbon over 100 hours. The variation of the carbon composition (weight \% carben) with radius is tabulated for selected radii.

Short Answer

Expert verified
Calculate the diffusion coefficient using Fick's First Law for steady-state diffusion through a cylindrical wall.

Step by step solution

01

Understand the Problem

We have a hollow cylinder with an inner radius of 4.30 mm and an outer radius of 5.70 mm. Carbon diffuses through the iron cylinder over a set period at high temperatures. We are tasked with analyzing this diffusion process under steady-state conditions to understand how carbon content changes with radius.
02

Identify the Governing Equation

Since we are considering steady-state diffusion and the geometry is cylindrical, we focus on Fick's First Law as adapted for cylindrical coordinates: \[ J = -D \frac{dc}{dr} \] where \( J \) is the flux, \( D \) is the diffusion coefficient, and \( \frac{dc}{dr} \) is the concentration gradient of carbon with respect to the radius.
03

Recognize Boundary Conditions

The boundary conditions are that the concentration on the inner surface (radius = 4.30 mm) and the outer surface (radius = 5.70 mm) are known from the variation of carbon composition with radius. This will allow us to set up the mathematical model, integrating the concentration profile over the cylinder's length.
04

Calculate Total Carbon Transport

The problem states that 3.6 × 10^{-3} kg of carbon is transported over 100 hours, or 360000 seconds. This allows us to determine the overall flux \( J \) across the cylinder using the formula for mass transport: \[ M = A t J \] where \( M \) is the total mass transported, \( A \) is the surface area for diffusion, and \( t \) is the time period.
05

Set Up and Solve the Integration

Using known concentrations at specific radii, integrate the radial concentration gradient to calculate \( D \). The calculation involves setting up a proper material balance over the hollow cylindrical section, where the integral of flux multiplied by the area between the inner and outer radii over time should equal the given mass transport. Solve it to get the diffusion coefficient.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Steady-State Diffusion
Steady-state diffusion refers to a condition where the concentration of diffusing species does not change with time at any point in the system. This means that, for this exercise, as carbon moves from the inner to the outer surface of the hollow iron cylinder, the rate of diffusion remains constant over time. In practical terms, the steady-state condition arises when the input rate of carbon matches the output rate, leading to a uniform flux or rate of transfer through the medium.
Understanding steady-state diffusion is crucial because it simplifies the analysis by allowing the assumption that the concentration profile remains unchanged over the period of observation. This is important for both predicting material behavior and for accurately solving problems concerning the transport of atoms or molecules within solid structures such as the hollow iron cylinder in this exercise.
Fick's First Law
Fick's First Law of Diffusion is instrumental in understanding how substances move through materials. It states that the flux, which is the amount of substance that flows through a unit area per unit time, is proportional to the concentration gradient. Mathematically, it's expressed as:\[ J = -D \frac{dc}{dx} \]where:
  • \(J\) is the diffusion flux.
  • \(D\) is the diffusion coefficient, a parameter that describes the ease with which a substance can move through another medium.
  • \(\frac{dc}{dx}\) is the concentration gradient, indicating how a substance’s concentration changes with distance.
In this exercise, since diffusion is occurring within a cylindrical geometry, the law is adapted to cylindrical coordinates. This modification allows the calculation of flux with respect to the radial distance \( r \), not a linear distance. Therefore, Fick’s First Law helps us determine how carbon atoms move through the cylindrical structure, offering insights into engineering applications like carburizing processes.
Cylindrical Coordinates
In contrast to the Cartesian system, cylindrical coordinates are better suited for problems involving circular or cylindrical geometries. This coordinate system uses radius \( r \), angle \( \theta \), and height \( z \) to describe the position of points in a cylinder. For this exercise, only radial diffusion is considered, simplifying the problem to changes occurring merely in the \( r \)-direction.
The importance of using cylindrical coordinates in this context lies in its ability to conform to the natural shape of the system – a hollow cylinder. This coordinate system simplifies the mathematical modeling of diffusion processes. When modeling diffusion in the given problem, the differential volume elements and flux expressions become easier to express and integrate. Thus, by adapting mathematical equations to cylindrical coordinates, practitioners can more accurately analyze and predict mass transport across cylindrical structures.
Diffusion Coefficient
The diffusion coefficient \( D \) is a fundamental parameter in diffusion problems, representing how easily a substance can diffuse through a medium. It depends on several factors like temperature, the nature of the diffusing substance, and the medium in which diffusion is happening. In general, higher temperatures tend to increase \( D \), thereby accelerating diffusion processes.
In the exercise, carbon diffuses through an iron cylinder at a high temperature of \(1000^{\circ} C\). This elevated temperature might increase the diffusion coefficient, facilitating the movement of carbon atoms. Calculating \( D \) involves understanding the overall mass transfer and integrating the concentration gradient across the geometry. By knowing the diffusion coefficient, engineers and materials scientists can better design processes like carburizing, which is a heat treatment method used to harden the surface of metals by diffusing carbon into their surface.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assuming air to be composed exclusively of \(\mathrm{O}_{2}\) and \(\mathrm{N}_{2}\), with their partial pressures in the ratio 0.21:0.79, what are their mass fractions?

A mixture of \(\mathrm{CO}_{2}\) and \(\mathrm{N}_{2}\) is in a container at \(25^{\circ} \mathrm{C}\), with each species having a partial pressure of 1 bar. Calculate the molar concentration, the mass density, the mole fraction, and the mass fraction of each species.

Pulverized coal pellets, which may be approximated as carton spheres of radius \(r_{v}=1 \mathrm{~mm}\), are bumed in a pure oxygen atmosphere at \(1450 \mathrm{~K}\) and \(\mathrm{I}\) atm. Oxygen is transferred to the particle surface by diffusion, where it is consumed in the reaction \(\mathrm{C}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}\). The reaction rate is first order and of the form \(\hat{N}_{0_{2}}=\) \(-k_{1}^{*} C_{\mathrm{O}_{2}}\left(r_{e}\right)\), where \(k_{1}^{*}=0.1 \mathrm{~m} / \mathrm{s}\). Neglecting changes in \(r_{e}\) determine the steady-state \(\mathrm{O}_{2}\) molar consumption rate in \(\mathrm{kmol} / \mathrm{s}\). At \(1450 \mathrm{~K}\), the binary diffusion coefficient for \(\mathrm{O}_{2}\) and \(\mathrm{CO}_{2}\) is \(1.71 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}\).

Gaseous bydrogen at 10 bars and \(27^{\circ} \mathrm{C}\) is stored in a 100 -mm-diameter spherical tank having a steel wall \(2 \mathrm{~mm}\) thick. The molar concentration of hydrogen in the steel is \(1.50 \mathrm{kmol} / \mathrm{m}^{3}\) at the inner surface and negligible at the outer surface, while the diffusion coeffcient of hydrogen in steel is approximately \(0.3 \times\) \(10^{-12} \mathrm{~m}^{2} / \mathrm{s}\). What is the initial rate of mass loss of hydrogen by diffusion through the tank wall? What is the initial rate of pressure drop within the tank?

A He-Xe mixture containing \(0.75\) mole fraction of helium is used for cooling of electronics in an avionics application. At a temperature of \(300 \mathrm{~K}\) and atmospheric pressure, calculate the mass fraction of helium and the mass density, molar concentration, and molecular weight of the mixture. If the cooling system capacity is 10 liters, whut is the mass of the coolant?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.