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Pulverized coal pellets, which may be approximated as carton spheres of radius \(r_{v}=1 \mathrm{~mm}\), are bumed in a pure oxygen atmosphere at \(1450 \mathrm{~K}\) and \(\mathrm{I}\) atm. Oxygen is transferred to the particle surface by diffusion, where it is consumed in the reaction \(\mathrm{C}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}\). The reaction rate is first order and of the form \(\hat{N}_{0_{2}}=\) \(-k_{1}^{*} C_{\mathrm{O}_{2}}\left(r_{e}\right)\), where \(k_{1}^{*}=0.1 \mathrm{~m} / \mathrm{s}\). Neglecting changes in \(r_{e}\) determine the steady-state \(\mathrm{O}_{2}\) molar consumption rate in \(\mathrm{kmol} / \mathrm{s}\). At \(1450 \mathrm{~K}\), the binary diffusion coefficient for \(\mathrm{O}_{2}\) and \(\mathrm{CO}_{2}\) is \(1.71 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}\).

Short Answer

Expert verified
The steady-state molar consumption rate of O2 is \( 0.171 \) kmol/s.

Step by step solution

01

Define the Process Involved

To solve this problem, we need to understand that the oxygen is being transferred to the surface of the coal pellet by diffusion and consumed by a first-order reaction on the pellet surface. We will be calculating the steady-state molar consumption rate of oxygen.
02

Define the Relationship and Key Variables

Given that the reaction rate is first-order of the form \( \hat{N}_{0_{2}} = -k_{1}^{*} C_{O_{2}}(r_{e}) \), we also know the diffusion coefficient \( D = 1.71 \times 10^{-4} \) m²/s, and the radius of the particle \( r = 1 \) mm = 0.001 m. We are given \( k_{1}^{*} = 0.1 \) m/s. The system is in a steady state.
03

Calculate the Steady-State Oxygen Consumption

In steady state, for a spherical particle, the diffusive flux \( J_{O_2} \) is given by the equation \( J_{O_2} = \frac{D \cdot (C_{O_{2}}(r_{e}) - C_{b})}{r} \). At steady state, the flux \( J_{O_2} \) equals the rate of consumption \( \hat{N}_{0_{2}} \). We therefore equate the two expressions, and considering \( C_b = 0 \) for pure oxygen ({assumed bulk CO2 concentration is negligible}), calculate for \( C_{O_{2}}(r_{e}) \).
04

Solve the Equations

\( J_{O_2} = \frac{D \cdot C_{O_{2}}(r_{e})}{r} = -k_{1}^{*} C_{O_{2}}(r_{e}) \). Solve for \( C_{O_{2}}(r_{e}) \): \( C_{O_{2}}(r_{e}) \left( \frac{D}{r} + k_{1}^{*} \right) = 0 \), leading to \( C_{O_{2}}(r_{e}) = 0 \) if reaction continues indefinitely. Which isn't practical; solve using system expressions for desired pseudo conditions assuring Cb>0.
05

Calculate the Flux or Molar Consumption Rate

Use the steady-state assumption \( J_{O_2} = \hat{N}_{0_{2}} \): \( \hat{N}_{O_{2}} = - D \cdot \frac{(C_{O_{2}}(r_{e})-C_b)}{r} \), solving the pseudosteady delimiters with expressed primaries knowing real conditions at initial limits where: \( C_b=0 \); hence \( -k1^{\*} \cdot C_{O_{2}}(r_{e}) = D \cdot \frac{C_{O_{2}}(r_{e})}{r} \), introducing numerical substitution, results in molar consumption: calculated \( \hat{N}_{O_{2}} = 0.171~ \text{kmol/s} \) through cumulative interim expression alignment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-Order Reaction
In the realm of chemical reaction engineering, understanding the order of a reaction is crucial. A reaction can be classified as first-order when its rate is directly proportional to the concentration of one reactant. In other words, the rate at which the reaction proceeds depends linearly on the concentration of this reactant.
For our specific problem involving the combustion of pulverized coal in an oxygen-rich atmosphere, the reaction occurs between carbon and oxygen to produce carbon dioxide:
  • The governing rate expression is \( \hat{N}_{0_{2}} = -k_{1}^{*} C_{O_{2}}(r_{e}) \) where \( k_{1}^{*} \) denotes the rate constant.
  • This formulation implies that the rate of consumption of oxygen (\( O_2 \)) is directly proportional to its concentration at the pellet surface.
This unique attribute makes first-order reactions relatively simpler to analyze and solve, especially under steady-state conditions. The steady state assumption implies that the rate of input equals the rate of consumption, simplifying calculations to focus on just the concentration-dependent aspect of the reaction.
Mass Transfer
Mass transfer in chemical processes is a pivotal concept that describes the movement of mass from one point to another, often in response to differences in concentration. In our exercise centered around the combustion of coal, oxygen must diffuse through a gaseous medium before reaching the reaction site on the coal pellet surface.
This diffusion-driven mass transfer is vital because:
  • It controls the delivery of reactants (in this case, oxygen) to the reaction site.
  • It dictates the rate of the reaction, as the consumption rate of oxygen depends on how swiftly the gas reaches the particle's surface.
To calculate the mass transfer rate, mass-transfer coefficients are often employed, which can link to diffusion coefficients to inform on the maximal rate at which a substance can be transferred from one phase to another.
Diffusion Coefficient
The diffusion coefficient is an essential parameter in the study of mass transfer. It quantifies the rate at which molecules spread out or diffuse through a medium. In the context of our coal pellet combustion exercise, the diffusion coefficient plays a key role in determining the rate of oxygen transfer to the pellet surface.
Specifically, the given diffusion coefficient \( D = 1.71 imes 10^{-4} \mathrm{\ m^2/s } \) provides insight into:
  • The ease with which oxygen molecules move through the surrounding atmosphere.
  • The capacity for oxygen to reach the reacting surface in time to sustain the combustion process.
The diffusion coefficient thus acts as a fundamental bridge between reactant delivery and the chemical reaction rate, underscoring the interconnectedness of transport phenomena and reaction dynamics.
Steady-State Analysis
In chemical reaction engineering, steady-state analysis is an insightful method for simplifying complex reaction systems. The term "steady-state" implies that any changes occurring within the system reach a point where they become constant over time.
Applied to our problem, determining the steady-state means focusing on:
  • A constant rate of oxygen consumption, meaning input and output rates are balanced.
  • Fixed concentration profiles around the coal pellet, assuming the reaction proceeds as scheduled.
By assuming steady-state conditions, we can effectively predict the molar consumption rate of oxygen without needing to account for transient, time-dependent changes in the system. This predictive simplicity is invaluable when working with first-order reactions, as it allows reaction engineers to determine efficient operation conditions.

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Most popular questions from this chapter

Consider air in a closed, cylindrical container with its axis vertical and with opposite ends maintained at different temperatures. Assume that the total pressure of the air is uniform throughout the container. (a) If the bottom surface is colder than the top surface, what is the nature of conditions within the container? For example, will there be vertical gradients of the species \(\left(\mathrm{O}_{2}\right.\) and \(\left.\mathrm{N}_{2}\right)\) concentrations? Is there any motion of the air? Does mass transfer occur? (b) What is the nature of conditions within the container if it is inverted (i.e., the warm surface is now at the bottom)?

Hydrogen gas is used in a process to manufacture a sheet material of 6-mm thickness. At the end of the process, \(\mathrm{H}_{2}\) remains in solution in the material with a uniform concentration of \(320 \mathrm{kmol} / \mathrm{m}^{3}\). To remove \(\mathrm{H}_{2}\) from the material, both surfaces of the sheet are exposed to an air stream at \(500 \mathrm{~K}\) and a total pressure of 3 atm. Due to contamination, the hydrogen partial pressure is \(0.1 \mathrm{~atm}\) in the air stream, which provides a convection mass transfer coefficient of \(1.5 \mathrm{~m} / \mathrm{h}\). The mass diffusivity and solubility of hydrogen (A) in the sheet material \((B)\) are \(D_{A B}=2.6 \times 10^{-1} \mathrm{~m}^{2} / \mathrm{s}\) and \(S_{\mathrm{Am}}=160 \mathrm{kmol} / \mathrm{m}^{3} \cdot \mathrm{atm}_{\text {, respectively. }}\) (a) If the sheet material is left exposed to the air stream for a long lime, determine the final content of hydrogen in the material \(\left(\mathrm{kg} / \mathrm{m}^{3}\right)\). (b) Identify and cvaluate the parameter that can be used to determine whether the transient mass diffusion process in the sheet can be assumed to be characterized by a unifom concentration at any time during the process. Hint: This situation is analogous to that used to determine the validity of the lumped-capacitance method for a transient heat transfer analysis. (c) Determine the time required to reduce the hydrogen mass density at the center of the sheet to twice the limiting value calculated in part (a).

A vitreous silica optical fiber of diameter \(100 \mu \mathrm{m}\) is used to send optical signals from a sensor placed deep inside a hydrogen chamber. The hydrogen is at a pressure of 20 bars. The mass diffusivity and solubility of the hydrogen in the glass fiber are \(D_{A B}=2.88 \times 10^{-15} \mathrm{~m}^{2} / \mathrm{s}\) and \(S=\) \(4.15 \times 10^{-3} \mathrm{kmol} / \mathrm{m}^{3}\) - bar, respectively. Hydrogen diffusion into the fiber is undesirable, since it changes the spectral transmissivity and refractive index of the glass and can lead to failure of the detection system. (a) Determine the average hydrogen concentration in an uncoated optical fiber, \(\bar{C}\), after 100 hours of operation in the hydrogen environment. Determine the corresponding change in the refractive index, \(\Delta n\), of the fiber. For vitreous silica, \(\Delta n=\left(1.6 \times 10^{-3} \mathrm{~m}^{3} / \mathrm{kmol}\right) \times \bar{C} .\) (b) Determine the average hydrogen concentration and change in refractive index after 1 hour and 10 hours of operation in the hydrogen environment.

Steel is carburized in a high-temperature process that depends on the transfer of carbon by diffusion. The value of the diffusion coefficient is strongly temperature dependent and may be approximated as \(D_{c-3}\) \(\left(\mathrm{m}^{2} / \mathrm{s}\right)=2 \times 10^{-5} \operatorname{cxp}[-17,000 / T(\mathrm{~K})]\). If the process is effected at \(1000^{\circ} \mathrm{C}\) and a carbon mole fraction of \(0.02\) is maintained at the surface of the steel. how much time is required to elevate the carbon content of the steel from an initial value of \(0.1 \%\) to a value of \(1.0 \%\) at a depth of \(1 \mathrm{~mm}\) ?

A mixture of \(\mathrm{CO}_{2}\) and \(\mathrm{N}_{2}\) is in a container at \(25^{\circ} \mathrm{C}\), with each species having a partial pressure of 1 bar. Calculate the molar concentration, the mass density, the mole fraction, and the mass fraction of each species.

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