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Steam at \(200 \mathrm{lbf} / \mathrm{in}^{2}, 660^{\circ} \mathrm{F}\) enters a turbine operating at steady state with a mass flow rate of \(16.5 \mathrm{lb} / \mathrm{min}\) and exits at 14.7 lbffin. \({ }^{2}, 238^{\circ}\) F. Stray heat transfer and the effects of motion and gravity can be ignored. Let \(T_{0}=537^{\circ} \mathrm{R}, p_{0}=14.7 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\) Determine for the turbine (a) the power developed and the rate of exergy destruction, each in Btu/min, and (b) the isentropic and exergetic turbine efficiencies.

Short Answer

Expert verified
Calculate power developed, isentropic efficiency using enthalpy values. Find exergy destruction and exergetic efficiency using specific exergies.

Step by step solution

01

- Identify and Organize Given Data

Given:- Inlet steam conditions: Pressure = 200 lbf/in², Temperature = 660°F- Outlet steam conditions: Pressure = 14.7 lbf/in², Temperature = 238°F- Mass flow rate: \( \dot{m} = 16.5 \, \mathrm{lb/min} \)- Environmental conditions: \( T_0 = 537^{\circ} \, \mathrm{R}, \, p_0 = 14.7 \, \mathrm{lbf/in}^2 \)
02

- Convert All Temperatures to Rankine

Convert the given temperatures to Rankine (°R).\[T_{in} = 660^{\circ}F + 460 = 1120^{\circ}R\]\[T_{out} = 238^{\circ}F + 460 = 698^{\circ}R\]
03

- Calculate Specific Enthalpies

Use steam tables or thermodynamic property software to find the specific enthalpies \(h_{in}\) and \(h_{out}\) at the given inlet and outlet conditions.
04

- Calculate the Power Developed by the Turbine

The power developed by the turbine is given by: \[W_{turbine} = \dot{m} (h_{in} - h_{out})\]Substitute the values of mass flow rate and specific enthalpies.
05

- Calculate Specific Entropies

Use steam tables or thermodynamic property software to find the specific entropies \(s_{in}\) and \(s_{out}\) at the given inlet and outlet conditions.
06

- Determine Isentropic Enthalpy

Determine the enthalpy \(h_{out,s}\) corresponding to the exit pressure (14.7 lbf/in²) and the inlet entropy \(s_{in}\).
07

- Calculate Isentropic Turbine Efficiency

The isentropic turbine efficiency \( \eta_{t} \) can be calculated using:\[\eta_{t} = \]Substitute the values of enthalpies.
08

- Calculate Exergy Inlet and Outlet

Calculates the specific exergies using:\[\psi_{in} = (h_{in} - h_0) - T_0(s_{in} - s_0)\]\[\psi_{out} = (h_{out} - h_0) - T_0(s_{out} - s_0)\]
09

- Calculate the Exergy Destruction

Calculate the exergy destruction rate using:\[\dot{E}_{d} = \dot{m} (\psi_{in} - \psi_{out})\]
10

- Calculate Exergetic Efficiency

Compute the exergetic efficiency \(\eta_{ex}\) using the relation:\[\eta_{ex} = (\dot{m} (\psi_{in} - \psi_{out})) / (\dot{W})\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Efficiency
Thermodynamic efficiency refers to how effectively a device converts the input energy into useful work. For a turbine, it is often measured using isentropic efficiency. This efficiency compares the actual work output to the work output that would be achieved in the ideal case, with no irreversibilities and assuming a reversible (isentropic) process. Using the given exercise data, thermodynamic efficiency is calculated by comparing the actual enthalpy drop in the turbine to the enthalpy drop in an isentropic, or ideal, process. This ratio gives us a measure of the performance of the turbine.
Exergy Analysis
Exergy analysis helps in determining how much usable energy is available for work from a system. It provides insight into the inefficiencies present in the system by breaking down the energy into usable and unusable parts. In the exercise, exergy at the turbine inlet and outlet are crucial for calculating exergy destruction and exergetic efficiency.
The exergy of steam, denoted as \(\psi\text{subscript}{in}\text\psi\text{subscript}{out}, }\) involves terms from the first law of thermodynamics (enthalpy) and the second law (entropy). Exergy destruction is calculated as the difference in specific exergies at the inlet and the outlet, multiplied by the mass flow rate.
Exergetic efficiency is computed as the ratio of the exergy recovered to the exergy input, indicating how efficiently the system utilizes its available energy.
Isentropic Process
An isentropic process is an idealized thermodynamic process that is both adiabatic and reversible, meaning it involves no heat transfer and no entropy generation. For turbines, the isentropic process is a perfect benchmark to compare actual turbine performance. An isentropic turbine assumes no energy losses, and thus, actual turbine performance is always less efficient due to real-world irreversibilities.
In our exercise, the isentropic process helps to determine the ideal exit enthalpy (\(h_{out,s}\)). This aids in evaluating isentropic efficiency, making it a critical aspect of turbine efficiency calculations.
Power Developed
The power developed by a turbine is a measure of the energy converted from steam into mechanical work per unit time. In the given exercise, the power developed (\(W_{turbine}\)) is calculated using the mass flow rate and the difference between the specific enthalpies at the inlet and outlet. The formula used is:
\[ W_{turbine} = \dot{m} (h_{in} - h_{out}) \]
where \(\dot{m}\) is the mass flow rate, \(h_{in}\) is the enthalpy at the inlet, and \(h_{out}\) is the enthalpy at the outlet. This calculated power indicates how much energy is converted into mechanical work by the turbine.
Steam Tables
Steam tables are essential tools in thermodynamics that provide the properties of steam at different pressures and temperatures. These tables include data such as specific enthalpy, specific entropy, and other important properties for water and steam.
In the exercise, steam tables are used to find the specific enthalpies (\(h_{in}\) and \(h_{out}\)) and specific entropies (\(s_{in} and s_{out}\)) at both the inlet and outlet conditions of the turbine.
These values are crucial for calculating the power developed, isentropic efficiency, and exergy rates. Understanding steam tables is key for accurate and efficient thermodynamic calculations in engineering practices.

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Most popular questions from this chapter

Saturated water vapor at \(400 \mathrm{lbf} / \mathrm{in}^{2}\) enters an insulated turbine operating at steady state. At the turbine exit the pressure is \(0.6\) lbf/in. \({ }^{2}\) The work developed is 306 Btu per pound of steam passing through the turbine. Kinetic and potential energy effects can be neglected. Let \(T_{0}=60^{\circ} \mathrm{F}\), \(p_{0}=1 \mathrm{~atm}\). Determine (a) the exergy destruction rate, in Btu per pound of steam expanding through the turbine. (b) the isentropic turbine efficiency- (c) the exergetic turbine efficiency.

An electric water heater having a \(200-L\) capacity heats water from 23 to \(55^{\circ} \mathrm{C}\). Heat transfer from the outside of the water heater is negligible, and the states of the electrical heating element and the tank holding the water do not change significantly. Perform a full exergy accounting, in kJ, of the electricity supplied to the water heater. Model the water as incompressible with a specific heat \(c=4.18 \mathrm{~kJ} / \mathrm{kg}+\mathrm{K}\). Let \(T_{0}=23^{\circ} \mathrm{C}\).

A domestic water heater holds \(189 \mathrm{~L}\) of water at \(60^{\circ} \mathrm{C}\), \(1 \mathrm{~atm}\). Determine the exergy of the hot water, in \(\mathrm{kJ}\). To what elevation, in \(m\), would a \(1000-\mathrm{kg}\) mass have to be raised from zero elevation relative to the reference environment for its exergy to equal that of the hot water? Let \(T_{0}=298 \mathrm{~K}\), \(p_{0}=1 \mathrm{~atm}, \mathrm{~g}=9.81 \mathrm{~m} / \mathrm{s}^{2}\).

One lbmol of carbon monoxide gas is contained in a \(90-\mathrm{ft}^{3}\) rigid, insulated vessel initially at 5 atm. An electric resistor of negligible mass transfers energy to the gas at a constant rate of \(10 \mathrm{Btu} / \mathrm{s}\) for \(2 \mathrm{~min}\). Employing the ideal gas model and ignoring the effects of motion and gravity, determine (a) the change in exergy of the gas, (b) the electrical work, and (c) the exergy destruction, each in Btu. Let \(T_{0}=70^{\circ} \mathrm{F}\), \(p_{0}=1 \mathrm{~atm}\).

Air enters a compressor operating at steady state at \(T_{1}=\) \(320 \mathrm{~K}, p_{1}=2\) bar with a velocity of \(80 \mathrm{~m} / \mathrm{s}\). At the exit, \(T_{2}=550 \mathrm{~K}, p_{2}=6\) bar and the velocity is \(180 \mathrm{~m} / \mathrm{s}\). The air can be modeled as an ideal gas with \(c_{p}=1.01 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\). Stray heat transfer can be ignored. Determine, in kJ per \(\mathrm{kg}\) of air flowing, (a) the power required by the compressor and (b) the rate of exergy destruction within the compressor. Let \(T_{0}=\) \(300 \mathrm{~K}, p_{0}=1\) bar. Ignore the effects of motion and gravity.

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