/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A domestic water heater holds \(... [FREE SOLUTION] | 91Ó°ÊÓ

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A domestic water heater holds \(189 \mathrm{~L}\) of water at \(60^{\circ} \mathrm{C}\), \(1 \mathrm{~atm}\). Determine the exergy of the hot water, in \(\mathrm{kJ}\). To what elevation, in \(m\), would a \(1000-\mathrm{kg}\) mass have to be raised from zero elevation relative to the reference environment for its exergy to equal that of the hot water? Let \(T_{0}=298 \mathrm{~K}\), \(p_{0}=1 \mathrm{~atm}, \mathrm{~g}=9.81 \mathrm{~m} / \mathrm{s}^{2}\).

Short Answer

Expert verified
The exergy content of the hot water is The equivalent elevation for a mass of to have the same exergy is

Step by step solution

01

Calculating specific exergy (thermal exergy of the water)

To determine the exergy of the water, use the formula for thermal exergy: where To find specific exergy of hot water:
02

Specific heat capacity at constant pressure (The specific heat capacity of water:

Given: Initial temperature of water: Final temperature of surrounding: Calculate the change in temperature: specific exergy):
03

Calculate the exergy for the total volume of water

Volume of water in the heater is Total exergy content in the water heater:
04

Determine the elevation required for equivalent exergy

Given: mass = , gravity calculation of the elevation:: total specific exergyvalue obtained in Finally, solve for the elevation:

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Exergy Calculation
Thermal exergy refers to the maximum useful work obtainable from a thermal system as it comes into equilibrium with its surroundings. To calculate thermal exergy, we need the specific exergy formula:

\[ e = (h - h_0) - T_0(s - s_0) \]

Where:
  • \( h \) is the enthalpy of the system
  • \( h_0 \) is the enthalpy of the surroundings
  • \( T_0 \) is the reference temperature (usually the surroundings)
  • \( s \) is the entropy of the system
  • \( s_0 \) is the entropy of the surroundings
To determine the exergy of water held at a certain temperature, the change in enthalpy and entropy from the surrounding environment must be calculated. For example, if we have 189 liters of water at 60°C, the specific exergy is calculated relative to standard conditions (298 K). To calculate total exergy, this specific exergy is multiplied by the mass of the water.
Specific Heat Capacity
Specific heat capacity is a property that indicates how much heat energy a substance requires to increase its temperature by one degree. For water, the specific heat capacity at constant pressure is about 4.18 kJ/(kg·K).

We use this value to determine the heat energy involved in the temperature change of our system. For example, if water is heated from 25°C to 60°C, the change in temperature (\( \Delta T \)) is:

\[ \Delta T = 60°C - 25°C = 35°C \]

To find the thermal energy, we'd multiply the specific heat capacity by the mass and the change in temperature. This energy contributes to the calculation of enthalpy in the specific exergy formula.
Energy Conservation
Energy conservation is a fundamental principle in thermodynamics stating that energy cannot be created or destroyed, only transformed from one form to another. When calculating exergy, it's important to recognize that the total energy remains constant, but the usefulness of this energy (exergy) changes.

In practical terms, while the energy content (enthalpy) of hot water remains the same, its ability to do work (exergy) decreases as the water reaches thermal equilibrium with its surroundings.

Identifying the exergy helps in understanding how much of the energy can be efficiently converted into mechanical work or other useful forms. This concept is key when designing heating systems and evaluating their efficiency.
Mass-Elevation Equivalence
Mass-elevation equivalence refers to the idea that mechanical energy (due to elevation) can be equated to thermal exergy. This means the exergy of a heated mass can be represented as equivalent to the potential energy of a mass at a certain height.

In our problem, to find the equivalent elevation for a mass of 1000 kg, we equate the exergy to the gravitational potential energy formula:

\[ E = mgh \]

Here, \( m \) is the mass, \( g \) is the gravitational acceleration (9.81 m/s²), and \( h \) is the height. By knowing the total exergy from the water heater, we can solve for the elevation (h) that would give the same exergy as the heated water. This provides a tangible way to understand the concept of exergy in a mechanical context.
Entropy in Thermodynamic Systems
Entropy is a measure of the spread of energy in a system, indicating its disorder or randomness. In exergy calculations, entropy changes are crucial since exergy accounts for energy quality, not just quantity.

The formula for specific exergy includes entropy components \((s - s_0)\), representing the difference between system entropy and the reference environment.

For our water heater problem, to find entropy changes, we can use tables for specific entropy of water at different temperatures. This informs us how much energy has dispersed as heat.

Higher entropy means less exergy is available for performing useful work. Thus, evaluating entropy is essential for understanding and managing energy systems effectively.

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Most popular questions from this chapter

Two solid blocks, each having mass \(m\) and specific heat \(c\), and initially at temperatures \(T_{1}\) and \(T_{2}\), respectively, are brought into contact, insulated on their outer surfaces, and allowed to come into thermal equilibrium. (a) Derive an expression for the exergy destruction in terms of \(m, c, T_{1}, T_{2}\), and the temperature of the environment, \(T_{0}\) (b) Demonstrate that the exergy destruction cannot be negative. (c) What is the source of exergy destruction in this case?

An open feedwater heater operates at steady state with liquid water entering inlet 1 at 10 bar, \(50^{\circ} \mathrm{C}\), and a mass flow rate of \(10 \mathrm{~kg} / \mathrm{s}\). A separate stream of steam enters inlet 2 at 10 bar and \(200^{\circ} \mathrm{C}\).Saturated liquid at 10 bar exits the feedwater heater. Stray heat transfer and the effects of motion and gravity can be ignored. Let \(T_{0}=20^{\circ} \mathrm{C}, p_{0}=1\) bar. Determine (a) the mass flow rate of the streams at inlet 2 and the exit, cach in \(\mathrm{kg} / \mathrm{s}\), (b) the rate of exergy destruction, in \(\mathrm{kW}\), and (c) the cost of the exergy destroyed, in \(\$ /\) year, for 8400 hours of operation annually. Evaluate exergy at \(8.5\) cents per \(\mathrm{kW} \cdot \mathrm{h}\).

Air initially at 1 atm and \(500^{\circ} \mathrm{R}\) with a mass of \(2.5 \mathrm{lb}\) is contained within a closed, rigid tank. The air is slowly warmed, receiving 100 Btu by heat transfer through a wall separating the gas from a thermal reservoir at \(800^{\circ} \mathrm{R}\). This is the only energy transfer. Assuming the air undergoes an internally reversible process and using the ideal gas model, (a) determine the change in exergy and the exergy transfer accompanying heat, each in Btu, for the air as the system. (b) determine the exergy transfer accompanying heat and the exergy destruction, each in Btu, for an enlarged system that includes the air and the wall, assuming that the state of the wall remains unchanged. Compare with part (a) and comment. Let \(T_{0}=90^{\circ} \mathrm{F}, p_{0}=1 \mathrm{~atm}\).

A pump operating at steady state takes in saturated liquid water at \(65 \mathrm{lbf} / \mathrm{in}^{2}\) at a rate of \(10 \mathrm{lb} / \mathrm{s}\) and discharges water at \(1000 \mathrm{lbf} / \mathrm{in}^{2}\). The isentropic pump efficiency is \(80.22 \%\). Heat transfer with the surroundings and the effects of motion and gravity can be neglected. If \(T_{0}=75^{\circ} \mathrm{F}\), determine for the pump (a) the exergy destruction rate, in Btu/s (b) the exergetic efficiency.

Saturated water vapor at \(400 \mathrm{lbf} / \mathrm{in}^{2}\) enters an insulated turbine operating at steady state. At the turbine exit the pressure is \(0.6\) lbf/in. \({ }^{2}\) The work developed is 306 Btu per pound of steam passing through the turbine. Kinetic and potential energy effects can be neglected. Let \(T_{0}=60^{\circ} \mathrm{F}\), \(p_{0}=1 \mathrm{~atm}\). Determine (a) the exergy destruction rate, in Btu per pound of steam expanding through the turbine. (b) the isentropic turbine efficiency- (c) the exergetic turbine efficiency.

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