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Nitrogen \(\left(\mathrm{N}_{2}\right)\) at 25 bar, \(450 \mathrm{~K}\) enters a turbine and expands to \(2 \mathrm{bar}, 250 \mathrm{~K}\) with a mass flow rate of \(0.2 \mathrm{~kg} / \mathrm{s}\) The turbine operates at steady state with negligible heat transfer with its surroundings. Assuming the ideal gas model with \(k=\) \(1.399\) and ignoring the effects of motion and gravity, determine (a) the isentropic turbine efficiency. (b) the exergetic turbine efficiency. Let \(T_{0}=25^{\circ} \mathrm{C}, p_{0}=1 \mathrm{~atm}\).

Short Answer

Expert verified
For ideal turbine operating isotropically.

Step by step solution

01

- Define Given Data and Assumptions

Identify the given data and assumptions.\( P_1 = 25 \mathrm{bar} \), \( T_1 = 450 \mathrm{~K} \), \( P_2 = 2 \mathrm{bar} \), \( T_2 = 250 \mathrm{~K} \), mass flow rate \( \dot{m} = 0.2 \mathrm{~kg/s} \), \( k = 1.399 \), \( T_0 = 298 \mathrm{~K} \) (25°C), \( P_0 = 1 \mathrm{~atm} = 1.01325 \mathrm{~bar} \). Assume nitrogen behaves as an ideal gas and the process is adiabatic.
02

- Identify Isentropic Outlet Temperature

Use the isentropic relation for ideal gases to find the isentropic outlet temperature, \( T_{2s} \).\[ T_{2s} = T_1 \left( \frac{P_2}{P_1} \right)^{(k-1)/k} \] Substitute the known values: \[ T_{2s} = 450 \left( \frac{2}{25} \right)^{(1.399-1)/1.399} \] Calculate the result.
03

- Calculate Actual Work Done by Turbine

Employ the first law of thermodynamics for a steady-state adiabatic process: \[\Delta h = h_1 - h_2t\dot{Q} = 0 \rightarrow \dot{m} \cdot \Delta h = \dot{m} \cdot (h_1 - h_2) = \dot{m} \cdot c_p (T_1 - T_2) \ \dot{W}_{actual} = \dot{m} \cdot c_p (T_1 - T_2)\]Given the specific heat capacity for nitrogen
04

- Determine Isentropic Work Done

Calculate the work done under isentropic conditions: \[\dot{W}_{s} = \dot{m} \cdot c_p (T_1 - T_{2s}) \]
05

- Find Isentropic Efficiency

The isentropic efficiency of the turbine is: \[\eta_{isentropic} = \frac{\dot{W}_{actual}}{\dot{W}_{s}}\]
06

- Calculate Exergy Destruction

The exergy destruction rate due to irreversibilities is: \[\dot{X}_{destruction} = T_0 \cdot \dot{S}_{gen} \] Use: \[\dot{S}_{gen} = \dot{m} \cdot ( s_2 - s_1 )\]
07

- Determine Exergetic Efficiency

The exergetic efficiency of the turbine is given by: \[\eta_{exergetic} = 1 - \frac{\dot{X}_{destruction}}{\dot{X}_{in}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Processes
Understanding thermodynamic processes is key when analyzing turbines and similar systems. In thermodynamics, a process describes how a substance changes its state (pressure, temperature, volume, etc.). A turbine involves the expansion of gases, which affects its energy state.

The exercise specifies that the turbine operates under steady-state, meaning the properties of the system do not change over time. It also mentions an adiabatic process, where no heat is transferred to or from the surroundings. This simplifies calculations as the main energy interaction is in the form of work.

For an ideal gas like nitrogen, changes in enthalpy can be simplified using specific heat capacities. Using these properties in enthalpy change calculations, we can find out the actual and isentropic work, which are essential for determining efficiencies.
Ideal Gas Behavior
Understanding that nitrogen behaves as an ideal gas is crucial for solving the problem given. An ideal gas refers to a hypothetical gas that perfectly follows the gas laws, allowing simplifications in calculations. For air or nitrogen, this assumption holds reasonably well under many conditions including those specified in the exercise.

In the exercise, nitrogen's behavior as an ideal gas lets us apply the isentropic relations. For an ideal gas during an isentropic process, the relationship between temperatures and pressures can be expressed as:

\[ T_{2s} = T_1 \left( \frac{P_2}{P_1} \right)^{(k-1)/k} \]

Here, \(T_1\) and \(T_2s\) are the initial and isentropic outlet temperatures, \(P_1\) and \(P_2\) the initial and final pressures, and \(k\) the specific heat capacity ratio. By substituting values into this formula, we can find the isentropic outlet temperature \(T_{2s}\).

This calculated value is used to determine the isentropic work by the gas during expansion, which is essential for efficiency calculations.
Exergetic Efficiency
Exergetic efficiency evaluates how effectively a system utilizes available energy to perform work. Unlike conventional efficiency which only looks at useful output relating to input, exergetic efficiency takes into account the quality of energy.

To find the exergetic efficiency, we need to first determine the exergy destruction, which measures the energy lost due to irreversibilities in the process. This is given by:

\[ \dot{X}_{destruction} = T_0 \cdot \dot{S}_{gen} \]

where \(T_0\) is the reference temperature and \(\dot{S}_{gen}\) is the entropy generation rate. The entropy generation rate can be calculated as:

\[ \dot{S}_{gen} \text{=} \dot{m} \left(s_2 − s_1\right) \]

Here, \(s_1\) and \(s_2\) are the specific entropies at the initial and final states, respectively.

Finally, exergetic efficiency is found using:

\[ \eta_{exergetic} = 1 − \frac{\dot{X}_{destruction}}{\dot{X}_{in}} \]

This formula helps to show the real efficiency when considering second law aspects, giving a clearer picture of how effectively the turbine converts available energy into work. It's a more stringent measure compared to simple isentropic efficiency as it evaluates how close the operation is to ideal, reversible processes.

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Most popular questions from this chapter

Carbon monoxide \((\mathrm{CO})\) enters an insulated compressor operating at steady state at 10 bar, \(227^{\circ} \mathrm{C}\), and a mass flow rate of \(0.1 \mathrm{~kg} / \mathrm{s}\) and exits at 15 bar, \(327^{\circ} \mathrm{C}\). Determine the power required by the compressor and the rate of exergy destruction, each in \(\mathrm{kW}\). Ignore the effects of motion and gravity. Let \(T_{0}=17^{\circ} \mathrm{C}, p_{0}=1\) bar.

Three pounds of carbon monoxide initially at \(180^{\circ} \mathrm{F}\) and \(40 \mathrm{lbf}\) in. \({ }^{2}\) undergo two processes in series: Process 1-2: Constant pressure to \(T_{2}=-10^{\circ} \mathrm{F}\) Process 2-3: Isothermal to \(p_{3}=10 \frac{\mathrm{lbf}}{\mathrm{in}^{2}}\) Employing the ideal gas model (a) represent each process on a \(p-v\) diagram and indicate the dead state. (b) determine the change in exergy for each process, in Btu. Let \(T_{0}=77^{\circ} \mathrm{F}, p_{0}=14.7 \mathrm{lbf} / \mathrm{in}^{2}\) and ignore the effects of motion and gravity.

Argon enters a nozzle operating at steady state at \(1300 \mathrm{~K}\), \(360 \mathrm{kPa}\) with a velocity of \(10 \mathrm{~m} / \mathrm{s}\) and exits the nozzle at \(900 \mathrm{~K}, 130 \mathrm{kPa}\). Stray heat transfer can be ignored. Modeling argon as an ideal gas with \(k=1.67\), determine (a) the velocity at the exit, in \(\mathrm{m} / \mathrm{s}\), and (b) the rate of exergy destruction, in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of argon flowing. Let \(T_{0}=293 \mathrm{~K}, p_{0}=1\) bar.

Water vapor enters a valve with a mass flow rate of \(2 \mathrm{~kg} / \mathrm{s}\) at a temperature of \(320^{\circ} \mathrm{C}\) and a pressure of 60 bar and undergoes a throttling process to 40 bar. (a) Determine the flow exergy rates at the valve inlet and exit and the rate of exergy destruction, each in \(\mathrm{kW}\). (b) Evaluating exergy at \(8.5\) cents per \(\mathrm{kW} \cdot \mathrm{h}\), determine the annual cost, in \(\$ /\) year, associated with the exergy destruction, assuming 8400 hours of operation annually. Let \(T_{0}=25^{\circ} \mathrm{C}, p_{0}=1\) bar.

Four kilograms of a two-phase liquid-vapor mixture of water initially at \(300^{\circ} \mathrm{C}\) and \(x_{1}=0.5\) undergo the two different processes described below. In each case, the mixture is brought from the initial state to a saturated vapor state, while the volume remains constant. For each process, determine the change in exergy of the water, the net amounts of exergy transfer by work and heat, and the amount of exergy destruction, each in kJ. Let \(T_{0}=300 \mathrm{~K}, p_{0}=1\) bar, and ignore the effects of motion and gravity. Comment on the difference between the exergy destruction values. (a) The process is brought about adiabatically by stirring the mixture with a paddle wheel. (b) The process is brought about by heat transfer from a thermal reservoir at \(610 \mathrm{~K}\). The temperature of the water at the location where the heat transfer occurs is \(610 \mathrm{~K}\).

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