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Argon enters a nozzle operating at steady state at \(1300 \mathrm{~K}\), \(360 \mathrm{kPa}\) with a velocity of \(10 \mathrm{~m} / \mathrm{s}\) and exits the nozzle at \(900 \mathrm{~K}, 130 \mathrm{kPa}\). Stray heat transfer can be ignored. Modeling argon as an ideal gas with \(k=1.67\), determine (a) the velocity at the exit, in \(\mathrm{m} / \mathrm{s}\), and (b) the rate of exergy destruction, in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of argon flowing. Let \(T_{0}=293 \mathrm{~K}, p_{0}=1\) bar.

Short Answer

Expert verified
The exit velocity is approximately 646.93 m/s and the rate of exergy destruction is approximately -39.704 kJ/kg.

Step by step solution

01

Identify given values and assumptions

Assign the given parameters: Inlet conditions: \(T_1 = 1300 \text{ K}\), \(P_1 = 360 \text{ kPa}\), \(v_1 = 10 \text{ m/s}\). Outlet conditions: \(T_2 = 900 \text{ K}\), \(P_2 = 130 \text{ kPa}\). Assume Argon is an ideal gas with specific heat ratio \(k = 1.67\). Also assume no heat transfer and steady state operation.
02

Apply the steady-flow energy equation

Use the steady-flow energy equation: \[\frac{V_1^2}{2} + c_{p}T_1 = \frac{V_2^2}{2} + c_{p}T_2\], where \(c_{p}\) is the specific heat at constant pressure. For an ideal gas, \[c_{p} = \frac{kR}{k-1}\]. Find \(R\) for Argon: \(R = \frac{8314}{40} \text{ J/kg·K} \approx 208.85 \text{ J/kg·K} \).Substitute \(R\) and \(k\) into the equation to get \(c_{p}\).
03

Calculate the specific heat \(c_p\)

Given \(k = 1.67\), \[c_{p} = \frac{1.67 \times 208.85}{(1.67-1)} \text{ J/kg·K} \approx 522.87 \text{ J/kg·K} \].
04

Substitute values and solve for exit velocity

Substitute values into the energy equation: \[\frac{10^2}{2} + 522.87 \times 1300 = \frac{V_2^2}{2} + 522.87 \times 900\]. Rearrange and solve for \(V_2\): \[50 + 679731 = \frac{V_2^2}{2} + 470583\]. So, \[209198 = \frac{V_2^2}{2}\]. Thus, \[V_2 = \frac{2 \times 209198}{208}\] Therefore, \(V_2\approx 646.93 \text{ m/s} \).
05

Calculate the rate of exergy destruction

From the definition of exergy destruction rate for an ideal gas: \[ \text{Rate of Exergy Destruction} = T_0 \times \text{Entropy Change} \]. First find the entropy change: \[ \frac{\text{d}S}{\text{mass}} = \frac{c_p \times \text{ln}(\frac{T_2}{T_1})} - R \times \text{ln}(\frac{P_2}{P_1}) \]. Substituting values, \[ \frac{\text{d}S}{\text{mass}} = 522.87 \times \text{ln}(\frac{900}{1300}) - 208.85 \times \text{ln}(\frac{130}{360}) \]. After calculations, the entropy change \( \text{d}S \text{ per mass} \approx -135.54 \text{ J/kg·K} \). Finally, \[ \text{Exergy Destruction Rate} = 293 \times -135.54 / 1000 \]. Therefore, \( \text{Exergy Destruction Rate} \approx -39.704 \text{ kJ/kg} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law relates the pressure, volume, and temperature of an ideal gas. It's given by: \[ PV = nRT \] where:
  • P is the pressure of the gas
  • V is the volume of the gas
  • n is the number of moles
  • R is the gas constant, which is 8.314 J/(mol·K) for all ideal gases
  • T is the absolute temperature in Kelvins
In the context of the given exercise, argon is treated as an ideal gas. This assumption allows us to use the Ideal Gas Law to connect various thermodynamic properties. Specifically, the Ideal Gas Law helps us determine specific heat and other properties that are essential when analyzing steady-flow processes in nozzles.
Nozzle Flow
Nozzles are devices designed to control the direction and characteristics of fluid flow. In many applications, such as jet engines and turbines, understanding nozzle flow is critical. The objective is to study how the velocity, pressure, and temperature of the fluid change as it moves through the nozzle.In the given problem, argon enters and exits the nozzle under steady-state conditions. This means the properties of the gas (like temperature and pressure) are constant over time at points of entry and exit. The steady-flow energy equation is crucial here, and it states: \[ \frac{V_1^2}{2} + c_p T_1 = \frac{V_2^2}{2} + c_p T_2 \] This equation illustrates the conservation of energy for a fluid particle as it moves through the nozzle. By using this equation, we can solve for various properties, such as the exit velocity, given the inlet conditions.
Entropy Change
Entropy is a measure of disorder within a system. When dealing with thermodynamic processes, particularly in a nozzle, assessing the change in entropy is essential. The entropy change for an ideal gas during a process can be determined using: \[ \Delta S = c_p \ln \left( \frac{T_2}{T_1} \right) - R \ln \left( \frac{P_2}{P_1} \right) \] where
  • c_p is the specific heat at constant pressure
  • R is the gas constant
  • T_1 and T_2 are the initial and final temperatures respectively
  • P_1 and P_2 are the initial and final pressures respectively
In the provided exercise, calculating the entropy change helps us determine the exergy destruction, which provides insight into the efficiency of the nozzle's performance. Exergy destruction represents the lost work potential due to irreversibilities in the process.
Specific Heat at Constant Pressure
Specific heat at constant pressure, denoted as \( c_p \), is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Kelvin, at constant pressure. For an ideal gas, it's related to the gas constant and the specific heat ratio \( k \) by: \[ c_p = \frac{k R}{k - 1} \] In our problem, since argon is modeled as an ideal gas, knowing \( k \) (the specific heat ratio) lets us calculate \( c_p \). For argon, given \( k = 1.67 \), we can use the specific gas constant for argon \( R = 208.85 \text{ J/kg}·\text{K} \) to find that: \[ c_p = \frac{1.67 \times 208.85}{1.67 - 1} \approx 522.87 \text{ J/kg}·\text{K} \] Understanding \( c_p \) is essential when applying the steady-flow energy equation to solve for temperatures and velocities at different points in the nozzle.

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Most popular questions from this chapter

One-half pound of air is contained in a closed, rigid, insulated tank. Initially the temperature is \(520^{\circ} \mathrm{R}\) and the pressure is \(14.7\) psia. The air is stirred by a paddle wheel until its temperature is \(600^{\circ} \mathrm{R}\). Using the ideal gas model, determine for the air the change in exergy, the transfer of exergy accompanying work, and the exergy destruction, all in Btu. Ignore the effects of motion and gravity and let \(T_{0}=537^{\circ} \mathrm{R}, p_{0}=14.7\) psia.

Water vapor enters a valve with a mass flow rate of \(2 \mathrm{~kg} / \mathrm{s}\) at a temperature of \(320^{\circ} \mathrm{C}\) and a pressure of 60 bar and undergoes a throttling process to 40 bar. (a) Determine the flow exergy rates at the valve inlet and exit and the rate of exergy destruction, each in \(\mathrm{kW}\). (b) Evaluating exergy at \(8.5\) cents per \(\mathrm{kW} \cdot \mathrm{h}\), determine the annual cost, in \(\$ /\) year, associated with the exergy destruction, assuming 8400 hours of operation annually. Let \(T_{0}=25^{\circ} \mathrm{C}, p_{0}=1\) bar.

One lbmol of carbon monoxide gas is contained in a \(90-\mathrm{ft}^{3}\) rigid, insulated vessel initially at 5 atm. An electric resistor of negligible mass transfers energy to the gas at a constant rate of \(10 \mathrm{Btu} / \mathrm{s}\) for \(2 \mathrm{~min}\). Employing the ideal gas model and ignoring the effects of motion and gravity, determine (a) the change in exergy of the gas, (b) the electrical work, and (c) the exergy destruction, each in Btu. Let \(T_{0}=70^{\circ} \mathrm{F}\), \(p_{0}=1 \mathrm{~atm}\).

Refrigerant \(134 a\) enters a counterflow heat exchanger operating at steady state at \(-32^{\circ} \mathrm{C}\) and a quality of \(40 \%\) and exits as saturated vapor at \(-32^{\circ} \mathrm{C}\). Air enters as a separate sticam with a unass fluw 1 ate of \(5 \mathrm{~kg} / \mathrm{s}\) and is couleal al a constant pressure of 1 bar from 300 to \(250 \mathrm{~K}\). Heat transfer between the heat exchanger and its surroundings can be ignored, as can the effects of motion and gravity. (a) As in Fig. E7.6, sketch the variation with position of the temperature of each stream. Locate \(T_{0}\) on the sketch. (b) Determine the rate of exergy destruction within the heat exchanger, in \(\mathrm{kW}\). (c) Devise and evaluate an exergetic efficiency for the heat exchanger. Let \(T_{0}=300 \mathrm{~K}, p_{0}=1\) bar.

A high-pressure (HP) boiler and a low-pressure (LP) boiler will be added to a plant's steam-generating system. Both boilers use the same fuel and at steady state have approximately the same rate of energy loss by heat transfer. The average temperature of the combustion gases is less in the LP boiler than in the HP boiler. In comparison to the LP boiler, might you spend more, the same, or less to insulate the HP boiler? Explain.

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