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A power cycle receives 1000 Btu by heat transfer from a reservoir at \(1000^{\circ} \mathrm{F}\) and discharges energy by heat transfer to a reservoir at \(300^{\circ} \mathrm{F}\). The thermal efficiency of the cycle is \(75 \%\) of that for a reversible power cycle operating between the same reservoirs, (a) For the actual cycle, determine the thermal efficiency and the energy discharged to the cold reservoir, in Btu. (b) Repeat for the reversible power cycle.

Short Answer

Expert verified
The actual cycle efficiency is 35.96%, with 640.38 Btu discharged. The reversible cycle efficiency is 47.95%, with 520.5 Btu discharged.

Step by step solution

01

Determine the Reversible Cycle Efficiency

First, find the thermal efficiency of a reversible (Carnot) cycle operating between the two reservoirs. The thermal efficiency of a Carnot cycle is given by:\[ \eta_{rev} = 1 - \frac{T_C}{T_H} \]where \( T_H \) and \(T_C\) are the absolute temperatures of the hot and cold reservoirs, respectively. Convert the temperatures from degrees Fahrenheit to Rankine by adding 460: \[ T_H = 1000^{\circ} F + 460 = 1460^{\circ} R \] \[ T_C = 300^{\circ} F + 460 = 760^{\circ} R \]Substitute these values into the Carnot efficiency formula: \[ \eta_{rev} = 1 - \frac{760}{1460} \]
02

Calculate Reversible Cycle Efficiency

Perform the calculation to find the reversible cycle efficiency: \[ \eta_{rev} = 1 - \frac{760}{1460} = 1 - 0.5205 = 0.4795 \]So, the thermal efficiency of the reversible cycle is 47.95%.
03

Determine Actual Cycle Efficiency

Given that the thermal efficiency of the actual cycle is 75% of the reversible cycle efficiency, calculate the actual cycle efficiency: \[ \eta_{actual} = 0.75 \times \eta_{rev} = 0.75 \times 0.4795 = 0.359625 \]So, the thermal efficiency of the actual cycle is 35.96%.
04

Calculate Energy Discharged for Actual Cycle

For the actual cycle, the thermal efficiency is given by: \[ \eta_{actual} = \frac{W_{cycle}}{Q_{in}} \]where \( Q_{in} = 1000 \ Btu \) and we'll find \( W_{cycle} \) first: \[ W_{cycle} = \eta_{actual} \times Q_{in} = 0.359625 \times 1000 = 359.625 \ Btu \]The energy discharged to the cold reservoir \( Q_{out} \) is given by: \[ Q_{out} = Q_{in} - W_{cycle} = 1000 - 359.625 = 640.375 \ Btu \]
05

Reversible Cycle Energy Discharged

For the reversible cycle, use the reversible cycle efficiency to find \( W_{cycle, rev} \): \[ W_{cycle, rev} = \eta_{rev} \times Q_{in} = 0.4795 \times 1000 = 479.5 \ Btu \]Similarly, calculate the energy discharged to the cold reservoir for the reversible cycle: \[ Q_{out, rev} = Q_{in} - W_{cycle, rev} = 1000 - 479.5 = 520.5 \ Btu \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

thermal efficiency
Thermal efficiency is a measure of how well a power cycle converts the energy it receives into useful work. It is defined as the ratio of the work output of the cycle \(W_{cycle}\) to the heat input \(Q_{in}\). In mathematical terms, this is expressed as: \[ \eta = \frac{W_{cycle}}{Q_{in}} \] Thermal efficiency is a crucial concept in thermodynamics because it reflects the performance of the power cycle. A higher efficiency means that a larger portion of the energy is converted into work.
However, no real power cycle can achieve 100% thermal efficiency due to inherent losses such as friction, heat loss, and irreversibilities in the cycle. In practice, engineers strive to design systems that approach the theoretical maximum efficiency for better energy utilization and cost-effectiveness.
Carnot cycle
The Carnot cycle is a theoretical thermodynamic cycle that provides the maximum possible efficiency for a power cycle operating between two temperatures. It serves as an ideal benchmark against which the performance of real power cycles can be measured. The Carnot cycle efficiency is given by the following equation: \[ \eta_{rev} = 1 - \frac{T_C}{T_H} \] where \( T_H \) and \( T_C \) are the absolute temperatures of the hot and cold reservoirs, respectively.
The temperatures must be converted to an absolute scale, such as Rankine (\(^\circ R\)) or Kelvin (K), for this equation to be valid. This efficiency is the upper limit a real power cycle can theoretically achieve, making it impossible for any system to operate with an efficiency higher than a Carnot cycle between the same reservoirs.
While the Carnot cycle is an idealization, it is invaluable in understanding the upper limits of efficiency and guiding the development of more efficient real-world systems.
energy transfer
Energy transfer in a power cycle involves the movement of energy in the form of heat and work between the system and its surroundings. In a typical power cycle, energy is transferred as heat from a high-temperature reservoir to the cycle and then from the cycle to a low-temperature reservoir. The energy transferred as heat to the cycle \(Q_{in}\) is partly converted into work \(W_{cycle}\) by the cycle. The remaining energy is transferred as heat to a low-temperature reservoir \(Q_{out}\).
This can be summarized by the equation: \[ Q_{in} = W_{cycle} + Q_{out} \] The first law of thermodynamics, which is essentially an energy balance, governs these energy transfers. Realizing efficient energy transfer is essential for optimizing the performance of power cycles and achieving higher thermal efficiencies.
Efficient energy transfer minimizes losses and ensures that a greater proportion of the input energy is converted to useful work, making the system more effective and economical.

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Most popular questions from this chapter

A quantity of water within a piston-cylinder assembly executes a Carnot power cycle. During isothermal expansion, the water is heated from saturated liquid at 50 bar until it is a saturated vapor. The vapor then expands adiabatically to a pressure of 5 bar while doing \(364.31 \mathrm{~kJ} / \mathrm{kg}\) of work. (a) Sketch the cycle on \(p\)-v coordinates. (b) Evaluate the heat transfer per unit mass and work per unit mass for each process, in \(\mathrm{kJ} / \mathrm{kg}\). (c) Evaluate the thermal efficiency. \(5.82\) One and one-half pounds of water within a piston-cylinder assembly execute a Carnot power cycle. During isothermal expansion, the water is heated at \(500^{\circ} \mathrm{F}\) from saturated liquid to saturated vapor. The vapor then expands adiabatically to a temperature of \(100^{\circ} \mathrm{F}\) and a quality of \(70.38 \%\). (a) Sketch the cycle on \(p-v\) coordinates. (b) Evaluate the heat transfer and work for each process, in Btu. (c) Evaluate the thermal efficiency.

A heating system must maintain the interior of a building at \(T_{\mathrm{H}}=20^{\circ} \mathrm{C}\) when the outside temperature is \(T_{\mathrm{C}}=2^{\circ} \mathrm{C}\). If the rate of heat transfer from the building through its walls and roof is \(16.4 \mathrm{~kW}\), determine the electrical power required, in \(\mathrm{kW}\), to heat the building using (a) electrical-resistance heating, (b) a heat pump whose coefficient of performance is \(3.0\), (c) a reversible heat pump operating between hot and cold reservoirs at \(20^{\circ} \mathrm{C}\) and \(2^{\circ} \mathrm{C}\), respectively.

A gas within a piston-cylinder assembly executes a Carnot power cycle during which the isothermal expansion occurs at \(T_{\mathrm{H}}=600 \mathrm{~K}\) and the isothermal compression occurs at \(T_{\mathrm{C}}=300 \mathrm{~K}\). Determine (a) the thermal efficiency. (b) the percent change in thermal efficiency if \(T_{\mathrm{H}}\) increases by \(15 \%\) while \(T_{\mathrm{C}}\) remains the same. (c) the percent change in thermal efficiency if \(T_{\mathrm{C}}\) decreases by \(15 \%\) while \(T_{\mathrm{H}}\) remains the same. (d) the percent change in thermal efficiency if \(T_{\mathrm{H}}\) increases by \(15 \%\) and \(T_{\mathrm{C}}\) decreases by \(15 \%\).

A power cycle receives energy \(Q_{\mathrm{H}}\) by heat transfer from a hot reservoir at \(T_{\mathrm{H}}=1200^{\circ} \mathrm{R}\) and rejects energy \(Q_{\mathrm{C}}\) by heat transfer to a cold reservoir at \(T_{\mathrm{C}}=400^{\circ} \mathrm{R}\). For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) \(Q_{\mathrm{H}}=900 \mathrm{Btu}, W_{\text {cycle }}=450 \mathrm{Btu}\) (b) \(Q_{\mathrm{H}}=900 \mathrm{Btu}, Q_{\mathrm{C}}=300 \mathrm{Btu}\) (c) \(W_{\text {cycle }}=600 \mathrm{Btu}, Q_{\mathrm{c}}=400 \mathrm{Btu}\) (d) \(\eta=70 \%\)

By removing energy by heat transfer from a room, a window air conditioner maintains the room at \(22^{\circ} \mathrm{C}\) on a day when the outside temperature is \(32^{\circ} \mathrm{C}\). (a) Determine, in \(\mathrm{kW}\) per \(\mathrm{kW}\) of cooling, the minimum theoretical power required by the air conditioner. (b) To achieve required rates of heat transfer with practicalsized units, air conditioners typically receive energy by heat transfer at a temperature below that of the room being cooled and discharge energy by heat transfer at a temperature above that of the surroundings. Consider the effect of this by determining the minimum theoretical power, in \(\mathrm{kW}\) per \(\mathrm{kW}\) of cooling, required when \(T_{\mathrm{C}}=18^{\circ} \mathrm{C}\) and \(T_{\mathrm{H}}=36^{\circ} \mathrm{C}\), and compare with the value found in part (a).

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