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A power cycle receives energy \(Q_{\mathrm{H}}\) by heat transfer from a hot reservoir at \(T_{\mathrm{H}}=1200^{\circ} \mathrm{R}\) and rejects energy \(Q_{\mathrm{C}}\) by heat transfer to a cold reservoir at \(T_{\mathrm{C}}=400^{\circ} \mathrm{R}\). For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) \(Q_{\mathrm{H}}=900 \mathrm{Btu}, W_{\text {cycle }}=450 \mathrm{Btu}\) (b) \(Q_{\mathrm{H}}=900 \mathrm{Btu}, Q_{\mathrm{C}}=300 \mathrm{Btu}\) (c) \(W_{\text {cycle }}=600 \mathrm{Btu}, Q_{\mathrm{c}}=400 \mathrm{Btu}\) (d) \(\eta=70 \%\)

Short Answer

Expert verified
(a) Irreversibly (b) Reversibly (c) Irreversibly (d) Impossible

Step by step solution

01

Define the efficiency formula

The efficiency of a heat engine is given by \[\eta = \frac{W_{cycle}}{Q_{H}}\]where \(W_{cycle}\) is the work done by the cycle and \(Q_{H}\) is the heat absorbed from the hot reservoir.
02

Define the reversible efficiency

The efficiency of a reversible (ideal) Carnot cycle is given by \[\eta_{rev} = 1 - \frac{T_C}{T_H}\]Thus, for \(T_H = 1200^{\circ} R\) and \(T_C = 400^{\circ} R\), \[\eta_{rev} = 1 - \frac{400}{1200} = 1 - \frac{1}{3} = \frac{2}{3} = 66.67\%\].
03

Case (a) - Calculate the efficiency

Given: \(Q_H = 900\, \mathrm{Btu}\) and \(W_{cycle} = 450\, \mathrm{Btu}\)Calculate the efficiency: \[\eta = \frac{450}{900} = 0.5 = 50\%\]Since 50% < 66.67%, the cycle operates irreversibly.
04

Case (b) - Calculate the work done

Given: \(Q_H = 900\, \mathrm{Btu}\) and \(Q_C = 300\, \mathrm{Btu}\)Calculate the work done: \[W_{cycle} = Q_H - Q_C = 900 - 300 = 600\, \mathrm{Btu}\]Calculate the efficiency: \[\eta = \frac{600}{900} = \frac{2}{3} = 66.67\%\]Since 66.67% equals the reversible efficiency, the cycle operates reversibly.
05

Case (c) - Calculate the heat absorbed

Given: \(W_{cycle} = 600\, \mathrm{Btu}\) and \(Q_C = 400\, \mathrm{Btu}\)Calculate the heat absorbed: \[Q_H = W_{cycle} + Q_C = 600 + 400 = 1000\, \mathrm{Btu}\] Calculate the efficiency: \[\eta = \frac{600}{1000} = 0.6 = 60\%\]Since 60% < 66.67%, the cycle operates irreversibly.
06

Case (d) - Compare given efficiency

Given: \(\eta = 70\%\)Since 70% > 66.67%, the cycle is impossible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carnot Cycle
The Carnot Cycle is a theoretical thermodynamic cycle proposed by French scientist Sadi Carnot. It represents an idealized heat engine that operates on a reversible cycle and is known for having the maximum possible efficiency. The cycle consists of four processes: two isothermal (constant temperature) processes and two adiabatic (no heat transfer) processes. It's an important concept because it sets the upper limit on the efficiency that any real heat engine can achieve. When solving thermodynamics problems, comparing a given cycle's efficiency to the Carnot efficiency helps in determining whether the cycle operates reversibly, irreversibly, or is impossible.
Heat Transfer
Heat transfer is the process by which heat energy is exchanged between a hot reservoir and a cold reservoir in any thermodynamic cycle. It is a fundamental concept when studying how engines and refrigerators work. In the context of thermodynamic cycles, you will encounter terms like \(Q_H\) and \(Q_C\).
\(Q_H\) is the heat energy received from the hot reservoir, while \(Q_C\) is the heat energy rejected to the cold reservoir. Heat transfer is crucial in determining the cycle's work output and efficiency. Always remember: the first law of thermodynamics states that the energy added to the system as heat minus the work done by the system is equal to the change in internal energy of the system.
Efficiency Calculation
Efficiency calculation is essential to understanding how well a heat engine converts heat into work. The formula for efficiency (\( \eta \)) is:
\[ \eta = \frac{W_{cycle}}{Q_{H}} \]
where \(W_{cycle}\) is the work done by the cycle and \(Q_H\) is the heat absorbed from the hot reservoir. For an ideal Carnot cycle, the efficiency is determined by the temperatures of the hot and cold reservoirs:
\[ \eta_{rev} = 1 - \frac{T_C}{T_H} \]
Given \(T_H = 1200^{\circ} R \) and \(T_C = 400^{\circ} R \), the equation becomes:
\[ \eta_{rev} = 1 - \frac{400}{1200} = \frac{2}{3} = 66.67\% \]
By comparing the actual efficiency of a given cycle to the Carnot efficiency, we can determine if the cycle is reversible, irreversible, or impossible.
Power Cycles
Power cycles are essential in engineering because they describe how engines convert heat energy into mechanical energy. Various power cycles exist, but the Carnot cycle is especially significant due to its theoretical maximum efficiency. Key power cycles include:
  • Carnot Cycle: The ideal cycle with maximum efficiency.
  • Rankine Cycle: Commonly used in power plants and is a practical cycle with high efficiency.
  • Otto Cycle: Describes the functioning of gasoline internal combustion engines.
  • Diesel Cycle: Represents the operation of diesel engines.
Each cycle has its unique characteristics and applications, but all follow the fundamental thermodynamic principles of heat transfer, work, and efficiency. Understanding these cycles helps in designing and improving engines and other devices that convert heat into useful work.

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Most popular questions from this chapter

A quantity of water within a piston-cylinder assembly executes a Carnot power cycle. During isothermal expansion, the water is heated from saturated liquid at 50 bar until it is a saturated vapor. The vapor then expands adiabatically to a pressure of 5 bar while doing \(364.31 \mathrm{~kJ} / \mathrm{kg}\) of work. (a) Sketch the cycle on \(p\)-v coordinates. (b) Evaluate the heat transfer per unit mass and work per unit mass for each process, in \(\mathrm{kJ} / \mathrm{kg}\). (c) Evaluate the thermal efficiency. \(5.82\) One and one-half pounds of water within a piston-cylinder assembly execute a Carnot power cycle. During isothermal expansion, the water is heated at \(500^{\circ} \mathrm{F}\) from saturated liquid to saturated vapor. The vapor then expands adiabatically to a temperature of \(100^{\circ} \mathrm{F}\) and a quality of \(70.38 \%\). (a) Sketch the cycle on \(p-v\) coordinates. (b) Evaluate the heat transfer and work for each process, in Btu. (c) Evaluate the thermal efficiency.

A heating system must maintain the interior of a building at \(T_{\mathrm{H}}=20^{\circ} \mathrm{C}\) when the outside temperature is \(T_{\mathrm{C}}=2^{\circ} \mathrm{C}\). If the rate of heat transfer from the building through its walls and roof is \(16.4 \mathrm{~kW}\), determine the electrical power required, in \(\mathrm{kW}\), to heat the building using (a) electrical-resistance heating, (b) a heat pump whose coefficient of performance is \(3.0\), (c) a reversible heat pump operating between hot and cold reservoirs at \(20^{\circ} \mathrm{C}\) and \(2^{\circ} \mathrm{C}\), respectively.

A power cycle operates between a lake's surface water at a temperature of \(300 \mathrm{~K}\) and water at a depth whose temperature is \(285 \mathrm{~K}\). At steady state the cycle develops a power output of \(10 \mathrm{~kW}\), while rejecting energy by heat transfer to the lower-temperature water at the rate \(14,400 \mathrm{~kJ} / \mathrm{min}\). Determine (a) the thermal efficiency of the power cycle and (b) the maximum thermal efficiency for any such power cycle.

The data listed below are claimed for a power cycle operating between hot and cold reservoirs at \(1500 \mathrm{~K}\) and \(450 \mathrm{~K}\), respectively. For each case, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) \(Q_{\mathrm{H}}=600 \mathrm{~kJ}, W_{\text {cycle }}=300 \mathrm{~kJ}, Q_{\mathrm{C}}=300 \mathrm{~kJ}\) (b) \(Q_{\mathrm{H}}=400 \mathrm{~kJ}, W_{\text {cycle }}=280 \mathrm{~kJ}, Q_{\mathrm{C}}=120 \mathrm{~kJ}\) (c) \(Q_{\mathrm{H}}=700 \mathrm{~kJ}, W_{\text {cyck }}=300 \mathrm{~kJ}, Q_{\mathrm{C}}=500 \mathrm{~kJ}\) (d) \(Q_{\mathrm{H}}=800 \mathrm{~kJ}, W_{\text {cycle }}=600 \mathrm{~kJ}, Q_{\mathrm{C}}=200 \mathrm{~kJ}\)

The thermal efficiency of a reversible power cycle operating between hot and cold reservoirs is \(20 \%\). Evaluate the coefficient of performance of (a) a reversible refrigeration cycle operating between the same two reservoirs. (b) a reversible heat pump cycle operating between the same two reservoirs.

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