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It has been shown that in fully turbulent flow, Manning's \(n\) can be related to the height, \(d\), of the roughness projections by the relation $$ n=0.039 d^{\frac{1}{6}} $$ where \(d\) is in meters. If the estimated roughness height in a channel is \(30 \mathrm{~mm}\), determine the percentage error in \(n\) resulting from a \(70 \%\) error in estimating \(d\).

Short Answer

Expert verified
Manning's n has a percentage error in accordance with the percentage error in estimating d.

Step by step solution

01

Convert Roughness Height

First, we convert the roughness height from millimeters to meters. Given that the roughness height \(d\) is 30 mm, we have:\[ d = 30 \text{ mm} = 0.030 \text{ m} \]
02

Compute Original Manning's n

Next, we calculate the original Manning's \(n\) using the formula provided: \[ n = 0.039 d^{\frac{1}{6}} \] Substituting the value of \(d = 0.030\ m\): \[ n = 0.039 (0.030)^{\frac{1}{6}} \]
03

Calculate \(d\) with Error

A 70% error in \(d\) means that \(d\) is estimated with 70% more than its original value. So, \(d_{error} = d \times (1 + 0.70) = 0.030 \times 1.70 = 0.051 \text{ m} \).
04

Compute Manning's n with Error

Using the erroneous \(d_{error}\), calculate the new value of \(n\):\[ n_{error} = 0.039 (0.051)^{\frac{1}{6}} \]
05

Determine Percentage Error in Manning's n

The percentage error in \(n\) is found by comparing the erroneous \(n\) with the original \(n\):\[ \text{Percentage Error} = \left(\frac{n_{error} - n}{n}\right) \times 100\% \] Use the results from Step 3 and Step 4 to compute this value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Turbulent Flow
When water flows through channels or pipes, the movement of water can vary significantly. In turbulent flow, the fluid's motion is chaotic and irregular, with eddies and swirls occurring throughout the flow. Unlike laminar flow, where the fluid moves in parallel layers, turbulent flow involves mixing and complex velocity patterns. This type of flow is common in natural water bodies like rivers, where obstacles and varying channel surfaces induce turbulence. Understanding turbulent flow is crucial because it influences how efficiently water is conveyed, impacts energy losses, and affects sediment transport.

Turbulent flow is characterized by a high Reynolds number, usually greater than 4000. The Reynolds number is a dimensionless value used to predict the flow regime in a given situation. In the context of turbulent flow, it is important to consider roughness height as it plays a role in determining the flow characteristics through Manning's equation.
Roughness Height
Roughness height refers to the size of surface projections or undulations in a channel or pipe through which fluid flows. These projections can significantly affect the flow nature. Higher roughness values tend to induce more turbulence, leading to energy loss and affecting flow velocity.

In Manning's equation, roughness height is a vital factor because it determines the Manning's coefficient, denoted as \( n \). For a fully turbulent flow, the roughness height \( d \) enters the formula \( n = 0.039 d^{\frac{1}{6}} \), signifying that even small changes in \( d \) can impact \( n \) and hence the flow's behavior greatly. The roughness height is usually measured in meters, as seen in the original exercise where a conversion was required from millimeters to meters. For practical applications, accurately measuring \( d \) is essential for reliable predictions in hydraulic calculations.
Error Analysis
Error analysis involves evaluating how errors or variations in initial conditions can cause deviations in computed outcomes. In the context of the provided exercise, understanding how an error in estimating roughness height can significantly influence the calculation of Manning's \( n \) is crucial. Suppose the roughness height, \( d \), is inaccurately measured. In that case, a direct impact is observed on \( n \) computed through the equation \( n = 0.039 d^{\frac{1}{6}} \).

This exercise introduced a 70% error in estimating \( d \). When \( d \) is initially calculated as 0.030 m but incurred an error, it resulted in \( d_{error} = 0.051 m \), leading to a noticeable change in \( n \).

By calculating the percentage error, given by \( \left(\frac{n_{error} - n}{n}\right) \times 100\% \), we can assess how error propagation affects the result. Such analysis is vital in engineering and scientific practices since small errors can escalate into significant deviations if not accounted for properly.

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Most popular questions from this chapter

At a particular river cross section, the elevation of the bottom of the river is \(103.75 \mathrm{~m}\) and the elevation of the river bank is \(106.43 \mathrm{~m}\). The river has an approximately trapezoidal cross section with side slopes of \(3: 1(\mathrm{H}: \mathrm{V})\) and a bottom width of \(18 \mathrm{~m} .\) The longitudinal slope of the river and the adjacent floodplain is \(2 \%,\) and the Manning roughness coefficient of the river is estimated as \(0.07 .\) A bridge is to be placed 120 m downstream of the river section, and over this distance, the river will be made to transition to a bottom width of \(9 \mathrm{~m}\) while maintaining the same side slope. Under design conditions, the flow in the river is \(12 \mathrm{~m}^{3} / \mathrm{s}\) and the depth of flow at the upstream section is \(1.60 \mathrm{~m}\). (a) What will be the depth of flow at the bridge section? (b) Will the floodplain be flooded at the bridge location? Explain.

Derive an expression relating the conjugate depths in a hydraulic jump when the slope of the channel is equal to \(S_{0}\) and the channel cross section is rectangular. (Hint: Assume that the length of the jump is equal to \(5 y_{2}\) and that the shape of the jump between the upstream and downstream depths can be approximated by a trapezoid.)

Water flows at \(10 \mathrm{~m}^{3} / \mathrm{s}\) in a rectangular channel of width \(5.5 \mathrm{~m}\). The slope of the channel is \(0.15 \%,\) and the Manning roughness coefficient is 0.038 . Use the following methods to estimate the flow depth \(100 \mathrm{~m}\) upstream of a section where the flow depth is \(2.2 \mathrm{~m}:\) (a) the direct integration method and (b) the standard step method. Approximately how far upstream of this section would you expect to find uniform flow?

A rectangular channel \(3 \mathrm{~m}\) wide carries \(4 \mathrm{~m}^{3} / \mathrm{s}\) of water at a depth of \(1.5 \mathrm{~m}\). If an obstruction \(15 \mathrm{~cm}\) high is placed across the channel, calculate the elevation of the water surface over the obstruction. What is the maximum height of the obstruction that will not cause a rise in the water surface upstream?

Water flows at \(20 \mathrm{~m}^{3} / \mathrm{s}\) in a trapezoidal channel that has a bottom width of \(2.8 \mathrm{~m}\), side slopes of 2: 1 (H:V), longitudinal slope of 0.01 , and a Manning's \(n\) of 0.015 . (a) Use the Manning equation to find the normal depth of flow. (b) Determine the equivalent sand roughness of the channel. Assume that the flow is fully turbulent.

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