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Derive an expression relating the conjugate depths in a hydraulic jump when the slope of the channel is equal to \(S_{0}\) and the channel cross section is rectangular. (Hint: Assume that the length of the jump is equal to \(5 y_{2}\) and that the shape of the jump between the upstream and downstream depths can be approximated by a trapezoid.)

Short Answer

Expert verified
The expression for conjugate depths in a hydraulic jump in a rectangular channel is given by \( y_2 = \frac{2y_1}{\sqrt{1 + 8F_1^2} - 1} \), where \( F_1 \) is the Froude number.

Step by step solution

01

Understand the Properties of a Hydraulic Jump

A hydraulic jump is a phenomenon in fluid dynamics where the fluid transitions from a high velocity, low depth flow (supercritical) to a low velocity, high depth flow (subcritical). In a rectangular channel, if the upstream depth is denoted as \( y_1 \) and the downstream depth as \( y_2 \), these are referred to as conjugate depths.
02

Apply the Momentum Equation

In a hydraulic jump, the conservation of momentum applies between the upstream and downstream sections. The momentum function for rectangular channels is given by \( M = Q^2/gA + Ay \), where: \( Q \) is the flow rate, \( g \) is the gravitational acceleration, \( A \) is the cross-sectional area, and \( y \) is the depth. Equating momentum upstream and downstream, we have: \[ \frac{Q^2}{gA_1} + y_1 = \frac{Q^2}{gA_2} + y_2 \].
03

Simplify the Momentum Equation for a Rectangular Channel

For a rectangular channel, the cross-sectional area \( A = by \), where \( b \) is the channel width. Hence, the equation becomes \[ \frac{Q^2}{gb^2y_1} + y_1 = \frac{Q^2}{gb^2y_2} + y_2 \]. Simplifying further using \( Q = by_1v_1 = by_2v_2 \), we get the conjugate depth relationship for rectangular channels: \( y_2 = \frac{2y_1}{\sqrt{1 + 8F_1^2} - 1} \), where \( F_1 = \frac{v_1}{\sqrt{gy_1}} \) is the Froude number.
04

Approximate the Shape of the Jump

The problem hints that the jump length \( L = 5y_2 \), and the shape can be approximated by a trapezoid. A trapezoid's area, with parallel sides of length \( y_1 \) and \( y_2 \), and height \( L \), is given by \[ A_{jump} = 0.5(y_1 + y_2)L \].
05

Relate Slope to Conjugate Depths

Using the momentum equation, the effect of the channel slope \( S_0 \) can be considered an additional force. However, the impact on the conjugate depths relationship is negligible for small slopes in derivation of \( y_2/y_1 \) under normal conditions, meaning \( S_0 \) contributes further downstream as an energy loss effect rather than a significant alteration on conjugate depth relation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conjugate Depths
In the context of a hydraulic jump, conjugate depths refer to the depths of water before and after the jump occurs across a flat or sloped surface. When water undergoes a hydraulic jump, it transitions from a high-speed, thin layer of flow to a slow-moving, thicker layer.
This transition involves two key depths: the upstream depth, often labeled as \( y_1 \), and the downstream depth, labeled as \( y_2 \). These depths are related, and understanding their relationship is crucial for predicting flow behavior. This connection is governed by the principle of momentum conservation. In a rectangular channel, these depths can be linked through the equation:
  • \( y_2 = \frac{2y_1}{\sqrt{1 + 8F_1^2} - 1} \)
where \( F_1 \) is the Froude number. This equation aids in determining one depth if the other is known, allowing engineers to design effective water management systems.
Momentum Conservation
Momentum conservation is a fundamental principle in fluid dynamics that helps to analyze hydraulic jumps. It states that the momentum before and after the jump must remain constant unless acted upon by an external force.
For a rectangular channel, the momentum conservation equation can be expressed as:
  • \( \frac{Q^2}{gA_1} + y_1 = \frac{Q^2}{gA_2} + y_2 \)
Here, \( Q \) represents the flow rate, \( g \) is gravitational acceleration, and \( A \) denotes the cross-sectional area. This simplifies to a form specific for a rectangular channel:
  • \( \frac{Q^2}{gb^2y_1} + y_1 = \frac{Q^2}{gb^2y_2} + y_2 \)
This principle allows us to balance the energy and momentum between upstream and downstream flows, ensuring accurate modeling of real-world water flow scenarios.
Rectangular Channel
A rectangular channel is a common structure in hydraulic engineering. It is designed with perpendicular sides and a flat bottom, which simplifies the calculation of flow properties.
In calculations, the cross-sectional area \( A \) of a rectangular channel is calculated as:
  • \( A = by \)
where \( b \) is the width of the channel and \( y \) is the flow depth. This straightforward geometry is advantageous for applying equations of motion and energy, which simplifies the analysis of phenomena like hydraulic jumps.
The rectangular shape allows uniform distribution of flows, making it easier to predict the behavior of liquids in such channels, a critical aspect when designing channels to maximize efficiency and control flow rates.
Froude Number
The Froude number is a dimensionless quantity used in fluid dynamics to describe the flow regime, particularly in open channel flows. It is expressed as:
  • \( F_1 = \frac{v_1}{\sqrt{gy_1}} \)
In this equation, \( v_1 \) represents the flow velocity, \( g \) is gravitational acceleration, and \( y_1 \) is the depth of the flow at the upstream section.
The Froude number helps classify the flow as:
  • Supercritical (\( F_1 > 1 \)): Fast, shallow flow.
  • Subcritical (\( F_1 < 1 \)): Slow, deep flow.
  • Critical (\( F_1 = 1 \)): Balance of inertial and gravitational forces.
Understanding the Froude number is essential for evaluating the stability of water flow, especially when predicting hydraulic jumps and their effects on structures like dams and weirs.

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Most popular questions from this chapter

Given that hydraulically rough flow conditions occur in open channels when \(u_{*} k_{s} / \nu \geq\) 70 , show that this condition can be expressed for water in terms of Manning parameters as $$ n^{6} \sqrt{R S_{0}} \geq 7.9 \times 10^{-14} $$ If a concrete-lined rectangular channel with a bottom width of \(5 \mathrm{~m}\) is constructed on a slope of \(0.05 \%\) and Manning's \(n\) is estimated to be \(0.013,\) determine the minimum flow depth for hydraulically rough flow conditions to exist.

Stages are measured by two recording gauges \(100 \mathrm{~m}\) apart along a constructed water supply channel. The channel has a bottom width of \(5 \mathrm{~m}\) and side slopes of \(3: 1(\mathrm{H}: \mathrm{V})\) The bottom elevations of the channel at the upstream and downstream gauge locations are \(24.01 \mathrm{~m}\) and \(23.99 \mathrm{~m}\), respectively. At a particular instance, the upstream and downstream stages are \(25.01 \mathrm{~m}\) and \(24.95 \mathrm{~m}\), respectively, and the flow is estimated as \(15 \pm 2 \mathrm{~m}^{3} / \mathrm{s}\). (a) Derive an expression for Manning's \(n\) as a function of the estimated flow rate. (b) Estimate Manning's \(n\) and the roughness height in the channel between the two measurement stations. (c) Quantitatively assess the sensitivity of the flow rate to the channel roughness.

A concrete-lined rectangular channel is \(8-\mathrm{m}\) wide and \(4-\mathrm{m}\) deep and has a longitudinal slope of \(0.2 \%\) and an estimated Manning's \(n\) of \(0.013 .\) A hydraulic structure controls the flow in the channel such that the depth of flow at the structure is \(3 \mathrm{~m}\) when the flow rate in the channel is \(24 \mathrm{~m}^{3} / \mathrm{s}\). Urban developers propose a localized contraction/expansion in the channel \(100 \mathrm{~m}\) upstream of the control structure to accommodate a pedestrian walkway. Taking eddy losses into account but neglecting friction losses, estimate the maximum contraction that should be allowed for the walkway. Based on your result, assess whether it is reasonable to neglect friction losses in this case.

Water flows in a concrete trapezoidal channel with a bottom width of \(3 \mathrm{~m}\), side slopes of \(2: 1(\mathrm{H}: \mathrm{V}),\) and a longitudinal slope of \(0.1 \% .\) The Manning roughness coefficient is estimated to be 0.015 . (a) What roughness height is characteristic of this channel? (b) For what range of flow depths and corresponding flow rates can \(n\) be assumed to be approximately constant and the Manning equation applicable? (c) If the flow rate in the channel is \(100 \mathrm{~m}^{3} / \mathrm{s}\), what Manning's \(n\) should be used and what is the corresponding flow depth? How does this flow depth compare with that obtained by using \(n=0.015 ?\)

A flume with a triangular cross section and side slopes of \(2: 1(\mathrm{H}: \mathrm{V})\) contains water flowing at \(0.45 \mathrm{~m}^{3} / \mathrm{s}\) at a depth of \(20 \mathrm{~cm}\). Verify that the flow is supercritical and calculate the conjugate depth.

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