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If the performance curve of a certain pump model is given by $$ h_{\mathrm{p}}=30-0.05 Q^{2} $$ where \(h_{\mathrm{p}}\) is the head added in \(\mathrm{m}\) and \(Q\) is the flow rate in \(\mathrm{L} / \mathrm{s}\), what is the performance curve of a pump system containing \(n\) of these pumps in series? What is the performance curve of a pump system containing \(n\) of these pumps in parallel?

Short Answer

Expert verified
Series: \( h_{system} = 30n - 0.05nQ^2 \), Parallel: \( h_{system} = 30 - \frac{0.05}{n^2} Q^2 \).

Step by step solution

01

Understand the Special Case

The given performance curve for one pump is \( h_p = 30 - 0.05 Q^2 \). This curve represents the relationship between the head added by the pump, \( h_p \) (in meters), and the flow rate, \( Q \) (in liters per second). Our task is to find the equivalent curve for multiple pumps in series or in parallel.
02

Pumps in Series

When pumps are arranged in series, the flow rate \( Q \) remains constant for each pump, but the head is accumulated across the pumps due to increased pressure. For \( n \) identical pumps, the total head is the sum of the heads added by each pump. Therefore, the equation becomes \( h_{system} = n \times (30 - 0.05 Q^2) \), which simplifies to \( h_{system} = 30n - 0.05nQ^2 \).
03

Pumps in Parallel

When pumps are arranged in parallel, the head \( h_p \) across each pump remains constant, but the flow rate is the sum of the flow rates through each pump. For \( n \) pumps in parallel, if each pump handles a flow rate \( Q/n \), the equation changes to \( h_{system} = 30 - 0.05 (Q/n)^2 \), which simplifies to \( h_{system} = 30 - \frac{0.05}{n^2} Q^2 \).
04

Final Performance Curves

For \( n \) pumps in series, the performance curve is \( h_{system} = 30n - 0.05nQ^2 \). For \( n \) pumps in parallel, the performance curve is \( h_{system} = 30 - \frac{0.05}{n^2} Q^2 \). These equations represent the new system performance, taking into account multiple pumps.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pumps in Series
When we talk about pumps in series, we imagine adding pumps one after another along the fluid path. This arrangement is useful when you need to increase the overall pressure of the system. In a series setup, each pump adds to the total head — essentially, the vertical lift that the pump can achieve. This means that the more pumps you have in series, the higher the potential elevation of the fluid.

For a given performance curve of a single pump governed by the equation \( h_p = 30 - 0.05 Q^2 \), when you place \( n \) pumps in series, the total head \( h_{system} \) becomes \( h_{system} = n \times (30 - 0.05 Q^2) \). This simplifies to \( h_{system} = 30n - 0.05nQ^2 \). The flow rate \( Q \) remains constant across each pump in series. This implies that if each pump adds a head of 30 meters at a certain flow rate, then in series, the contribution multiplies, creating a larger total head.
  • Series setup enhances pressure.
  • Flow rate remains constant.
  • Total head equals the sum of individual heads.
Pumps in Parallel
Arranging pumps in parallel differs significantly from a series setup. With pumps in parallel, all pumps work together to increase the flow rate capacity of the system. This configuration is ideal when you need a higher volume of fluid to be pumped but with the same pressure level. Each pump contributes to the total flow without altering the head, as the pressure across the pumps remains unchanged.

Given the performance curve for one pump as \( h_p = 30 - 0.05 Q^2 \), the parallel arrangement adapts as follows: Each pump handles a fraction of the total flow, \( Q/n \), and the performance curve becomes \( h_{system} = 30 - 0.05 (Q/n)^2 \), which simplifies to \( h_{system} = 30 - \frac{0.05}{n^2} Q^2 \). This means for \( n \) pumps, the head remains the same as a single pump, but the system can move a larger total amount of fluid.
  • Parallel setup increases flow rate.
  • Head across the system remains constant.
  • Total flow rate is shared among pumps.
Head-Flow Relationship
The head-flow relationship is a central concept in understanding pump performance and how different configurations affect system output. Head, measured in meters, represents the energy added to the fluid by the pump to overcome gravitational forces and system losses. Meanwhile, flow rate, often in liters per second (L/s), describes the volume of fluid the pump moves over time.

Each pump has a unique performance curve depicting how head decreases as flow rate increases, as seen in the formula \( h_p = 30 - 0.05 Q^2 \). This equation relates head \( h_p \) inversely to the square of the flow rate \( Q \), demonstrating that to increase flow, head must be sacrificed and vice versa. In practical terms, achieving a balance between desired head and flow rate is critical for efficient pump operation and system design.
  • Head signifies energy added to fluid.
  • Flow rate measures volume movement.
  • Inverse relationship critical for performance.
Fluid Mechanics Systems
Understanding fluid mechanics systems is vital for optimizing the use of pumps within any configuration. These systems encompass the behavior of fluids and the forces acting on them, essential knowledge for designing and controlling pump networks. In any pumping system, the objective is to efficiently move fluids from one location to another with minimal losses.

Incorporating multiple pumps requires a deep appreciation of concepts like velocity, pressure differentials, and potential energy, as they determine how effectively a pump system can do its job. Modern systems often incorporate sophisticated controls and sensors to maintain optimal conditions, ensuring that pumps operate within desired performance parameters.
  • Focus on fluid behavior and forces.
  • Enhance efficiency with design and control.
  • Utilize technology for system optimization.

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Most popular questions from this chapter

A single-jet Pelton wheel hydropower plant is to be operated such that the shaft power developed by the Pelton wheel is equal to \(15 \mathrm{MW}\) when the head just upstream of the nozzle is equal to \(1600 \mathrm{~m}\). The Pelton wheel is constructed such that is has a diameter of \(4 \mathrm{~m}\), has a deflection angle of \(170^{\circ},\) and rotates at a controlled speed of 600 rpm. Determine the appropriate nozzle diameter to be used in the project. Assume water at \(20^{\circ} \mathrm{C}\) and a nozzle loss coefficient of 0.03 .

A hydropower installation with reaction-type (Francis) turbines is to be located where the downstream water surface elevation is \(100 \mathrm{~m}\) below the water surface elevation in the upstream reservoir. The 2.0 -m-diameter concrete-lined penstock is \(500 \mathrm{~m}\) long and has an estimated roughness height of \(15 \mathrm{~mm}\). When the flow rate through the system is \(20 \mathrm{~m}^{3} / \mathrm{s}\), the combined head loss in the turbine and draft tube is \(5.0 \mathrm{~m}\), and the average velocity in the tailrace is \(0.80 \mathrm{~m} / \mathrm{s}\). Estimate the power that can be extracted from the system.

A pump manufacturer makes three homologous series of pumps with three different specific speeds. The manufacturer documents the performance of each homologous series by nondimensional functional relationships. An engineer identifies the desired homologous series for a particular project as the one that has a best efficiency point with a flow coefficient of \(0.035,\) a head coefficient of \(0.14,\) and a power coefficient of \(0.006 .\) For a particular pump with an impeller diameter of \(600 \mathrm{~mm}\) and a rated rotational speed of \(1140 \mathrm{rpm}\), determine the rated discharge, total dynamic head, brake horsepower, and efficiency of the pump. Assume water at \(20^{\circ} \mathrm{C}\).

A 1: 4 scale model of a water pump is operated at a speed of \(4500 \mathrm{rpm}\). At its best efficiency point, the efficiency of the model pump is \(84 \%,\) and the model delivers a flow rate of \(0.7 \mathrm{~m}^{3} / \mathrm{s}\) with an added head of \(4.9 \mathrm{~m}\). If the full-scale pump has a rotational speed of \(120 \mathrm{rpm}\), what is the flow rate and head delivered by the fullscale pump operating at its most efficient point? What is the power requirement of the full-scale pump at its best efficiency point? Assume water at \(20^{\circ} \mathrm{C}\).

A pump has an impeller diameter of \(300 \mathrm{~mm}\) and a rotational speed of \(1500 \mathrm{rpm}\). At the best efficiency operating point, the pump adds a head of \(9 \mathrm{~m}\) at a flow rate of \(25 \mathrm{~L} / \mathrm{s} .\) What is the specific speed of the pump? What type of pump is this likely to be?

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