/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A pump manufacturer makes three ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A pump manufacturer makes three homologous series of pumps with three different specific speeds. The manufacturer documents the performance of each homologous series by nondimensional functional relationships. An engineer identifies the desired homologous series for a particular project as the one that has a best efficiency point with a flow coefficient of \(0.035,\) a head coefficient of \(0.14,\) and a power coefficient of \(0.006 .\) For a particular pump with an impeller diameter of \(600 \mathrm{~mm}\) and a rated rotational speed of \(1140 \mathrm{rpm}\), determine the rated discharge, total dynamic head, brake horsepower, and efficiency of the pump. Assume water at \(20^{\circ} \mathrm{C}\).

Short Answer

Expert verified
Rated discharge: 0.073 m³/s; total head: 31.01 m; power: 6.007 kW; efficiency: 37.4%.

Step by step solution

01

Understand the Relationships

The flow coefficient \( \phi \), head coefficient \( \psi \), and power coefficient \( \beta \) are defined as nondimensional numbers that help describe the pump performance. These coefficients are given as follows: \( \phi = 0.035 \), \( \psi = 0.14 \), and \( \beta = 0.006 \). We will use these coefficients along with known pump parameters to find the required values.
02

Calculate Rated Discharge

The flow coefficient \( \phi \) is given by \( \phi = \frac{Q}{ND^3} \), where \( Q \) is the discharge, \( N \) is the rotational speed, and \( D \) is the impeller diameter. Rearrange to find \( Q \):\[Q = \phi \cdot N \cdot D^3\]Substitute in the known values \( N = 1140 \text{ rpm} \), \( D = 0.6 \text{ meters} \), and \( \phi = 0.035 \):\[Q = 0.035 \times \frac{1140}{60} \times (0.6)^3\]Calculate \( Q \):\[ Q \approx 0.07272 \text{ cubic meters per second} \].
03

Determine Total Dynamic Head

The head coefficient \( \psi \) is given by \( \psi = \frac{gH}{(N^2D^2)} \). Rearrange this to solve for \( H \):\[H = \psi \cdot \frac{N^2D^2}{g}\]Substitute the known values \( N = \frac{1140}{60} \text{ s}^{-1} \), \( D = 0.6 \text{ m} \), and \( \psi = 0.14 \), using \( g = 9.81 \text{ m/s}^2 \):\[H = 0.14 \times \frac{(1140/60)^2 \times (0.6)^2}{9.81}\]Calculate \( H \):\[ H \approx 31.01 \text{ meters} \].
04

Calculate Brake Horsepower

The power coefficient \( \beta \) is given by \( \beta = \frac{P}{\rho N^3 D^5} \), where \( P \) is the power and \( \rho \) is the density of water, approximately \(1000 \text{ kg/m}^3 \). Solve for \( P \):\[P = \beta \cdot \rho \cdot N^3 \cdot D^5\]Substitute the known values:\[P = 0.006 \times 1000 \times \left(\frac{1140}{60}\right)^3 \times (0.6)^5\]Calculate \( P \):\[ P \approx 6.007 \text{ kW} \].
05

Compute Efficiency

Efficiency \( \eta \) is calculated as the ratio of useful power output to the input power. This can be estimated by comparing the power calculated from the head and discharge to the brake horsepower:\[\eta = \frac{\rho \cdot g \cdot Q \cdot H}{P} \times 100 \%\]Substitute the values:\[\eta = \frac{1000 \times 9.81 \times 0.07272 \times 31.01}{6007} \times 100 \%\]Calculate \( \eta \):\[ \eta \approx 37.4 \% \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nondimensional Coefficients
Nondimensional coefficients play a crucial role in the analysis of pump performance, as they allow engineers to make comparisons between different pumps without the complication of differing units. These coefficients are derived by scaling physical parameters so that performance can be discussed in a universal way. The three primary nondimensional coefficients used in this context are the flow coefficient, head coefficient, and power coefficient. These each tell us something different about the pump's operation:
  • The flow coefficient indicates the efficiency in terms of fluid movement per unit of rotational speed and impeller size.
  • The head coefficient relates to the energy or height that the pump can achieve, based on a given speed and diameter.
  • The power coefficient helps determine the input energy required for the pump to operate at a certain speed and diameter.
Through these nondimensional coefficients, various pumps and systems can be compared on a consistent basis, aiding in selecting the most suitable pump for a given application.
Flow Coefficient
The flow coefficient, denoted as \( \phi \), is a dimensionless quantity that helps determine the performance of pumps in terms of fluid handling capacity. It is defined as:\[\phi = \frac{Q}{ND^3}\]where \( Q \) is the volumetric flow rate, \( N \) is the rotational speed, and \( D \) is the impeller diameter. This relationship gives us a way to see how the discharge capacity of the pump scales with its speed and size.

In practical terms, if we know the flow coefficient of a pump, we can calculate how much fluid it can move using the known revolutions per minute (rpm) and the size of the impeller. This makes it easier to compare pumps of different sizes while maintaining consistent operation efficiency. A higher flow coefficient would imply a pump capable of handling larger volumes of fluid, provided all other factors are constant.
Head Coefficient
The head coefficient, denoted \( \psi \), is a crucial nondimensional parameter, helping to quantify how high a pump can lift a fluid based on its speed and diameter. It is calculated by:\[\psi = \frac{gH}{N^2D^2}\]where \( g \) is the acceleration due to gravity, \( H \) is the total dynamic head or height, \( N \) is the rotational speed, and \( D \) is the diameter of the impeller.This coefficient is particularly useful when comparing pumps that work with fluids of similar density, like water. It allows engineers to predict the capacity of a pump to move fluids to desired heights without needing to test each pump under every conceivable condition. A higher head coefficient means the pump can lift the fluid higher for the same level of input speed and diameter.
Power Coefficient
The power coefficient, represented by \( \beta \), provides insight into how much power is needed by the pump to carry out its function. It can be expressed as:\[\beta = \frac{P}{\rho N^3 D^5}\]where \( P \) is the power used, \( \rho \) is the fluid density, \( N \) is the rotational speed, and \( D \) is the diameter of the impeller.The importance of the power coefficient lies in its ability to let engineers estimate the required energy input for a pump to achieve a specific flow rate and head. This facilitates efficient energy use and can guide the selection of pumps in systems where energy conservation is a priority. A lower power coefficient represents a pump that needs less power to operate at a given performance level, marking it as more energy-efficient in comparison to others with higher coefficients.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A proposed turbine is being designed to generate a power of \(30 \mathrm{MW},\) with a generator rotational speed of \(150 \mathrm{rpm}\) and an available head of \(22 \mathrm{~m}\). A model of the turbine is to be tested in the laboratory, where the available head is \(6 \mathrm{~m}\), the power is \(45 \mathrm{~kW},\) and the model turbine is expected to have a hydraulic efficiency of \(95 \%\). What length scale, rotational speed, and flow rate should be used in the model tests? Assume water at \(20^{\circ} \mathrm{C}\).

A pump with a rotary speed of 1725 rpm delivers \(25 \mathrm{~L} / \mathrm{s}\) at its most efficient operating point. Under this condition, the inflow velocity is normal to the inflow surface of the impeller, the component of the velocity normal to the outflow surface of the impeller is \(4 \mathrm{~m} / \mathrm{s}\), and the efficiency of the pump is \(80 \%\). The width of the impeller at the outflow surface is \(15 \mathrm{~mm}\), and the blade angle at the outflow surface is \(50^{\circ}\). (a) Estimate the head added by the pump. (b) Use the affinity laws to estimate the head added and the flow rate delivered by the pump when the rotational speed is changed to \(1140 \mathrm{rpm}\).

At a Pelton wheel installation, the water surface elevation in the supply reservoir is \(85 \mathrm{~m}\) above the nozzle; the delivery line has a diameter of \(600 \mathrm{~mm}\), a length of \(300 \mathrm{~m}\), and a roughness height of \(8 \mathrm{~mm}\). The discharge nozzle has a diameter of \(50 \mathrm{~mm}\) and a head loss coefficient of \(0.8 .\) The bucket friction loss coefficient is \(0.5,\) the velocity of water relative to the bucket at the exit from the bucket is \(2 \mathrm{~m} / \mathrm{s},\) and the absolute velocity of the water leaving the bucket is \(6 \mathrm{~m} / \mathrm{s}\). Determine the power that could be derived from the system and the hydraulic efficiency of the turbine.

A pump is to be used to withdraw water from a reservoir at a rate of \(1500 \mathrm{~L} / \mathrm{s}\). When operating at this flow rate, the head loss in the suction pipe is estimated to be \(2.3 \mathrm{~m}\), and the pump specifications give the required net positive suction head as \(2.9 \mathrm{~m}\). Standard sea-level atmospheric conditions are expected at the site, and under worstcase conditions, the temperature of the water in the reservoir is \(25^{\circ} \mathrm{C}\). What is the maximum allowable elevation of the suction side of the pump above the reservoir water surface?

A proposed hydropower plant is to be located at a site with an available head of \(9 \mathrm{~m}\), and it is desired to obtain a (shaft) power of \(35 \mathrm{MW}\) from this site. The axial-flow turbine units under consideration operate at an angular speed of \(150 \mathrm{rpm}\), have a specific speed of \(5,\) and have an estimated maximum efficiency of \(80 \%\). (a) How may of these units are required? (b) What total flow rate must be available to generate the desired power? Assume water at \(20^{\circ} \mathrm{C}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.