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The velocity field in a two-dimensional flow is given by $$ \mathbf{V}=(2+8 x+4 y) \mathbf{i}+(1+4 x-6 y) \mathbf{j} $$ Determine the vorticity field and assess the rotationality of the flow.

Short Answer

Expert verified
The vorticity is zero; the flow is irrotational.

Step by step solution

01

Understanding Vorticity in a Flow

Vorticity, denoted as \( \boldsymbol{\omega} \), is a measure of the local rotation in a fluid flow. In two-dimensional flow, the vorticity is a vector whose only non-zero component is perpendicular to the plane of the flow. The vorticity vector in two dimensions is \( \boldsymbol{\omega} = (0, 0, \omega_z) \) where \( \omega_z \) is the out-of-plane component.
02

Formula for Vorticity in 2D

The vorticity component \( \omega_z \) in two dimensions is given by the formula \( \omega_z = \frac{\partial v}{\partial x} - \frac{\partial u}{\partial y} \), where \( u \) and \( v \) are the components of the velocity field \( \mathbf{V} = u \mathbf{i} + v \mathbf{j} \).
03

Identifying Velocity Components

From the velocity field \( \mathbf{V} = (2 + 8x + 4y) \mathbf{i} + (1 + 4x - 6y) \mathbf{j} \), we identify \( u = 2 + 8x + 4y \) and \( v = 1 + 4x - 6y \).
04

Calculate \( \frac{\partial v}{\partial x} \)

To find \( \frac{\partial v}{\partial x} \), take the partial derivative of \( v = 1 + 4x - 6y \) with respect to \( x \). This results in \( \frac{\partial v}{\partial x} = 4 \).
05

Calculate \( \frac{\partial u}{\partial y} \)

To find \( \frac{\partial u}{\partial y} \), take the partial derivative of \( u = 2 + 8x + 4y \) with respect to \( y \). This results in \( \frac{\partial u}{\partial y} = 4 \).
06

Determine Vorticity \( \omega_z \)

Substitute the calculated partial derivatives into the vorticity formula: \( \omega_z = 4 - 4 = 0 \). This means the vorticity vector is \( \boldsymbol{\omega} = (0, 0, 0) \).
07

Assess Rotationality of the Flow

Since the vorticity \( \boldsymbol{\omega} \) is zero, the flow is irrotational. In fluid dynamics, a flow with zero vorticity is said to be irrotational, indicating no local spinning motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Irrotational Flow
In fluid dynamics, an irrotational flow is one where the vorticity is zero everywhere in the fluid. Vorticity measures the local spinning motion of the fluid; hence, when a flow is irrotational, this implies no internal spinning at any point within the fluid.

To determine whether a flow is irrotational, one examines the vorticity vector. For a two-dimensional flow, this vector has only one non-zero component perpendicular to the plane of flow. If this component is zero, the flow is irrotational. This generally indicates a streamlined and orderly fluid motion without swirls or eddies.

Mathematically speaking, in this specific problem, the vorticity was found to be zero, confirming the flow as irrotational. Such flows are often easier to analyze and are pivotal in solving many practical fluid dynamics problems.
Velocity Field
A velocity field represents the velocity of fluid particles at every point in a fluid flow. It indicates how fast and in which direction the fluid particles are moving. The velocity field is typically expressed in terms of its components in a coordinate system.

In this exercise, the two-dimensional velocity field is given by: \[ \mathbf{V} = (2 + 8x + 4y) \mathbf{i} + (1 + 4x - 6y) \mathbf{j} \] Where:\( u = 2 + 8x + 4y \) is the velocity component in the x-direction and \( v = 1 + 4x - 6y \) is the velocity component in the y-direction.

Understanding this velocity field helps in plotting the pathlines, streamlines, and further analyzing the dynamics of the flow. It's imperative to understand these components thoroughly whenever analyzing fluid motion in multidimensional spaces.
Two-Dimensional Flow
Two-dimensional flow refers to fluid motion where the velocity components are only functions of two spatial dimensions, typically x and y, meaning the third dimension's impact is negligible or constant.

In two-dimensional flows, the analysis becomes simpler because it involves fewer components. The velocity field has two main components in the x and y directions, making visualizations like streamlines and pathlines vastly easier.

The vorticity in such flows also simplifies, as seen in this problem, where only one component of vorticity exists perpendicular to the plane. This simplification is crucial when determining rotationality, especially in fluid dynamics contexts or applications involving things like aerodynamics and weather systems.
Rotationality Assessment
Assessing the rotationality of a flow involves examining the vorticity. In fluid dynamics, a flow with zero vorticity is deemed irrotational. Therefore, to assess whether a flow is rotational, one calculates the vorticity and checks its magnitude.

In this exercise, after computing the vorticity component \( \omega_z \), it was found to be zero: \[ \omega_z = \frac{\partial v}{\partial x} - \frac{\partial u}{\partial y} = 4 - 4 = 0 \] This result confirms the flow as non-rotational or irrotational, indicating no local spinning.

Understanding the rotationality of flow is critical for applications that require precise flow control and prediction, such as in engineering systems and atmospheric science, ensuring efficient performance and safety.

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Most popular questions from this chapter

Two-dimensional unsteady flow of an incompressible fluid occurs in the \(x y\) plane. When polar coordinates are used, the \(\theta\) -component of the velocity is given by $$ v_{\theta}=-\frac{C \sin \theta}{r^{2}} $$ where \(C\) is a constant. Determine the required functional form of the \(r\) -component of the velocity.

A flow field in which the radial component of the velocity is everywhere equal to zero and in which the tangential component of the velocity depends only on the radial distance, \(r\), from a center point is called a vortex. Consider the vortex illustrated in Figure \(5.69,\) where Point \(P\) is the center of the vortex, Point 1 is on one streamline, and Point 2 is on another streamline. For which of the following velocity fields can the Bernoulli equation be applied between Points 1 and \(2: v_{\theta}=a r\) or \(v_{\theta}=a / r\), where \(a\) is any constant?

A viscous liquid flows down an inclined plane as shown in Figure \(5.62 .\) The flow is two-dimensional in the \(x y\) plane, and the \(x\) -axis is oriented in the flow direction. Apply the Navier-Stokes equation to this problem and write the components of the Navier-Stokes equation in their most simplified forms.

The stream function of a particular two-dimensional flow field is given by \(\psi=\) \(0.2 x y \mathrm{~m}^{2} / \mathrm{s}\), where \(x\) and \(y\) are the Cartesian coordinates in meters. Determine the volume flow rate between the points \((1 \mathrm{~m}, 1 \mathrm{~m})\) and \((2 \mathrm{~m}, 3 \mathrm{~m})\).

A two-dimensional velocity field has the velocity components \(u=-2 x\) and \(v=2 y\). (a) Verify that this flow field can be described by a potential function. (b) Determine the circulation, \(\Gamma,\) around a closed path of straight lines connecting the following points: \((1,1),(2,1),(2,4),(1,4),\) and \((1,1) .\) Explain the significance of your result.

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