/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 The stream function of a particu... [FREE SOLUTION] | 91Ó°ÊÓ

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The stream function of a particular two-dimensional flow field is given by \(\psi=\) \(0.2 x y \mathrm{~m}^{2} / \mathrm{s}\), where \(x\) and \(y\) are the Cartesian coordinates in meters. Determine the volume flow rate between the points \((1 \mathrm{~m}, 1 \mathrm{~m})\) and \((2 \mathrm{~m}, 3 \mathrm{~m})\).

Short Answer

Expert verified
The volume flow rate is 1.0 m²/s between the points.

Step by step solution

01

Understanding the Stream Function

The stream function \(\psi\) is given as \(\psi = 0.2xy\). In two-dimensional incompressible flow, the difference in the stream function values between two points represents the volume flow rate between those points.
02

Calculate Stream Function at Point 1

Substitute \(x = 1\) and \(y = 1\) into the stream function equation:\[ \psi_1 = 0.2(1)(1) = 0.2 \, \mathrm{m}^2/\mathrm{s}. \]
03

Calculate Stream Function at Point 2

Substitute \(x = 2\) and \(y = 3\) into the stream function equation:\[ \psi_2 = 0.2(2)(3) = 1.2 \, \mathrm{m}^2/\mathrm{s}. \]
04

Determine the Volume Flow Rate

The volume flow rate between two points in a stream function is given by \[ Q = \psi_2 - \psi_1. \]Substitute the values obtained:\[ Q = 1.2 - 0.2 = 1.0 \, \mathrm{m}^2/\mathrm{s}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Volume Flow Rate
Volume flow rate is a measure of how much fluid flows through a specific area per unit time. It is an essential concept in fluid mechanics that helps us determine the efficiency of fluid motion in different applications like pipes, rivers, or any system where fluid transfer is required.
In the context of stream functions, the volume flow rate between two points can be calculated by finding the difference in the stream function values at those points. This is particularly useful in analyzing two-dimensional flow fields.
When you calculate the stream function values at specific points and find their difference, you essentially measure the total volume of fluid passing through the area bounded by these points in a unit of time. This difference directly gives the volume flow rate in the units of square meters per second (\(\mathrm{m}^2/\mathrm{s}\)).
Exploring Two-Dimensional Flow
Two-dimensional flow refers to fluid movement that is confined to a plane, meaning it occurs in two dimensions only, disregarding any variations in the third dimension. This simplification is crucial in fluid dynamics as it allows for easier analysis and visualization using concepts like stream functions.
In many real-world applications, such as aerodynamics over airfoils or water flow in open channels, flow can be approximated as two-dimensional. This assumption helps in developing manageable mathematical models to describe the fluid motion.
For instance, using a stream function \(\psi\), we can represent two-dimensional flow fields. In these fields, streamlines can easily be derived, showing the paths of fluid elements over time without crossing one another. This visualization is smooth and intuitive, helping engineers and scientists analyze complex flow patterns.
Incompressible Flow Significance
Incompressible flow is a type of fluid flow where the fluid density remains constant throughout. This assumption simplifies the equations of motion considerably, as it negates changes in density with pressure and temperature variations.
In many practical scenarios, particularly liquids like water, this approximation holds true. This is why incompressibility is an integral part of the study of fluid mechanics and modeling flows in engineering systems where volume conservation is crucial.
When dealing with incompressible flow in two-dimensional scenarios, the stream function becomes a powerful tool. The constant density ensures that the volume flow rate, derived from differences in the stream function, remains a reliable measure of actual fluid movement across a given surface without stretching or compressing. This consistency is vital for precise calculations and assessments in both theoretical studies and practical applications of fluid dynamics.

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Most popular questions from this chapter

The velocity components in a two-dimensional velocity field in the \(y z\) plane are \(u=2 y^{2} \mathrm{~m} / \mathrm{s}\) and \(v=-2 y z \mathrm{~m} / \mathrm{s},\) where \(y\) and \(z\) are in meters. Determine the rate of rotation of a fluid element about the point ( \(1 \mathrm{~m}, 1 \mathrm{~m}\) ). Indicate whether the rotation is in the clockwise or counterclockwise direction.

Consider a flow with the following steady-state velocity field: $$ \mathbf{V}=6 x y \mathbf{i}+3 y z \mathbf{j}+4 x z^{2} \mathbf{k} $$ Determine the acceleration field. Determine the velocity and acceleration at \((x, y, z)\) \(=(3,4,2)\)

The two-dimensional velocity field of an incompressible fluid is given by \(u=3 y(4 x+\) 1), \(v=-6 y^{2}+x^{2}\). Determine the analytic expression for the stream function and describe how you would use this stream function to plot the streamlines of the flow.

A two-dimensional velocity field in the \(r \theta\) plane is described by the velocity components \(v_{r}=-6 / r \mathrm{~m} / \mathrm{s}\) and \(v_{\theta}=3 / r \mathrm{~m} / \mathrm{s}\), where \(r\) and \(\theta\) are polar coordinates in meters and radians, respectively. The gravity force acts in the negative \(z\) -direction, and the fluid has a density of \(1.20 \mathrm{~kg} / \mathrm{m}^{3}\). Calculate the pressure gradients in the \(r\) -, \(\theta-,\) and \(z\) -directions at \(r=2 \mathrm{~m}\) and \(\theta=\pi / 4 \mathrm{rad}\).

SAE 30 oil at \(20^{\circ} \mathrm{C}\) flows between two horizontal \(0.50-\mathrm{m}\) -wide parallel plates separated by \(30 \mathrm{~mm}\). The length of the top and bottom plates in the direction of flow is \(2 \mathrm{~m}\), the bottom plate is stationary, the top plate moves at \(3 \mathrm{~cm} / \mathrm{s}\), an adverse pressure gradient of \(700 \mathrm{~Pa} / \mathrm{m}\) is applied between the plates, and the flow is laminar between the plates. Determine the flow rate between the plates and the force that must be applied to move the top plate.

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