/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 The two-dimensional flow field o... [FREE SOLUTION] | 91Ó°ÊÓ

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The two-dimensional flow field of an incompressible fluid is described in polar coordinates as \(v_{r}=2 / r, v_{\theta}=4 / r^{2}\). Determine the analytic expression for the stream function.

Short Answer

Expert verified
\( \psi(r, \theta) = \frac{4}{r} + 2\theta \)

Step by step solution

01

Understand Stream Function

For an incompressible flow in polar coordinates, the stream function \( \psi(r, \theta) \) is defined such that \( v_r = \frac{1}{r} \frac{\partial \psi}{\partial \theta} \) and \( v_\theta = -\frac{\partial \psi}{\partial r} \). These relationships help us relate velocity components to the stream function.
02

Integrate for \( \frac{\partial \psi}{\partial r} \)

Starting with the expression \( v_\theta = -\frac{\partial \psi}{\partial r} \), substitute \( v_\theta = \frac{4}{r^2} \) to get:\[-\frac{\partial \psi}{\partial r} = \frac{4}{r^2}\]Integrate with respect to \( r \) to find \( \psi(r, \theta) \):\[\psi = -\int \frac{4}{r^2}\, dr = \frac{4}{r} + f(\theta)\]
03

Integrate for \( \frac{1}{r} \frac{\partial \psi}{\partial \theta} \)

Using the expression \( v_r = \frac{1}{r} \frac{\partial \psi}{\partial \theta} \), substitute \( v_r = \frac{2}{r} \):\[\frac{1}{r} \frac{\partial \psi}{\partial \theta} = \frac{2}{r}\]Multiply by \( r \) and integrate with respect to \( \theta \):\[\frac{\partial \psi}{\partial \theta} = 2\]Integrate:\[\psi = 2\theta + g(r)\]
04

Combine and Solve for \( \psi(r, \theta) \)

Combine the results from the previous steps. Our expressions for \( \psi \) were \( \psi = \frac{4}{r} + f(\theta) \) and \( \psi = 2\theta + g(r) \), implying:\[\psi = \frac{4}{r} + 2\theta\]Here, the function of integration could be any constant, but typically added parts are included accordingly to both functions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Incompressible Flow
Incompressible flow refers to fluid motion where the fluid's density remains constant over time. This usually occurs in liquids rather than gases. In the context of this exercise, we are dealing with a two-dimensional incompressible fluid flow in polar coordinates.
The key characteristic of incompressible flow is that the divergence of the velocity field must be zero. Mathematically, this is expressed as:\[abla \cdot \mathbf{v} = 0\]where \( \mathbf{v} \) is the velocity vector of the fluid. For our two-dimensional situation, it simplifies to involve the radial and angular components of velocity in polar coordinates:
  • Radial component: \( v_r \)
  • Angular component: \( v_\theta \)
The stream function, which we'll discuss more, becomes particularly useful in describing the velocity of incompressible flows without directly dealing with the pressure changes.
Polar Coordinates
Polar coordinates offer a way to describe the spatial position of a point based on its distance from a reference point and its angular displacement from a reference direction.
This system is especially useful in problems with circular or rotational symmetry, like the one we are considering.
To understand water flowing in a circle, like around a drain, it's easier to use the terms radius \( r \) and angle \( \theta \) rather than \( x \) and \( y \) Cartesian coordinates.
The main components in this system are:
  • \( r \) - the distance from the origin to the point.
  • \( \theta \) - the angle from a reference direction, usually taken from the positive x-axis.
  • Velocity has components \( v_r \) and \( v_\theta \) in the radial and angular directions, respectively.
This framework simplifies the analysis of the flow field by adapting to its natural geometry.
Streamline Equation
In fluid mechanics, streamlines are lines that represent the flow of the fluid such that the tangent at any point on it equals the velocity of the fluid at that point. The stream function \( \psi \, (r, \theta) \) gives a way to visualize these lines.
For this problem:\[v_r = \frac{1}{r} \frac{\partial \psi}{\partial \theta}\]
\[v_\theta = -\frac{\partial \psi}{\partial r}\]
By finding \( \psi \), one can draw streamlines, providing insights into the behavior of the fluid flow.
This function is chosen such that the derivative with respect to either \( r \) or \( \theta \) yields the respective velocity component, ensuring that \( abla \cdot \mathbf{v} = 0 \). It's a practical and mathematical tool to study complex fluid motions easily, especially when working with incompressible flows.
Velocity Components
Velocity components in polar coordinates, \( v_r \) and \( v_\theta \), decompose the velocity \( \mathbf{v} \) of a fluid particle into directional parts aligned with the radial and angular directions.
These components give a precise understanding of the motion direction:
  • Radial Component \( v_r \): Describes how fast the particle moves towards or away from the center. In our task, \( v_r = \frac{2}{r} \).
  • Angular Component \( v_\theta \): Describes the rotational movement around the center. In this exercise, \( v_\theta = \frac{4}{r^2} \).
Combining these helps form a complete picture of fluid motion, tailored to the problem's geometry. Understanding how these velocities intertwine is crucial for deriving other flow characteristics like the stream function. These velocity expressions contributed directly to finding the streamlines of the flow, indicating paths that particles in the fluid follow.

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Most popular questions from this chapter

Consider the steady flow of SAE 10 oil at \(20^{\circ} \mathrm{C}\) between two horizontal flat plates spaced \(20 \mathrm{~mm}\) apart. The average pressure between the plates is on the order of \(100 \mathrm{kPa}\), and the average velocity is on the order of \(0.08 \mathrm{~m} / \mathrm{s}\). What simplified form of the Navier-Stokes equation would be applicable in this situation?

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In a two-dimensional incompressible flow field, the \(y\) component of the velocity, \(v\), is given by \(v=5 x^{2}\). The \(x\) component of the velocity, \(u(x, y)\), is unknown, but it is known that \(u(x, y)\) must satisfy the boundary condition that \(u(0, y)=0\). Determine \(u(x, y)\)

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