/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 SAE 30 oil at \(20^{\circ} \math... [FREE SOLUTION] | 91影视

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SAE 30 oil at \(20^{\circ} \mathrm{C}\) flows in a \(15-\mathrm{m}\) -long, \(225-\mathrm{mm}\) -diameter pipe. The pipe is horizontal, and under a particular flow condition, the volume flow rate is \(20 \mathrm{~L} / \mathrm{min}\). (a) Verify that Hagen-Poiseuille flow can be assumed in the pipe. (b) What is the difference in pressure between the entrance and exit of the pipe?

Short Answer

Expert verified
(a) Yes, Hagen-Poiseuille flow can be assumed as the flow is laminar with Re = 644. (b) The pressure difference is 1936.1 Pa.

Step by step solution

01

Check Laminar Flow Condition

To verify if Hagen-Poiseuille flow can be assumed, we need to check if the flow is laminar. The flow is considered laminar if the Reynolds number \( Re \) is less than 2000. The Reynolds number for flow in a pipe is given by:\[Re = \frac{\rho u D}{\mu}\]Where:\( \rho \) = density of fluid,\( u \) = velocity of fluid,\( D \) = diameter of the pipe,\( \mu \) = dynamic viscosity of the fluid.Given:- Volume flow rate \( Q = 20 \text{ L/min} = 0.000333 \text{ m}^3/\text{s}\)- Diameter \( D = 0.225 \text{ m} \)- Kinematic viscosity of SAE 30 oil at \(20^{\circ} \text{C}\), \( u = 2.92 \times 10^{-5} \text{ m}^2/\text{s}\)Velocity, \( u \), can be calculated from:\[u = \frac{Q}{A} = \frac{Q}{\frac{\pi D^2}{4}}\]Plugging in the values, we get \( u = \frac{0.000333}{\frac{\pi (0.225)^2}{4}} = 0.00836 \text{ m/s} \).\[ Re = \frac{0.00836 \times 0.225}{2.92 \times 10^{-5}} = 644 \]Since \( Re = 644 \lt 2000 \), the flow is laminar.
02

Apply Hagen-Poiseuille Equation

To find the pressure difference between the entrance and the exit of the pipe, we use the Hagen-Poiseuille equation for laminar flow:\[\Delta P = \frac{8 \mu L Q}{\pi R^4}\]Where:- \( L = 15 \text{ m} \)- \( R = \frac{D}{2} = 0.1125 \text{ m} \)- \( \mu \) (dynamic viscosity) is given by \( \mu = \rho u \) where \( \rho \) (the density) is approximately \( 891 \text{ kg/m}^3 \)First, calculate the dynamic viscosity:\[\mu = 891 \times 2.92 \times 10^{-5} = 0.0260 \text{ Ns/m}^2\]Then, substitute the values into the Hagen-Poiseuille equation:\[\Delta P = \frac{8 \times 0.0260 \times 15 \times 0.000333}{\pi \times (0.1125)^4} = 1936.1 \text{ Pa}\]The difference in pressure between the entrance and the exit of the pipe is 1936.1 Pascal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
The Reynolds number is a crucial dimensionless quantity in fluid mechanics used to predict the flow pattern in different fluid flow situations. It's crucial for determining whether the flow is laminar or turbulent. The Reynolds number is calculated using the formula:\[ Re = \frac{\rho u D}{\mu} \]where:
  • \( \rho \) is the density of the fluid.
  • \( u \) is the velocity of the fluid.
  • \( D \) is the diameter of the pipe.
  • \( \mu \) is the dynamic viscosity of the fluid.
For flow in a pipe, if the Reynolds number is less than 2000, the flow is considered laminar. This was confirmed in the original exercise, where the computed Reynolds number was 644鈥攊ndicating laminar flow. Understanding the Reynolds number allows engineers to design systems that may require either laminar or turbulent flow, depending on the application's needs.
Laminar Flow
Laminar flow is a type of fluid flow where the fluid moves in smooth paths or layers, with little to no disruption between them. This flow regime is characterized by low fluid velocity and high viscosity. In such conditions, the different layers of fluid slide past one another in an orderly manner, which makes the flow predictable and orderly. Identifying laminar flow is essential in applications involving fluids, such as in medical devices or chemical processing, where the precise control of fluid behavior is needed. The hallmark sign of laminar flow is a Reynolds number less than 2000, as shown in the solution, where a flow pattern was deemed laminar with a Reynolds number of 644. Laminar flow ensures that calculations like those using the Hagen-Poiseuille equation remain accurate, providing reliable assessments of pressure drop and other critical factors in engineering design.
Dynamic Viscosity
Dynamic viscosity is a measure of a fluid's resistance to flow. It's a fundamental parameter that describes the internal friction in a fluid, which is crucial for understanding how a fluid will behave under different flow conditions. The dynamic viscosity \( \mu \) can be calculated using the relationship between density \( \rho \) and kinematic viscosity \( u \):\[ \mu = \rho u \]In the exercise, the kinematic viscosity of the SAE 30 oil was given, allowing us to compute dynamic viscosity. With a density of 891 kg/m鲁 and a kinematic viscosity of 2.92 x 10鈦烩伒 m虏/s, the dynamic viscosity was calculated to be 0.0260 Ns/m虏. This is key for calculating the Reynolds number and for applying the Hagen-Poiseuille equation, which ultimately helped determine the pressure drop in the pipe. Different fluids will exhibit unique viscosity values, which can significantly affect fluid dynamics and system design.
Pressure Drop in Pipe Flow
Pressure drop in pipe flow is an important factor in the design of piping systems, affecting the energy required to transport fluids. It is influenced by the pipe's length, diameter, fluid properties, and flow velocity. For laminar flow, such as in the scenario where Reynolds number is low, the pressure drop can be accurately calculated using the Hagen-Poiseuille equation:\[ \Delta P = \frac{8 \mu L Q}{\pi R^4} \]where \( L \) is the pipe length, \( Q \) is the volume flow rate, \( \mu \) is the dynamic viscosity, and \( R \) is the pipe radius. Substituting the given values from the problem, a pressure drop of 1936.1 Pa was found between the pipe's entrance and exit. Understanding pressure drop is vital for ensuring efficient fluid transport, minimizing energy consumption, and maintaining optimal operation in fluid systems. The Hagen-Poiseuille equation applies only under laminar flow conditions, emphasizing the importance of flow characterization in practical applications.

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