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Two-dimensional unsteady flow of an incompressible fluid occurs in the \(x y\) plane. When polar coordinates are used, the \(r\) component of the velocity is given by $$ v_{r}=r^{2} \sin \theta+r \cos \theta $$ Determine the required functional form of the \(\theta\) -component of the velocity.

Short Answer

Expert verified
\( v_\theta = 3r^2 \cos \theta + 2r \sin \theta \).

Step by step solution

01

Identify the Continuity Equation

For an incompressible fluid in polar coordinates, the continuity equation is given by \( \frac{1}{r} \frac{\partial}{\partial r}(r v_r) + \frac{1}{r} \frac{\partial v_\theta}{\partial \theta} = 0 \). This equation ensures mass conservation in the flow.
02

Substitute the r-Component of Velocity

Substitute \( v_r = r^2 \sin \theta + r \cos \theta \) into the continuity equation to find \( v_\theta \). First, calculate the term \( \frac{1}{r} \frac{\partial}{\partial r}(r v_r) \).
03

Calculate the Derivative

Calculate \( r v_r = r^3 \sin \theta + r^2 \cos \theta \), then differntiate with respect to \( r \) to get \( \frac{\partial}{\partial r}(r v_r) = 3r^2 \sin \theta + 2r \cos \theta \).
04

Plug into the Continuity Equation

Substituting into the continuity equation gives \( \frac{1}{r}(3r^2 \sin \theta + 2r \cos \theta) + \frac{1}{r} \frac{\partial v_\theta}{\partial \theta} = 0 \). Simplifying the first term results in \( 3r \sin \theta + 2 \cos \theta \).
05

Solve for \( \frac{\partial v_\theta}{\partial \theta} \)

Rearrange terms to find \( \frac{\partial v_\theta}{\partial \theta} = -r(3r \sin \theta + 2 \cos \theta) \). Simplify it as \( = -3r^2 \sin \theta - 2r \cos \theta \).
06

Integrate with Respect to \( \theta \)

Integrate \( \frac{\partial v_\theta}{\partial \theta} \) with respect to \( \theta \) to find \( v_\theta \). Calculating the integrals gives \( v_\theta = 3r^2 \cos \theta + 2r \sin \theta + f(r) \), where \( f(r) \) is a function of \( r \) only.
07

Determine the Function \( f(r) \)

Since there are no boundary conditions specified and there's no dependence of \( v_\theta \) on any functions other than those already accounted for, assume that \( f(r) = 0 \). Therefore, \( v_\theta = 3r^2 \cos \theta + 2r \sin \theta \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
In fluid mechanics, polar coordinates are an alternative to Cartesian coordinates for describing the position of a point in a plane. Instead of using x and y coordinates, we use the radial distance r from the origin, and the angle \( \theta \) from the positive x-axis.
This system is particularly useful for solving problems exhibiting rotational symmetry or when dealing with circular geometries.
  • The radial coordinate \( r \) measures the distance from the origin, and it is always non-negative.
  • The angular coordinate \( \theta \) is the angle in radians, usually measured counterclockwise from the positive x-axis.
Polar coordinates simplify the mathematical description of physical phenomena involving circles or rotations. In the context of this problem, employing polar coordinates allows us to efficiently express velocities as functions of \( r \) and \( \theta \), enhancing problem-solving approaches.
Continuity Equation
The continuity equation is a fundamental principle in fluid dynamics that expresses the conservation of mass in a fluid system. For an incompressible fluid, which means the fluid density remains constant, the continuity equation is written as:\[\frac{1}{r} \frac{\partial}{\partial r}(r v_r) + \frac{1}{r} \frac{\partial v_\theta}{\partial \theta} = 0\]This equation ensures that the flow does not create or destroy mass. It must, therefore, be satisfied by the velocity components of the flow.
  • \( v_r \) is the radial component of velocity, showing how fast the fluid is moving away or toward the origin.
  • \( v_\theta \) is the tangential component of velocity, representing fluid movement along a circle centered at the origin.
The continuity equation is essential when solving problems involving fluid flow, as it provides a relationship between these velocity components, allowing us to determine unknown velocity profiles.
Two-Dimensional Flow
In fluid dynamics, two-dimensional (2D) flow refers to a kind of flow where the velocity at every point can be described using only two spatial dimensions, typically denoted as x and y, or in polar coordinates, r and \( \theta \).
This simplification occurs when variations along the third axis (such as z in a 3D space) are negligible compared to those in the other two axes.
  • 2D flow is common in many applications and significantly eases the complexity of solving fluid dynamics problems.
  • It allows for more manageable calculations while adequately capturing the flow behavior across an area or section of the flow field.
In the given problem, the flow is assumed two-dimensional, simplifying the analysis since only the radial and tangential components need to be considered, reducing potential three-dimensional complexities.
Unsteady Flow
Unsteady flow in fluid dynamics describes a condition where the flow properties, such as velocity, pressure, or density, change with time at a given point in space.
Unlike steady flow, where these properties are constant, unsteady flow can vary, and the systems must be analyzed at different time instances.
  • In this exercise, the flow is unsteady, indicating that the velocity components \( v_r \) and \( v_\theta \) are functions of both the spatial coordinates and time.
  • This temporal change requires time to be considered when applying equations such as the continuity equation.
Unsteady flows are often more challenging to study due to their time-varying nature, but they more accurately represent real-world phenomena such as waves, pulsating flows, and turbulent flows.

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Most popular questions from this chapter

SAE 30 oil at \(20^{\circ} \mathrm{C}\) flows in a \(15-\mathrm{m}\) -long, \(225-\mathrm{mm}\) -diameter pipe. The pipe is horizontal, and under a particular flow condition, the volume flow rate is \(20 \mathrm{~L} / \mathrm{min}\). (a) Verify that Hagen-Poiseuille flow can be assumed in the pipe. (b) What is the difference in pressure between the entrance and exit of the pipe?

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