Chapter 4: Problem 21
Water flows over a \(0.2-\mathrm{m}\) -high step in a 5 -m-wide channel as illustrated in Figure 4.52. If the flow rate in the channel is \(15 \mathrm{~m}^{3} / \mathrm{s}\) and the upstream and downstream depths are \(3.00 \mathrm{~m}\) and \(2.79 \mathrm{~m}\), respectively, calculate the force on the step.
Short Answer
Step by step solution
Determine Cross-sectional Area Upstream
Determine Cross-sectional Area Downstream
Calculate Flow Velocity Upstream
Calculate Flow Velocity Downstream
Calculate Forces Using Bernoulli's Equation
Insert Known Values to Determine Pressure Force
Calculate Net Horizontal Force
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bernoulli's Equation
This principle is essentially a statement of the conservation of energy principle for flowing fluids. For our problem, this means:
- When high initial pressure is applied, the velocity of flow increases, reducing potential energy due to lower fluid height.
- The mathematical expression we use simplifies the complex interactions by equating various forms of energy in the fluid.
Flow Velocity
Here's how to understand it:
- The flow velocity helps calculate important parameters like pressure changes and forces exerted by the fluid on surfaces.
- It can be determined using the continuity equation, which asserts that the product of cross-sectional area and flow velocity is constant for incompressible flows.
Cross-sectional Area
Here’s what you need to know:
- This area is the surface through which the fluid flows and is crucial for calculating flow velocity and the flow rate.
- The area in a channel is often determined by its width multiplied by the fluid height.
Pressure Force Calculation
Here's how it comes into play:
- Pressure forces depend not only on pressure differences but also on flow velocity changes and elevations in the fluid path.
- In fluid dynamics, especially when considering horizontal flow like in our exercise, it's critical to evaluate changes in kinetic and potential energy to find net force.