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Calculate the momentum-flux correction factor, \(\beta,\) for the following velocity distribution: $$ v(r)=V_{0}\left[1-\left(\frac{r}{R}\right)^{2}\right] $$ where \(v(r)\) is the velocity at a radial distance \(r\) from the centerline of a pipe of radius \(R\)

Short Answer

Expert verified
The momentum-flux correction factor \(\beta\) is \(\frac{8}{3}\).

Step by step solution

01

Understand the Velocity Distribution

The velocity distribution provided is: \(v(r)=V_{0}\left[1-\left(\frac{r}{R}\right)^{2}\right]\). This is the velocity at any point \(r\) within a pipe of radius \(R\). At the centerline (\(r=0\)), the velocity is maximum and equal to \(V_0\). As \(r\) approaches \(R\), the velocity decreases and becomes zero.
02

Define the Momentum-Flux Correction Factor, \(\beta\)

The momentum-flux correction factor, \(\beta\), is defined as the ratio of the actual momentum flux to the momentum flux calculated assuming a uniform velocity profile. It is given by:\[ \beta = \frac{\int_{0}^{R} v^2(r) \, 2 \pi r \, dr}{V_{m}^2 \cdot \pi R^2} \]where \(V_m\) is the mean velocity across the pipe section, defined as:\[ V_m = \frac{2}{R^2} \int_{0}^{R} v(r) \, r \, dr \]
03

Calculate Mean Velocity, \(V_m\)

We need to calculate \(V_m\) using the formula:\[ V_m = \frac{2}{R^2} \int_{0}^{R} V_0\left[1-\left(\frac{r}{R}\right)^{2}\right] r \, dr \]Calculating the integral:\[ \int_{0}^{R} \left[1-\left(\frac{r}{R}\right)^{2}\right] r \, dr = \left[ \frac{r^2}{2} - \frac{r^4}{4R^2} \right]_{0}^{R} \]Substitute the limits:\[ \frac{R^2}{2} - \frac{R^2}{4} = \frac{R^2}{4} \]Plug into the expression for \(V_m\):\[ V_m = \frac{2V_0}{R^2} \times \frac{R^2}{4} = \frac{V_0}{2} \]
04

Calculate Actual Momentum Flux

Calculate \(\int_{0}^{R} v^2(r) \, 2 \pi r \, dr\):\[ \int_{0}^{R} V_0^2 \left[1-\left(\frac{r}{R}\right)^{2}\right]^2 2 \pi r \, dr \]Expand and integrate:\[ = 2 \pi V_0^2 \int_{0}^{R} \left[1 - 2\left(\frac{r}{R}\right)^{2} + \left(\frac{r}{R}\right)^{4}\right] r \, dr \]Calculate separately:\[ \int_{0}^{R} r \, dr = \frac{R^2}{2}, \quad \int_{0}^{R} r^3 \, dr = \frac{R^4}{4}, \quad \int_{0}^{R} r^5 \, dr = \frac{R^6}{6} \]Substitute back:\[ = 2 \pi V_0^2 \left[ \frac{R^2}{2} - \frac{R^2}{2} + \frac{R^2}{6} \right] = 2 \pi V_0^2 \frac{R^2}{3} \]
05

Calculate \(\beta\)

Substitute the found values into the expression for \(\beta\):\[ \beta = \frac{2 \pi V_0^2 \frac{R^2}{3}}{\left(\frac{V_0}{2}\right)^2 \pi R^2} \]Simplify:\[ \beta = \frac{8}{3} \] This is the correction factor accounting for the non-uniform velocity distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Distribution
Velocity distribution in fluid dynamics refers to how the velocity of a fluid changes within a pipe or channel. In our context, the equation \(v(r)=V_{0}\left[1-\left(\frac{r}{R}\right)^{2}\right]\) expresses the velocity distribution inside a pipe of radius \(R\). Here, \(v(r)\) is the velocity at a radial distance \(r\) from the pipe's centerline, and \(V_0\) is the maximum velocity at the centerline. As \(r\) increases towards the pipe's edge, the velocity decreases until it reaches zero at \(r=R\). This distribution is parabola-shaped, indicating that fluid flows fastest at the center and slows down towards the edges, which is typical in laminar flow conditions.
Understanding velocity distribution helps in analyzing how fluid momentum varies within pipes, which is crucial for calculating factors like momentum flux and optimizing fluid transport.
Mean Velocity
Mean velocity, \(V_m\), is a representative average velocity of a fluid's flow across a section of a pipe. Calculating the mean velocity involves integrating the velocity distribution across the pipe's radius and dividing by the cross-sectional area. The formula is given by:
\[ V_m = \frac{2}{R^2} \int_{0}^{R} v(r) \, r \, dr \]
For our velocity distribution, this integral computes the area under the velocity curve, normalizing it to give a practical average velocity. By plugging into this formula, we find that:
\[ V_m = \frac{V_0}{2} \]
This result implies that the mean velocity of the fluid is half of the maximum velocity \(V_0\) found at the pipe's center. Knowing mean velocity is important for engineering applications as it allows for the prediction of flow rates and assists in designing efficient piping systems.
Momentum Flux
Momentum flux is the rate of momentum flow through a unit area of a cross-section in a fluid system. It is a key parameter for understanding the dynamics of fluid motion, especially in non-uniform velocity profiles. Calculating momentum flux involves integrating the square of the velocity across the cross-section of the pipe:\[ \int_{0}^{R} v^2(r) \, 2 \pi r \, dr \]In our scenario, this calculation considers the velocity distribution \(v(r)\) and provides insight into how momentum is carried by various parts of the fluid. The result helps derive the correction factor \(\beta\), which corrects for non-uniformities in fluid velocity, allowing us to account for the actual momentum as opposed to an idealized uniform distribution. Understanding momentum flux is crucial in optimizing transport processes and ensuring structural integrity in fluid systems.
Non-Uniform Velocity Profile
A non-uniform velocity profile indicates that the fluid flow across a pipe's cross-section is uneven. In our situation, the velocity profile \(v(r)=V_{0}\left[1-\left(\frac{r}{R}\right)^{2}\right]\) demonstrates how velocity varies from the maximum at the center to zero at the boundary, creating a parabolic shape. This non-uniformity is typical in laminar flows, where viscous forces are significant, causing variation in velocity layers within the fluid.
The momentum-flux correction factor \(\beta\) is introduced to address this non-uniform profile. It relates the true momentum flux to that predicted by assuming a uniform flow:\[ \beta = \frac{\int_{0}^{R} v^2(r) \, 2 \pi r \, dr}{V_{m}^2 \cdot \pi R^2} \]This factor, \(\frac{8}{3}\) in our case, corrects for velocity variations, enabling engineers to make more accurate predictions and designs in fluid systems. Recognizing and adjusting for non-uniform velocity profiles is vital for ensuring that systems perform effectively and safely under real-world conditions.

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Most popular questions from this chapter

Water is pumped from a lower reservoir to a higher reservoir using a pump that delivers \(30 \mathrm{~kW}\) of power. The elevation difference between the upper and lower reservoirs is \(15 \mathrm{~m}\), and the head loss in the pipeline is estimated as \(6 \mathrm{~m}\). Find the flow rate in the pipeline, the rate at which energy is lost from the system, and the fraction of input power that is lost.

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A rocket weighs \(6000 \mathrm{~kg}\), burns fuel at a rate of \(40 \mathrm{~kg} / \mathrm{s}\), and has an exhaust velocity of \(3000 \mathrm{~m} / \mathrm{s}\). Estimate the initial acceleration of the rocket and the velocity after 10 seconds. Neglect the drag force of the surrounding air and assume that the pressure of the exhaust gas is equal to the pressure of the surrounding atmosphere.

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