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A fluid particle follows a circular streamline that has a radius of \(2 \mathrm{~m}\). The magnitude of the velocity, \(V\), of a fluid particle on the streamline varies with time according to the relation \(V=(0.8+2.5 t) \mathrm{m} / \mathrm{s}\), where \(t\) is the time in seconds. What are the normal and tangential components of the acceleration of a fluid particle located on the streamline at \(t=3 \mathrm{~s}\) ?

Short Answer

Expert verified
Tangential acceleration is 2.5 m/s²; normal acceleration is 34.445 m/s².

Step by step solution

01

Understand the Problem

We need to find the normal and tangential components of the acceleration of a fluid particle that is moving in a circular path with radius \( r = 2 \text{ m} \), where the velocity \( V(t) = 0.8 + 2.5t \text{ m/s} \). The given time is \( t = 3 \text{ s} \).
02

Determine Tangential Component of Acceleration

The tangential component of acceleration \( a_t \) is the derivative of the velocity with respect to time. Given the velocity, \( V(t) = 0.8 + 2.5t \), the tangential acceleration \( a_t \) is the derivative of this velocity function with respect to time. Thus, \( a_t = \frac{dV}{dt} = 2.5 \text{ m/s}^2 \).
03

Calculate Velocity at \( t = 3 \text{ s} \)

Substitute \( t = 3 \text{ s} \) into the velocity equation to find the velocity at this time. \( V(3) = 0.8 + 2.5(3) = 0.8 + 7.5 = 8.3 \text{ m/s} \).
04

Determine Normal Component of Acceleration

The normal component of acceleration \( a_n \) for circular motion is given by \( a_n = \frac{V^2}{r} \). Substitute \( V = 8.3 \text{ m/s} \) and \( r = 2 \text{ m} \) into the equation: \( a_n = \frac{(8.3)^2}{2} = \frac{68.89}{2} = 34.445 \text{ m/s}^2 \).
05

Provide Final Numerical Answers

For a fluid particle located on the streamline at \( t = 3 \text{ s} \), the tangential component of acceleration is \( a_t = 2.5 \text{ m/s}^2 \), and the normal component of acceleration is \( a_n = 34.445 \text{ m/s}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
Circular motion refers to the movement of an object along the circumference of a circle. This can also include objects following a curved path, where the circle has a specific radius. In the context of fluid mechanics, circular motion is how a fluid particle flows along a streamline that forms a circle. The path has a definite radius, and the particle continuously travels in this circular path.

When dealing with circular motion, it's important to address the velocity of the object, as it moves around the circle. Unlike linear motion, in circular trajectory, even if the speed is constant, the direction is constantly changing. This introduces the concept of acceleration in a unique way, where it is split into different components.
Acceleration Components
In fluid mechanics, as with many other physics scenarios, the acceleration of a particle can be broken down into two primary components: tangential and normal. These components help in understanding how the particle accelerates as it travels in a circular path.

- **Tangential Acceleration**: This is parallel to the direction of velocity change and affects the speed of the particle. If the particle is speeding up or slowing down as it moves along the path, the tangential acceleration is involved. - **Normal (or Centripetal) Acceleration**: This is directed towards the center of the circle (perpendicular to the tangential direction) and affects the change in direction. It is a crucial factor in keeping the particle moving around the curve and not veering off.
Understanding these components is key in successfully maneuvering problems involving circular motion in fluid dynamics.
Tangential Acceleration
Tangential acceleration (\( a_t \)) in circular motion arises when there is a change in speed of the particle as it moves along the path. It does not deal with the change in direction but only changes in magnitude of the velocity.

Calculating tangential acceleration is relatively straightforward. It is the rate of change of velocity with respect to time. If the velocity function is given as a function of time, \( V(t) \), then the tangential acceleration can be computed by deriving the velocity function:\[a_t = \frac{dV}{dt}\]

In our exercise, where a fluid particle travels along a circular streamline, the tangential velocity function is given by \( V(t) = 0.8 + 2.5t \, \text{m/s} \).By taking the derivative, we find,\[a_t = 2.5 \, \text{m/s}^2\]At \( t = 3 \, \text{s} \), regardless of position on the circle, this value of \( a_t \) remains constant, showing that the particle is accelerating uniformly along its path.
Normal Acceleration
Normal acceleration, also known as centripetal acceleration, is crucial in maintaining circular motion. It is what keeps the fluid particle moving along its circular path. Unlike tangential acceleration, normal acceleration is directed towards the axis or center of the circle, essentially "pulling" the particle towards the circle's center.

To determine normal acceleration (\( a_n \)), we use the formula:\[a_n = \frac{V^2}{r}\]where \( V \) is the velocity of the particle at a particular time, and \( r \) is the radius of the circular path.

In the exercise, with \( r = 2 \, \text{m} \) and a velocity at \( t = 3 \, \text{s} \) as \( 8.3 \, \text{m/s} \), the normal acceleration can be calculated:\[a_n = \frac{(8.3)^2}{2} = 34.445 \, \text{m/s}^2\]

This large value of normal acceleration indicates the strong force keeping the particle on its curved path and also reflects how rapidly changes to the direction occur. It offers insights into the dynamics of the particle’s movement along the circular path.

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Most popular questions from this chapter

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