/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Consider the case in which fluid... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the case in which fluid of density \(\rho\) circulates around a central point such that the velocity, \(V\), at any distance \(r\) from the central point is given by $$ V=C r $$ where \(C\) is a constant. Note that the streamlines are circles and that \(V\) on each streamline is in the tangential direction. It is known that the pressure is equal to \(p_{0}\) at a distance \(r_{0}\) from the central point. Determine an expression for the pressure distribution in any horizontal plane in terms of \(r,\) where \(C, p_{0}, r_{0}\) are parameters of the pressure distribution.

Short Answer

Expert verified
The pressure distribution is \( p = p_0 + \frac{1}{2} \rho C^2 r_0^2 - \frac{1}{2} \rho C^2 r^2 \).

Step by step solution

01

Apply Bernoulli's Equation

Since the flow is circular and in a horizontal plane, Bernoulli's principle applies. We can write: \[ p + \frac{1}{2}\rho V^2 = p_0 + \frac{1}{2}\rho V_0^2 \]where \(V = C r\) and \(V_0 = C r_0\). This equation states that the sum of pressure energy and kinetic energy is constant along a streamline.
02

Substitute the Velocity Equation

Substitute the expressions for the velocities into Bernoulli's equation: \[ p + \frac{1}{2}\rho (C r)^2 = p_0 + \frac{1}{2}\rho (C r_0)^2 \]This step sets up the equation in terms of \(r\).
03

Simplify the Equation

Simplify the equation: \[ p + \frac{1}{2} \rho C^2 r^2 = p_0 + \frac{1}{2} \rho C^2 r_0^2 \]We can reorder the terms to solve for \(p\).
04

Solve for Pressure p

Isolate \(p\) on one side of the equation:\[ p = p_0 + \frac{1}{2} \rho C^2 r_0^2 - \frac{1}{2} \rho C^2 r^2 \]We now have our expression for the pressure \(p\) at any distance \(r\) from the central point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's Equation
Bernoulli's equation is a fundamental principle in fluid dynamics, describing the conservation of energy in a fluid flow situation. According to Bernoulli's equation, the total energy along a streamline remains constant. The equation is expressed as:
  • Pressure energy: \( p \)
  • Kinetic energy: \( \frac{1}{2}\rho V^2 \)
  • Potential energy, often omitted in horizontal flow: \( \rho gh \)
For the scenario where the flow is circular and in a horizontal plane, potential energy can be ignored, simplifying the equation to:\[ p + \frac{1}{2} \rho V^2 = \, \text{constant} \]This illustrates how changes in fluid speed affect pressure: as velocity increases, pressure decreases, and vice versa. In the example exercise, Bernoulli's equation helps us calculate the pressure distribution around the central point. The pressure difference between two points depends on the difference in their kinetic energy terms, reflecting velocity changes along the streamline.
Circular Streamlines
Circular streamlines occur in situations where fluid flows in a path that curves around a central point or axis. A streamline represents the trajectory followed by fluid particles in steady flow. In the problem at hand, the streamlines are perfect circles, each keeping the central point equidistant from any point on the streamlines.This is characterized by the velocity \( V = C r \), where \( r \) is the radius—distance from the central point—and \( C \) is a constant, representing a proportionality factor that relates to how velocity changes with distance from the center.
  • Velocity is always tangent to the streamline.
  • Each circular streamline has a unique, constant radius (\( r \)).
The tangential velocity suggests that while flowing around the circle, particles on different streamlines move at different speeds based on their distance \( r \) from the central point. The further from the center, the faster the flow, in this instance due to the equation \( V = Cr \). The circular motion also influences the pressure distribution in the fluid, as shown by the derivation using Bernoulli's equation.
Kinetic Energy in Fluid Flow
Kinetic energy in fluid flow refers to the energy due to the motion of the fluid particles. In the context of fluid dynamics, it is an essential component accounted for in Bernoulli's equation and is given by the term \( \frac{1}{2}\rho V^2 \).For the given problem, the kinetic energy component varies with the radius \( r \) from the central point. Since the velocity changes as \( V = C r \), the kinetic energy in each streamline becomes:
  • \( \frac{1}{2} \rho (C r)^2 \)
This makes kinetic energy directly proportional to the square of the radius:
  • Larger \( r \) means higher kinetic energy.
  • Higher speeds due to a larger radius enhance the kinetic energy component.
In this exercise, differences in kinetic energy at various radial distances contribute significantly to the variation in pressure along the circular streamlines. As velocity increases with distance, the increased kinetic energy results in a corresponding decrease in pressure, due to the energy balance described by Bernoulli’s principle.

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Most popular questions from this chapter

A three-dimensional velocity field is given by $$ \mathbf{v}=(3 z+2 y+2) \mathbf{i}+(2 x+z+1) \mathbf{j}+(3 x+y-1) \mathbf{k} $$ Determine the following: (a) the magnitude of the velocity at the origin, (b) the acceleration field, (c) the location of the stagnation point, and(d) the location where the acceleration is equal to zero.

A closed \(15-\mathrm{cm}\) -diameter cylindrical tank is filled with water and is rotated at \(600 \mathrm{rpm} .\) What is the maximum pressure difference between the center and the wall of the \(\operatorname{tank} ?\)

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Water at \(25^{\circ} \mathrm{C}\) flows through a \(1.5-\mathrm{m}\) section of a converging conduit in which the velocity, \(V\) (in \(\mathrm{m} / \mathrm{s}\) ), in the conduit increases linearly with distance, \(x\) (in \(\mathrm{m}\) ), from the entrance of the section according to the relation $$ V=1.5(1+0.5 x) \mathrm{m} / \mathrm{s} $$ The flow can be approximated as being inviscid. (a) Determine the pressure gradient as a function of \(x\) and determine the pressure difference across the \(1.5-\mathrm{m}\) section of conduit by integrating the pressure gradient. (b) Determine the pressure difference across the conduit using the Bernoulli equation and compare your result with that obtained in part (a).

The temperature, \(T,\) and the vertical component, \(w,\) of the wind velocity on the side of a very steep cliff are approximated by the relations $$ T(z, t)=20\left(1-0.3 z^{2}\right) \sin \left(\frac{\pi t}{6}\right){ }^{\circ} \mathrm{C}, \quad w=2.1\left(1+0.5 z^{2}\right) \mathrm{m} / \mathrm{s} $$ where \(z\) is the elevation above sea level in \(\mathrm{km}\) and \(t\) is the time in seconds. The horizontal components of the wind velocity are negligible along the cliff. Estimate the rate of change of temperature in the wind at \(z=1.2 \mathrm{~km}\) and \(t=5400 \mathrm{~s}(1.5 \mathrm{~h})\).

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