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A car manufacturer tests a full-scale car in a wind tunnel and uses a dynamometer to measure the drag force. The wind tunnel uses air at a temperature of \(15^{\circ} \mathrm{C}\) and a pressure of \(101.3 \mathrm{kPa}\), and the airspeed in the tunnel is \(95 \mathrm{~km} / \mathrm{h}\). The car has a frontal area of \(3.01 \mathrm{~m}^{2},\) and the measured drag force is \(310 \mathrm{~N}\). What is the drag coefficient of the car? If a properly scaled model of the car with a length scale ratio \(L_{\mathrm{r}}\) was tested instead of the full-scale version, what drag coefficient would you expect for the model?

Short Answer

Expert verified
The drag coefficient of the car is 0.330, and it remains the same for the scaled model.

Step by step solution

01

Convert Airspeed to Meters per Second

The airspeed given is in kilometers per hour (km/h). To use it in calculations, we should convert it to meters per second (m/s). Using the conversion factor, where 1 km/h = 0.27778 m/s, we find:\[u = 95 \text{ km/h} \times 0.27778 \text{ m/s/km/h} = 26.39 \text{ m/s}\]
02

Calculate Air Density

To calculate the air density (\(\rho\)), we can use the ideal gas law. The gas constant for air is approximately \(R = 287 \text{ J/(kg·K)}\). First convert temperature to Kelvin:\[T = 15^{\circ} \text{C} + 273.15 = 288.15 \text{ K}\]Then find the air density using the equation \(\rho = \frac{P}{R \cdot T}\):\[P = 101.3 \text{ kPa} = 101300 \text{ Pa}\]\[\rho = \frac{101300}{287 \times 288.15} = 1.225 \text{ kg/m}^3\]
03

Determine Drag Coefficient

The drag coefficient \(C_d\) can be found using the drag force equation:\[Fd = \frac{1}{2} \cdot C_d \cdot \rho \cdot A \cdot u^2\]Rearrange to solve for \(C_d\):\[C_d = \frac{2 \cdot Fd}{\rho \cdot A \cdot u^2} = \frac{2 \cdot 310}{1.225 \cdot 3.01 \cdot 26.39^2}\]\[C_d = 0.330\]
04

Expect the Same Drag Coefficient for Scaled Model

For a properly scaled model tested under the same dynamic similarity conditions (Reynolds number), the drag coefficient \(C_d\) will be the same as for the full-scale model. The drag coefficient is not affected by scaling. Therefore, the drag coefficient for the model is also:\[C_d = 0.330\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wind Tunnel Testing
Wind tunnel testing is a crucial method in aerodynamic evaluations for vehicles, airplanes, and even buildings. It allows engineers to study the effects of airflows in a controlled environment. During such tests, a full-size or scaled model is placed in a tunnel where controlled airflows simulate real-world conditions. This helps in assessing aerodynamic performance, including lift and drag forces. The wind tunnel replicates the airspeed and angle of airflow that an object would encounter in real life. This simulation assists in determining critical parameters such as the drag coefficient, which is a measure of how much drag an object experiences from air resistance. It's essential for understanding how designs affect fuel efficiency and overall performance. Wind tunnels can vary in size and complexity, accommodating anything from small-scale models to full-size vehicles.
Air Density Calculation
Calculating air density is a fundamental step in aerodynamic tests. It is an important factor influencing the drag force experienced by an object. Air density (\(\rho\)) can be determined using the ideal gas law, where atmospheric pressure (\(P\)), the air temperature (\(T\)), and a constant (\(R\), specific for air) come together. To calculate air density, first convert the temperature from Celsius to Kelvin, since Kelvin is the standard unit for thermodynamic temperature in physics. In this case, 15°C becomes 288.15K. Then, convert pressure from kilopascals to pascals. 101.3 kPa becomes 101300 Pa. These conversions are crucial as they make the units compatible. Air density is then calculated as \(\rho = \frac{P}{R \cdot T}\), where \(R = 287 \text{ J/(kg·K)}\). Understanding air density is essential for accurately predicting how air will interact with any structure subjected to aerodynamic forces.
Dynamic Similarity
Dynamic similarity is a concept vital in experiments that rely on scale models, such as those tested in wind tunnels. It implies that two objects can be considered dynamically similar if they have matching dimensionless parameters, mainly the Reynolds number. This means their flow conditions and behavior will be nearly identical, despite size differences. For example, when testing a scale model of a car, the wind tunnel conditions such as airspeed, viscosity, and model size are adjusted to achieve dynamic similarity with the full-scale car. This ensures that the test results are applicable to the real-world scenario, even though the model might be significantly smaller. Achieving dynamic similarity helps engineers predict the aerodynamic performance of the actual object by using tests conducted on its smaller likeness.
Reynolds Number
Reynolds number is a dimensionless value that helps predict flow patterns in different fluid flow situations. It is crucial in the study of aerodynamics and fluid mechanics as it indicates whether the flow will be laminar or turbulent. The Reynolds number is calculated using the formula \(Re = \frac{\rho \cdot u \cdot L}{\mu}\), where \(\rho\) is the fluid density, \(u\) is the flow velocity, \(L\) is a characteristic linear dimension (like an object's length), and \(\mu\) is the dynamic viscosity of the fluid. A high Reynolds number indicates turbulent flow, characterized by chaotic changes in pressure and velocity, while a low number suggests a smooth, laminar flow. In the context of wind tunnel testing, maintaining the same Reynolds number between a scale model and the full-sized object is key to ensuring that the aerodynamic tests are valid and relevant to real-world conditions.

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Most popular questions from this chapter

A prototype sports car has an engine that can deliver \(360 \mathrm{~kW}\) of power. The shape of the car is such that is has an estimated drag coefficient of 0.20 and a frontal area of \(2.50 \mathrm{~m}^{2}\). If the car is to be tested on a track at sea level under standard conditions, estimate the maximum possible speed the car can attain.

Experiments with a person who weighs \(833.6 \mathrm{~N}\) on a bicycle rolling freely down a \(5 \%\) incline show that the person-plus-bicycle attains a terminal speed of \(18 \mathrm{~m} / \mathrm{s}\). The frontal area of the person-plus-bicycle is \(0.6 \mathrm{~m}^{2},\) and the rolling resistance of the bicycle is negligible. Estimate the drag coefficient of the person-plus- bicycle combination. Assume standard air.

A model aircraft has a total wing area of \(6 \mathrm{~m}^{2}\). Based on experimental results from similar aircraft, it is estimated that the lift and drag coefficients are around 0.71 and 0.17 , respectively. It is intended that the model airplane fly at a speed of \(15 \mathrm{~m} / \mathrm{s}\) under standard sea-level conditions. (a) What is the maximum allowable weight of the airplane? (b) What is the power required to fly the airplane at its design speed?

Consider the general case in which a body of mass \(m\) and frontal area \(A\) free-falls in an environment where the effective gravity is \(g^{\prime},\) the density is \(\rho,\) and the drag coefficient of the body is constant and equal to \(C_{\mathrm{D}}\). Show that the time interval, \(\Delta t,\) for the velocity to change from \(V_{1}\) to \(V_{2}\) is given by $$ \Delta t=\frac{m}{2 \sqrt{a b}}\left[\ln \left|\frac{\sqrt{a}+\sqrt{b} V}{\sqrt{a}-\sqrt{b} V}\right|\right]_{V_{1}}^{V_{2}}, \quad \text { where } \quad a=m g^{\prime} \quad \text { and } \quad b=\frac{1}{2} \rho A C_{\mathrm{D}} $$ Explain how this formula could be used to calculate the time it takes a body dropped in the atmosphere to attain a speed equal to \(90 \%\) of its terminal speed.

Experiments on a car in a wind tunnel indicate that the drag coefficient of the car with all the windows up is 0.35 and that the drag coefficient with all the windows down is 0.45 . The car has a frontal area of \(3.0 \mathrm{~m}^{2}\). Consider the case where the car is driven at \(90 \mathrm{~km} / \mathrm{h}\) for a distance of \(205 \mathrm{~km}\), gasoline costs \(\$ 0.6604 / \mathrm{L}\), and the available energy from gasoline for overcoming aerodynamic drag is \(4.50 \mathrm{MJ} / \mathrm{kg}\). Estimate the additional gasoline cost incurred as a result of driving with the windows down. Assume standard air.

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