/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 A prototype sports car has an en... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A prototype sports car has an engine that can deliver \(360 \mathrm{~kW}\) of power. The shape of the car is such that is has an estimated drag coefficient of 0.20 and a frontal area of \(2.50 \mathrm{~m}^{2}\). If the car is to be tested on a track at sea level under standard conditions, estimate the maximum possible speed the car can attain.

Short Answer

Expert verified
The maximum possible speed of the car is approximately 385.88 km/h.

Step by step solution

01

Identify the given variables and physical constants

We are given the power output of the engine as \( P = 360 \text{ kW} = 360,000 \text{ W} \). The drag coefficient is given as \( C_d = 0.20 \), and the frontal area as \( A = 2.50 \text{ m}^2 \). We know the air density at sea level under standard conditions is approximately \( \rho = 1.225 \text{ kg/m}^3 \).
02

Recall the formula for drag force

The drag force \( F_d \) experienced by the car is given by the formula:\[ F_d = \frac{1}{2} C_d \rho A v^2 \]where \( v \) is the speed of the car.
03

Establish the relationship between power, force, and speed

The power output \( P \) of the engine is related to the drag force and speed by:\[ P = F_d \times v \]Substitute the expression for drag force:\[ P = \frac{1}{2} C_d \rho A v^3 \]
04

Solve for maximum speed

Rearrange the equation to solve for \( v \):\[ v^3 = \frac{2P}{C_d \rho A} \]\[ v = \left( \frac{2P}{C_d \rho A} \right)^{1/3} \]Substitute the known values:\[ v = \left( \frac{2 \times 360,000}{0.20 \times 1.225 \times 2.50} \right)^{1/3} \]
05

Calculate the numerical value for maximum speed

Perform the calculations:\[ v = \left( \frac{720,000}{0.20 \times 1.225 \times 2.50} \right)^{1/3} \]\[ v = \left( \frac{720,000}{0.6125} \right)^{1/3} \]\[ v = (1,175,102.04)^{1/3} \]\[ v ≈ 107.19 \text{ m/s} \]
06

Convert speed from m/s to km/h

To convert the speed from meters per second (m/s) to kilometers per hour (km/h), multiply by 3.6:\[ v ≈ 107.19 \text{ m/s} \times 3.6 = 385.88 \text{ km/h} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aerodynamic Drag
Aerodynamic drag is a crucial factor when considering the motion of vehicles, especially high-speed ones like a sports car. It refers to the resistance a vehicle encounters while moving through air. As a car speeds up, the air exerts a force against it, which opposes the car’s motion.
This resistance depends on several parameters:
  • The shape of the car, which affects how air flows around it.
  • The frontal area that comes into contact with the oncoming air.
  • The speed at which the car is traveling.
Think of aerodynamic drag as nature's way of slowing down the vehicle. Reducing it can significantly enhance a car's performance and fuel efficiency. Understanding this concept is key to optimizing vehicle dynamics and engineering designs for better speed and efficiency.
Drag Coefficient
The drag coefficient, denoted as \( C_d \), is a dimensionless number that represents a vehicle's aerodynamic efficiency. It acts as a measure of the car’s ability to slice through the air with minimal resistance.
A lower drag coefficient indicates a sleek design, allowing the vehicle to move with less effort against aerodynamic forces.
The typical values for a modern car range between 0.25 and 0.30, but high-performance cars often achieve even lower numbers, such as 0.20 in our exercise example. This value is predominantly determined by the car's shape and surface smoothness.
Optimizing the drag coefficient is an ongoing engineering challenge and directly impacts the car's top speed and overall fuel efficiency, making it a fundamental parameter in automotive design.
Power and Energy
Power and energy are essential concepts when discussing vehicle dynamics. Power, measured in watts (W), indicates the rate at which the engine does work or transfers energy to move the vehicle.
In our example, the sports car has an engine that outputs \(360 \text{ kW}\), reflecting its potential to overcome aerodynamic drag and maintain high speeds.
The formula \(P = F_d \times v\) links the engine's power to the car's speed and the opposing drag force. It shows that, for a given power output, reducing drag allows the vehicle to achieve higher speeds.
Ultimately, efficient power utilization is pivotal in achieving not only higher speeds but also greater energy conservation, influencing both performance and environmental impact.
Air Density
Air density, represented by \( \rho \), is a critical property of the atmosphere that affects aerodynamic drag. It's a measure of the mass of air per unit volume, typically in \(\text{kg/m}^3\).
At sea level and standard conditions, air density is about \(1.225 \text{ kg/m}^3\). This density affects how much drag force opposes a vehicle's movement, with denser air contributing to higher resistance.
Air density can vary due to altitude, temperature, and humidity changes. Higher altitudes generally result in lower densities, which would decrease aerodynamic drag and potentially allow for higher speeds.
Understanding how these factors impact drag helps engineers design vehicles for optimal performance in varying environmental conditions.
Vehicle Dynamics
Vehicle dynamics encompasses the many forces and motions acting on a car as it moves. This field explores how a vehicle responds to different inputs from the engine, road, driver, and environment.
Key aspects of vehicle dynamics include handling, acceleration, braking, and of course, drag. The interaction between these factors determines how well a vehicle performs and how comfortable it feels to the driver.
  • For example, understanding aerodynamic drag is essential for predicting and optimizing speed capabilities.
  • Power management is crucial for balancing acceleration with efficiency.
  • Drag coefficient and air density strongly affect how the vehicle handles under different speeds and conditions.
Overall, delving into vehicle dynamics allows for a more comprehensive approach to designing vehicles that are not only fast but also stable and efficient on the road.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An aircraft has a wing planform area of \(180 \mathrm{~m}^{2}\), an aspect ratio of \(7.5,\) a zero-lift drag coefficient of \(0.0185,\) and a weight of \(800 \mathrm{kN}\) when fully loaded. Estimate the speed of the aircraft that will minimize the required engine thrust when the aircraft is flying under standard sea-level atmospheric conditions.

Firing tests on a \(10-\mathrm{mm}\) -diameter bullet with a mass of \(20 \mathrm{~g}\) show that in standard air, the bullet speed decreases from \(300 \mathrm{~m} / \mathrm{s}\) to \(180 \mathrm{~m} / \mathrm{s}\) over a distance of \(200 \mathrm{~m}\). Estimate the average drag coefficient of the bullet. Neglect compressibility effects.

For aerial assaults, the armed forces of the United States generally use a T-10 parachute that has a nominal diameter of \(10.7 \mathrm{~m}\) when opened and a weight of \(14 \mathrm{~kg}\). The estimated drag coefficient of the T-10 parachute is equal to 1.4. Estimate the terminal velocity of an \(82-\mathrm{kg}\) person jumping with \(28 \mathrm{~kg}\) of gear (excluding the parachute) from a height \(350 \mathrm{~m}\) above ground. The average air density over the jump height can be taken as \(1.20 \mathrm{~kg} / \mathrm{m}^{3}\).

A small aircraft has a total wing area of \(30 \mathrm{~m}^{2},\) a lift coefficient of 0.45 at takeoff settings, and a total mass of \(2800 \mathrm{~kg}\). (a) Determine the takeoff speed in \(\mathrm{km} / \mathrm{h}\) of the aircraft at sea level under standard atmospheric conditions. (b) Determine the wing loading. (c) Determine the required power to maintain a constant cruising speed of \(300 \mathrm{~km} / \mathrm{h}\) for a cruising drag coefficient of \(0.035 .\) Assume standard air.

Experiments on a car in a wind tunnel indicate that the drag coefficient of the car with all the windows up is 0.35 and that the drag coefficient with all the windows down is 0.45 . The car has a frontal area of \(3.0 \mathrm{~m}^{2}\). Consider the case where the car is driven at \(90 \mathrm{~km} / \mathrm{h}\) for a distance of \(205 \mathrm{~km}\), gasoline costs \(\$ 0.6604 / \mathrm{L}\), and the available energy from gasoline for overcoming aerodynamic drag is \(4.50 \mathrm{MJ} / \mathrm{kg}\). Estimate the additional gasoline cost incurred as a result of driving with the windows down. Assume standard air.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.