/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 A jet plane flies at constant sp... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 2

A jet plane flies at constant speed in a vertical circular loop. At what point in the loop does the seat exert the greatest force on the pilot? The least force?

Short Answer

Expert verified
The greatest force is exerted on the pilot at the top of the loop where gravity and the centripetal force are both acting in the same direction, adding together. The least force is exerted at the bottom of the loop where gravity and the centripetal force work against each other, reducing the net force exerted on the pilot.

Step by step solution

01

Analyze the situation

In this problem, we have two forces at play, gravity and the force from circular motion. At the top of the loop, these forces add up, and at the bottom of the loop, they partially cancel out. The pilot feels the 鈥榝orce鈥� which includes the force of the seat pushing on the pilot (which provides the centripetal force necessary for circular motion) plus the weight of the pilot. This is the net force which is responsible for the circular motion.
02

Calculate force at the top of the loop

At the top of the loop, gravity and the centripetal force work in the same direction, causing a greater force to be exerted on the pilot. The net force acting on the pilot is the sum of the gravitational force and the centripetal force. This force is exerted upwards, towards the centre of the loop.
03

Calculate force at the bottom of the loop

At the bottom of the circle, gravity and the centripetal force work in opposite directions. The net force acting on the pilot is the difference between the centripetal force and the gravitational force. This force is also directed upwards, towards the centre of the loop.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In cross-country skiing, skis should easily glide forward but should remain at rest when the skier pushes back against the snow. What frictional properties should the ski wax have to achieve this goal?

Two unfortunate climbers, roped together, are sliding freely down an icy mountainside. The upper climber (mass \(80 \mathrm{~kg}\) ) is on a slope at \(16^{\circ}\) to the horizontal, but the lower climber (mass \(65 \mathrm{~kg}\) ) has gone over the edge to a steeper slope at \(32^{\circ}\). (a) Assuming frictionless ice and a massless rope, what's the acceleration of the pair? (b) The upper climber manages to stop the slide with an ice ax. After the climbers have come to a complete stop, what force must the ax exert against the ice?

In a loop-the-loop roller coaster, show that a car moving too slowly would leave the track at an angle \(\phi\) given by \(\cos \phi=\mathrm{v}^{2} / r g\), where \(\phi\) is the angle made by a vertical line through the center of the circular track and a line from the center to the point where the car leaves the track.

Moving through a liquid, an object of mass \(m\) experiences a resisCH tive drag force proportional to its velocity, \(F_{\text {frag }}=-b v\), where \(b\) is a constant. (a) Find an expression for the object's speed as a function of time, when it starts from rest and falls vertically through the liquid. (b) Show that it reaches a terminal velocity \(m g / b\).

Example 5.7: A roller-coaster car is going at \(17.7 \mathrm{~m} / \mathrm{s}\) as it passes through the top of the loop-the-loop section of the "Full Throttle" roller coaster, where the curvature radius is \(19.5 \mathrm{~m}\). What are the magnitude and direction normal force that the car's seat exerts on a \(72.1-\mathrm{kg}\) passenger at the top of the loop?
See all solutions

Recommended explanations on Physics Textbooks

Further Mechanics and Thermal Physics

Read Explanation

Oscillations

Read Explanation

Medical Physics

Read Explanation

Circular Motion and Gravitation

Read Explanation

Solid State Physics

Read Explanation

Kinematics Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.