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What force is necessary to stretch a spring \(48 \mathrm{cm},\) if its spring constant is \(270 \mathrm{N} / \mathrm{m} ?\)

Short Answer

Expert verified
The force necessary to stretch the spring is \(129.6 N\).

Step by step solution

01

Identify the given values

The given values are the spring constant (k) which is \(270 N/m\), and the displacement or stretched distance (x), which is \(48 cm\). Note, however, that k is given in terms of meters, therefore x also needs to be in meters. This implies that we will need to convert it to meters from centimeters.
02

Convert centimeters to meters

We know that 1 meter equals 100 centimeters. So, to convert 48 centimeters into meters, divide 48 by 100. This gives us \(0.48m\).
03

Apply Hooke's Law

Now that we have the required values, we will apply Hooke's Law formula which is \(F = k*x\). Putting the values in the equation we get \(F = 270N/m * 0.48m\).
04

Calculate Force

Multiply 270 with 0.48 to get the force. The result is \(129.6 N\). Therefore, a force of \(129.6 N\) is needed to stretch the spring by \(48 cm\).

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