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You're an engineer working on Ares I, NASA's replacement for the space shuttles. Performance specs call for a first-stage rocket capable of accelerating a total mass of 630 Mg vertically from rest to \(7200 \mathrm{km} / \mathrm{h}\) in 2.0 min. You're asked to determine the required engine thrust (force) and the force exerted on a \(75-\mathrm{kg}\) astronaut during liftoff. What do you report?

Short Answer

Expert verified
The required engine thrust (force) needed for the liftoff is \(1.06 * 10^{10} N\) and the force exerted on a 75-kg astronaut during liftoff is approximately 1997.25 N.

Step by step solution

01

Convert the Given Units to SI Units

First convert the speed from km/h to m/s by using the converter 1 km/h = \(0.28 m/s\) and time from minutes to seconds. So, the speed changes to \(7200 km/h * 1 km/h = 2020 m/s\) and time changes to \(2 min * 60s/min = 120 s\).
02

Calculating Acceleration

The acceleration \(a\) can be calculated by final velocity divided by time, \(a = \frac{\Delta v}{\Delta t} = \frac{2020 m/s}{120s} = 16.83 m/s^2\).
03

Determining Thrust

By Newton's second law, since Force = mass x acceleration, the thrust \(F\) required can be calculated by \(F (Thrust) = m (total mass) * a\). Substituting values, we get \(F (Thrust) = (630 * 10^6g) * 16.83 m/s^2 = 1.06 * 10^10 N\). Here, note that 1 Mg = \(10^6 g\)
04

Calculating Force Exerted on Astronaut

This force is the sum of the force due to gravity and the force due to acceleration experienced. Force due to gravity = Astronaut's mass x g (where g = 9.8m/s^2). So force due to gravity = 75 kg * 9.8 m/s^2 = 735N. Force due to acceleration = Astronaut's mass * acceleration computed above = 75 kg * 16.83 m/s^2 = 1262.25 N. The total force experienced by the astronaut = force due to gravity + force due to acceleration = 735N + 1262.25 N = 1997.25 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rocket Thrust Calculation
When engineers like those working on the Ares I rocket need to calculate the thrust required for a rocket to achieve a certain speed, they rely on physics principles anchored by Newton's second law of motion. This law states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration (\( F = m \times a \)). In the context of a rocket launch, 'thrust' refers to the force that propels a rocket upward against the pull of gravity.

To compute the thrust needed for a rocket, we must first understand the desired outcome; for the Ares I, it's to reach a velocity of 2020 m/s from rest within 120 seconds. The total mass of the rocket is given as 630 Mg, which must be converted to kilograms (630,000 kg) that calculation involves establishing the acceleration required to reach the target velocity in the defined time frame, which was done using the formula for acceleration (\( a = \frac{\triangle v}{\triangle t} \)).

Once we know the acceleration, we use Newton's second law to determine the thrust. By multiplying the total mass of the rocket by the acceleration, we get the thrust required to achieve the desired speed. It's critical to ensure all units are consistent, which is why mass was converted from Mg to kilograms (kg) and gravimetric units to the SI unit of force, Newtons (N). By adhering to these unit conversions and calculations, engineers can make precise thrust estimations necessary for a successful launch.
Acceleration Calculation
Acceleration is a measure of how quickly an object changes its velocity. In order to calculate acceleration during a rocket's liftoff, we need to know the change in velocity and the time frame over which this change occurs. The formula used is remarkably simple: \( a = \frac{\triangle v}{\triangle t} \), where \( \triangle v \) is the change in velocity and \( \triangle t \) is the time it takes for that change.

For the Ares I rocket, we define 'from rest' as an initial velocity of 0 m/s, and the rocket must reach a final velocity of 2020 m/s. The change in velocity here is straightforward: 2020 m/s - 0 m/s. The time frame given is 2.0 minutes, which converts to 120 seconds. Using these values, the acceleration calculation is a clear application of the formula, resulting in an acceleration of 16.83 m/s².

Understanding acceleration is crucial for both determining the required thrust for the rocket and evaluating the forces that will be exerted on objects inside the rocket, such as astronauts. By mastering acceleration calculations and consistently using SI units, complex motions in rocketry can be effectively planned and analyzed.
Force Exerted on Astronaut
During liftoff, astronauts experience significant forces due to the acceleration of the rocket and the force of Earth's gravity. To determine the total force exerted on an astronaut, we need to calculate two distinct components: the force due to gravity (often called 'weight') and the force due to acceleration.

The force due to gravity is calculated using the formula: \( F_{gravity} = m \times g \), where \( m \) is the mass of the astronaut, and \( g \) is the acceleration due to gravity (9.8 m/s² on Earth). For an astronaut with a mass of 75 kg, this results in a gravitational force of 735 N. However, during liftoff, the astronaut is also subjected to the force of the rocket's acceleration, calculated by multiplying the astronaut's mass by the rocket's acceleration (\( F_{acceleration} = m \times a \)).

For our astronaut in the Ares I, the acceleration has already been established at 16.83 m/s². Therefore, the force due to acceleration would be 1262.25 N. The total force experienced by the astronaut is the sum of these two forces, resulting in approximately 1997.25 N. This force affects how astronauts train for the physical stresses of launch and how engineers design safety measures and restraints within the spacecraft to safeguard astronauts' well-being during the intense acceleration of liftoff.

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Most popular questions from this chapter

You're asked to calibrate a device used to measure vertical acceleration in helicopters. The device consists of a mass \(m\) hanging from a massless spring of constant \(k .\) Your job is to express the acceleration as a function of the position \(y\) of the mass relative to where it is when there's no acceleration. Take the positive \(y\) -axis to point upward.

At 560 metric tons, the Airbus \(A-380\) is the world's largest airliner. What's the upward force on an \(A-380\) when the plane is (a) flying at constant altitude and (b) accelerating upward at \(1.1 \mathrm{m} / \mathrm{s}^{2} ?\)

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Although we usually write Newton's second law for one-dimensional motion in the form \(F=m a\), which holds when mass is constant, a more fundamental version is \(F=\frac{d(m v)}{d t} .\) Consider an object whose mass is changing, and use the product rule for derivatives to show that Newton's law then takes the form \(F=m a+v \frac{d m}{d t}\).

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