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Chapter 36: Problem 28

Use shell notation to characterize rubidium's outermost electron.

Short Answer

Expert verified
The outermost electron of rubidium is characterized as [Kr]5s^1 in shell notation.

Step by step solution

01

Find the Atomic Number

Look up the atomic number of rubidium on the periodic table. The atomic number is equal to the number of electrons in an atom. Its atomic number is 37, meaning that a neutral rubidium atom has 37 electrons.
02

Determine the Electron Configuration

The electron configuration is determined by the Aufbau principle which states that electrons occupy the lowest energy level first. So, rubidium's electron configuration will be \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1\)
03

Identify the Outermost Electron

The outermost electron is the electron in the highest energy level. In the electron configuration of rubidium, that would be 5s. Using shell notation, this is usually written as [Kr]5s^1 as Krypton has the electron configuration of all other orbitals besides the last one.

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