Chapter 26: Problem 12
Why is a piece of iron attracted into a solenoid?
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Chapter 26: Problem 12
Why is a piece of iron attracted into a solenoid?
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The Biot-Savart law shows that the magnetic field of a current element decreases as \(1 / r^{2} .\) Could you put together a complete circuit whose field exhibits this decrease? Why or why not?
A proton moving with velocity \(\vec{v}_{1}=3.6 \times 10^{4} \hat{\jmath} \mathrm{m} / \mathrm{s}\) experiences a magnetic force of \(7.4 \times 10^{-16} \hat{\imath} \mathrm{N} .\) A second proton moving on the \(x\) -axis experiences a magnetic force of \(2.8 \times 10^{-16} \hat{\jmath} \mathrm{N}\). Find the magnitude and direction of the magnetic field (assumed uniform), and the velocity of the second proton.
Number 12 gauge wire, commonly used in household wiring, is \(2.053 \mathrm{mm}\) in diameter and can safely carry currents of up to 20.0 A. For a wire carrying this maximum current, find the magnetic field strength (a) \(0.150 \mathrm{mm}\) from the wire's axis, (b) at the wire's surface, and (c) 0.375 mm beyond the wire's surface.
Find an expression for the magnetic field at the center of a square loop of side \(a\) carrying current \(I\).
A wire carrying 15 A makes a \(25^{\circ}\) angle with a uniform magnetic field. The magnetic force per unit length of wire is \(0.31 \mathrm{N} / \mathrm{m}\) Find (a) the magnetic field strength and (b) the maximum force per unit length that could be achieved by reorienting the wire.
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