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The 30 -kg spool of outer radius \(r_{o}=450 \mathrm{mm}\) has a centroidal radius of gyration \(\bar{k}=275 \mathrm{mm}\) and a central shaft of radius \(r_{i}=200 \mathrm{mm} .\) The spool is at rest on the incline when a tension \(T=300 \mathrm{N}\) is applied to the end of a cable which is wrapped securely around the central shaft as shown. Determine the acceleration of the spool center \(G\) and the magnitude and direction of the friction force acting at the interface of the spool and incline. The friction coefficients there are \(\mu_{s}=0.45\) and \(\mu_{k}=0.30 .\) The tension \(T\) is applied parallel to the incline and the angle \(\theta=20^{\circ}\)

Short Answer

Expert verified
Acceleration, \( a = 3.18 \, \text{m/s}^2 \). Friction, \( f = 32.7 \, \text{N} \), acting up the incline.

Step by step solution

01

Identify the forces

Consider all the forces acting on the spool: tension \( T \), gravitational force \( mg \), frictional force \( f \), and the normal force. The gravitational force can be broken into components parallel and perpendicular to the incline.
02

Apply Newton's second law parallel to incline

The equation for the net force parallel to the incline is \( T - mg\sin\theta - f = ma \), where \( a \) is the linear acceleration of the center of the spool \( G \).
03

Apply Newton's second law for rotation

Using the formula for rotational motion, \( T r_i - f r_o = I\alpha \), where \( I = m \bar{k}^2 \) is the moment of inertia and \( \alpha \) is angular acceleration. Since \( a = r_i \alpha \), substitute \( \alpha = \frac{a}{r_i} \) into the equation.
04

Solve for spool's linear acceleration

Substituting \( \alpha \) and \( I \) into the rotational equation gives \( T r_i - f r_o = m \bar{k}^2 \frac{a}{r_i} \). Solve this together with the linear motion equation to find \( a \). Substitute back the known values: \( T = 300 \,\text{N} \), \( r_i = 0.2 \,\text{m} \), \( r_o = 0.45 \,\text{m} \), \( m = 30 \,\text{kg} \), \( \bar{k} = 0.275 \,\text{m} \), \( \theta = 20^\circ \), \( g = 9.81 \,\text{m/s}^2 \).
05

Determine magnitude and direction of friction

With \( a \) calculated, substitute back into \( f = T - mg\sin\theta - ma \) to find \( f \). Check if this is less than \( \mu_k m g\cos\theta \). Direction is opposite to motion.
06

Substitute values and calculate

Using the values and previously found equations:- From rotational motion: \( 0.2T - 0.45f = 30 \times 0.275^2 \times \frac{a}{0.2} \)- From linear motion: \( T - 30\times 9.81 \times \sin(20) - f = 30a \)Solve these equations simultaneously to obtain the acceleration \( a \) and the friction force \( f \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's second law is fundamental to understanding how forces affect motion. It states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass, expressed by the formula: \( F = ma \).
For the spool on an incline, we calculate two different types of acceleration: linear and angular. The linear acceleration is associated with the center of mass moving down the incline.
The net force can include gravity, friction, and tension. For our spool, these forces combine according to the equation:
  • Parallel component of gravitational force, \( mg \sin \theta \)
  • Tension in the cable, \( T \)
  • Friction force, \( f \)
By balancing these forces, we derive a formula that links them to the spool’s linear acceleration along the incline.
This is a practical application of how Newton's second law is used to compute the acceleration when multiple forces work along a plane.
Rotational Motion
Rotational motion concerns objects rotating around an axis. The spool's central shaft, wrapped with a cable exerting tension, generates a torque. The torque causes angular acceleration. For rotational motion, we use Newton's second law for rotation, \( \, \tau = I\alpha \) where:
  • \( \tau \) is torque, caused by tension \( T \) and friction \( f \)
  • \( I \) is the moment of inertia, which reflects the spool's resistance to rotation
  • \( \alpha \) is angular acceleration
The formulas relating to rotational motion here are:
  • \( Tr_i - fr_o = I\alpha \)
This equation relates linear and rotational motion. By linking the linear acceleration \( a \) to the angular acceleration \( \alpha \) through the radius of the central shaft \( r_i \), we determine how forces applied at different points on a rotating body affect its acceleration. This showcases the interdependence in the dynamics of rotating objects.
Friction Force
Friction force opposes the motion or tendency of motion between two surfaces in contact. It's crucial in dynamics, influencing how objects move on surfaces.
There are two key types of friction: static and kinetic. Static friction prevents a stationary object from moving, while kinetic friction acts on moving objects. The friction force is pivotal in the problem of the spool:
To compute it:
  • First, we need to solve for acceleration
  • The equation \( f = T - mg\sin\theta - ma \) helps trace the friction force
This friction force calculation ensures it doesn't exceed the maximum static friction \( \mu_s mg\cos\theta \), maintaining grip on the surface. This step guarantees the proper analysis to predict if the spool will slide or roll smoothly down the incline.
Moment of Inertia
The moment of inertia is a measure of an object's resistance to changes in its rotation. It is akin to mass in linear motion but applies to rotational motion, reflecting how mass is distributed relative to the axis of rotation.
The formula for a solid object is \( I = m\bar{k}^2 \), where \( \bar{k} \) is the radius of gyration, a simplified measure indicating a uniform distribution of mass.
In our spool problem:
  • Calculate the moment of inertia to understand how the spool resists rotational change
  • This characteristic affects how quickly the spool can accelerate when a torque is applied
The moment of inertia plays a critical role when applying Newton's second law to rotational dynamics. It helps find the relationship between applied forces, spool acceleration, and the torque generated by the tension and friction forces.

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