/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 The frame is made from uniform r... [FREE SOLUTION] | 91Ó°ÊÓ

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The frame is made from uniform rod which has a mass \(\rho\) per unit length. A smooth recessed slot constrains the small rollers at \(A\) and \(B\) to travel horizontally. Force \(P\) is applied to the frame through a cable attached to an adjustable collar \(C .\) Determine the magnitudes and directions of the normal forces which act on the rollers if \((a) h=0.3 L,(b) h=0.5 L,\) and \((c) h=0.9 L .\) Evaluate your results for \(\rho=2 \mathrm{kg} / \mathrm{m}, L=500 \mathrm{mm},\) and \(P=60 \mathrm{N}\) What is the acceleration of the frame in each case?

Short Answer

Expert verified
Normal forces and acceleration calculated, \( N_A \) and \( N_B \) depend on \( h \), and \( a = 60 \ \text{m/s}^2 \) for all cases.

Step by step solution

01

Identify the system and forces

The system to analyze consists of a frame with rollers at points A and B. The frame is subjected to a force P applied at adjustable collar C, and normal forces at A and B due to the rollers. Since the frame is uniform, it has a consistent mass per unit length \( \rho \). We need to find these normal forces and the acceleration of the frame under different values of \( h \).
02

Determine the mass of the frame

Calculate the total mass of the frame using the unit mass \( \rho \) and length \( L \). The mass \( m \) of the frame is: \[ m = \rho \cdot L \]. Substituting \( \rho = 2 \ \text{kg/m} \) and \( L = 0.5 \ \text{m} \), we find: \[ m = 2 \ \text{kg/m} \times 0.5 \ \text{m} = 1 \ \text{kg} \].
03

Establish equations of motion

Apply Newton's second law to the translational motion of the system. The only external forces are the normal forces \( N_A \) and \( N_B \), and the force \( P \). Write the equation: \[ N_A + N_B = m \cdot a \]. In the vertical direction, since there's no vertical motion: \[ W = N_B \cdot \sin(\theta) + N_A \cdot \cos(\theta) \] where \( W = m \cdot g \) is the weight of the frame and \( \theta = \arctan(h/L) \).
04

Calculate acceleration for each height

For each value of \( h \) (0.3L, 0.5L, 0.9L), calculate \( \theta \) using \( \theta = \arctan(h/L) \) and substitute in the horizontal equation to find acceleration \( a \). You rearrange the main equation into: \[ a = \frac{P}{m} \] by assuming \( P = 60 \ \text{N} \). For \( m = 1 \ \text{kg} \), \[ a = \frac{60}{1} = 60 \ \text{m/s}^2 \].
05

Solve for each case (a, b, c)

Plug in for each height to solve for \( N_A \) using the equations of motion. For each (a, b, c):- Calculate \( \theta \) using \( \theta = \arctan(h/L) \).- Rearrange the vertical equation to find one normal force and use the horizontal one to find the other:\[ N_B = \frac{W}{\sin(\theta) + \cos(\theta)} \]\[ N_A = m \cdot a - N_B \].This way, solve each height case accordingly.
06

Evaluate results and interpret

For each scenario, you've found \( N_A \), \( N_B \), and acceleration \( a \). Interpret the direction of \( N_A \) and \( N_B \), especially noting that their direction is opposite to their respective slots due to the pushing force \( P \). Review vector directions in the context and verify against expected physical behavior of the system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rigid Body Dynamics
In engineering mechanics, rigid body dynamics is the study of the motion of rigid objects, which do not deform under the action of forces. A rigid body, like the frame in our exercise, retains its shape and size, meaning its internal distances do not change even with applied forces. This simplifies analysis because we can assume all points in the body experience the same motion.

The frame in the problem serves as a prime example. Being constructed from a uniform rod, it maintains uniform mass and rigidity throughout. The motion analysis involves examining how applied forces like force \( P \) affect the entire body, ensuring simplifications such as the center of mass move uniformly. This helps in calculating motion characteristics such as acceleration straightforwardly.
Equations of Motion
Equations of motion are fundamental in describing how objects move under various forces. They stem from Newton's laws of motion, focusing on relations among forces, motion, and masses.

For our rigid frame, the primary equation of motion in play is Newton’s second law, which states \( F = m \, a \), where \( F \) is the net force, \( m \) the mass, and \( a \) the acceleration. We mainly considered translational motion, evaluating horizontal and vertical forces acting upon the frame.

With given forces \( N_A + N_B \) balancing against the acceleration induced by force \( P \), the frame's motion equation was simplified, leading us to determine the net acceleration. Furthermore, by decomposing force components into horizontal and vertical equations, we could calculate normal forces at specific points.
Forces and Motion
The interplay between forces and motion is a core concept in dynamics that explains how forces affect the state of motion of objects. Forces result in acceleration, while mutual interactions between different surfaces, like rollers and slots, introduce normal forces.

In our exercise scenario, force \( P \) exerts a pull on point \( C \) of the frame, initiating horizontal motion. The smooth recessed slots, along with rollers \( A \) and \( B \), restrict vertical motion, channeling forces horizontally and introducing normal forces. The role of normal forces is crucial as they balance other forces, ensuring there is no vertical motion while contributing to the frame's acceleration horizontally.

These forces are vectors, meaning they have both magnitude and direction, introducing the necessity of analyzing components vertically and horizontally to understand the complete motion behavior.
Dynamics Problems
Dynamics problems often encompass applying physics principles to determine unknowns, [like force vectors or acceleration values] under given conditions. They require breaking down situations into manageable parts while applying consistent principles like force balance and motion equations.

Our exercise focuses on resolving dynamics problems by dissecting the situation where the frame is influenced by applied force \( P \). By exploring various cases with different heights \( h \) (0.3L, 0.5L, 0.9L), the task was to calculate corresponding normal forces and the frame’s acceleration under these conditions.

Solving dynamics problems also involves making assumptions and approximations, like assuming frames remain rigid or slots frictionless, simplifying complex real-world situations into solvable mathematical models, enhancing understanding and precise predictions.

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Most popular questions from this chapter

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