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A model rocket weighs 1.5 lb just before its vertical launch. Its experimental solid-fuel motor carries 0.1 lb of fuel, has an escape velocity of 3000 ft/sec, and burns the fuel for 0.9 sec. Determine the acceleration of the rocket at launch and its burnout velocity. Neglect aerodynamic drag and state any other assumptions.

Short Answer

Expert verified
Initial acceleration: 7.89 ft/s², Burnout velocity: 214.84 ft/s.

Step by step solution

01

Understanding the System

The total initial weight of the rocket is 1.5 lb, out of which 0.1 lb is fuel. The rocket launches vertically, and we need to find the initial acceleration and the final velocity of the rocket after the fuel is burnt out.
02

Assumptions

We assume that the only forces acting on the rocket are gravity and the thrust from the fuel being exhausted. Aerodynamic drag is neglected as mentioned in the problem. The rocket is launched from the surface of the Earth.
03

Compute Initial Acceleration Using Thrust Equation

The thrust generated by the rocket motor can be calculated using the formula for momentum: \(F = v_{e} \cdot \frac{dm}{dt}\), where \(v_{e}\) is the effective exhaust velocity (3000 ft/s), and \(\frac{dm}{dt}\) is the rate of change of mass (fuel burn rate \(\frac{0.1}{0.9}\, \text{lb/s}\)).\[F = 3000 \times \frac{0.1}{0.9} = 333.33\, \text{lb-ft/s}\]
04

Calculate the Weight Force

The weight force of the rocket is \(W = m \cdot g\). Here \(m\) is the mass of the rocket, and \(g\) is the acceleration due to gravity (32.2 ft/s²). Convert the rocket weight to a mass in slugs using \(m = \frac{1.5}{32.2} \).
05

Initial Acceleration Calculation

Apply Newton's second law of motion, \(F - W = m \cdot a\), to find the initial acceleration (\(a\)).\[a = \frac{F - W}{m} = \frac{333.33 - 48.44}{\frac{1.5}{32.2}} = 7.89\, \text{ft/s}^2\]
06

Burnout Velocity Calculation

The burnout velocity can be calculated using the rocket equation: \(v = v_{0} + v_{e} \cdot \ln\left(\frac{m_{0}}{m_{f}}\right)\), where \(v_{0}\) is the initial velocity (0 ft/s), \(m_{0}\) is the initial mass, and \(m_{f}\) is the final mass.\[v = 0 + 3000 \cdot \ln\left(\frac{1.5}{1.4}\right) = 214.84\, \text{ft/s} \]
07

Conclude Calculations

Summarize the findings: The initial acceleration of the rocket at launch is approximately 7.89 ft/s², and the burnout velocity is 214.84 ft/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thrust Calculation
When calculating the thrust of a rocket, we are essentially looking at the force generated by the expulsion of fuel. This force is what propels the rocket upward. The thrust (\( F \)) can be determined using the equation for momentum:
  • \( F = v_{e} \cdot \frac{dm}{dt} \)
Here,\( v_{e} \) stands for the effective exhaust velocity, and \( \frac{dm}{dt} \) is the rate of change of mass, or the fuel burn rate. In the case of our model rocket, the effective exhaust velocity is 3000 ft/s, making it quite fast. The burn rate is found using the total fuel weight and the burn time, which is\( \frac{0.1}{0.9} \) lb/s.
Combining these values, we get the thrust as333.33 lb-ft/s, illustrating the rocket's strong propulsion capability against gravity.
Newton's Second Law
Newton's Second Law of Motion is a cornerstone principle for understanding how objects move. It tells us how the motion of an object changes when it is subjected to a force. For rockets, the law can be expressed with the formula:
  • \( F - W = m \cdot a \)
Where \( F \) is the thrust force, \( W \) is the weight force due to gravity, \( m \) is the mass, and \( a \) is the resulting acceleration.
In this particular rocket problem, we use this equation to calculate the initial acceleration. First, we determine the weight force, \( W \), as the product of the mass (converted from weight to slugs, using \( \frac{1.5}{32.2} \) for conversion) and gravity (32.2 ft/s²). After knowing \( F \) and \( W \), we plug these into our equation.
This calculation provides us with an initial acceleration of 7.89 ft/s², illustrating how much faster each second the rocket accelerates upwards upon launch.
Rocket Propulsion
Rocket propulsion is what drives a rocket forward by expelling gas at high speeds in the opposite direction. This uses the principle of action and reaction. The force of the expelled fuel (action) creates an equal and opposite force (reaction) on the rocket body, propelling it skyward. The expelled fuel, moving at a high velocity creates the rocket's thrust, which is critical for overcoming gravitational forces and gaining height.
Key factors in efficient propulsion include:
  • Fuel burn rate - how quickly fuel is consumed dramatically affects the thrust.
  • Exhaust velocity - higher velocities improve thrust efficiency.
  • Rocket mass - the lighter the rocket, the less force required to accelerate it.
Understanding these factors helps in designing efficient rockets, whether they are tiny model rockets or massive spacefaring vehicles.
Acceleration and Velocity
Acceleration and velocity are two fundamental aspects of the rocket's motion.
Accurately calculating these can show how fast a rocket is traveling at any moment (velocity) and how fast it's speeding up (acceleration). The rocket in this scenario starts its journey from rest, hence an initial velocity (\( v_{0} = 0 \) ft/s). As the rocket climbs, it continuously accelerates due to the thrust overpowering gravitational pull.
By applying the rocket propulsion equation:
  • \( v = v_{0} + v_{e} \cdot \ln\left(\frac{m_{0}}{m_{f}}\right) \)
where \( m_{0} \) is the initial mass including fuel, and \( m_{f} \) is the mass after fuel burnout, we find the burnout velocity to be214.84 ft/s. This gives us an idea of how fast the rocket is moving right when it runs out of fuel.
Understanding these dynamics is essential for predicting a rocket's path and performance efficiently.

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