/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 81 A railroad coal car weighs 54,60... [FREE SOLUTION] | 91Ó°ÊÓ

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A railroad coal car weighs 54,600 lb empty and carries a total load of 180,000 lb of coal. The bins are equipped with bottom doors which permit discharging coal through an opening between the rails. If the car dumps coal at the rate of \(20,000 \mathrm{lb} / \mathrm{sec}\) in a downward direction relative to the car, and if frictional resistance to motion is 4 lb per ton of total remaining weight, determine the coupler force \(P\) required to give the car an acceleration of \(0.15 \mathrm{ft} / \mathrm{sec}^{2}\) in the direction of \(P\) at the instant when half the coal has been dumped.

Short Answer

Expert verified
The coupler force required is approximately 963.13 lb.

Step by step solution

01

Calculate the Remaining Coal

The total load of coal is 180,000 lb. When half of it is dumped, the remaining coal is \[ 0.5 \times 180,000 = 90,000 \, \text{lb} \]
02

Calculate Total Remaining Weight

Sum the weight of the empty car and the remaining coal weight:\[ 54,600 \, \text{lb} + 90,000 \, \text{lb} = 144,600 \, \text{lb} \]
03

Calculate Frictional Resistance

Find the frictional resistance based on the remaining weight. First, convert total weight to tons (1 ton = 2,000 lb): \[ \frac{144,600 \, \text{lb}}{2,000 \, \text{lb/ton}} = 72.3 \, \text{tons} \]The frictional force is then \[ 72.3 \, \text{tons} \times 4 \, \text{lb/ton} = 289.2 \, \text{lb} \]
04

Calculate Inertial Force Required for Acceleration

Use Newton's second law to find the inertial force:\[ F = ma \]where mass \( m \) is the total weight divided by gravity (\( g = 32.2 \, \text{ft/s}^2 \)):\[ m = \frac{144,600 \, \text{lb}}{32.2 \, \text{ft/s}^2} \approx 4,492.86 \, \text{slugs} \]Thus, the force \[ F = 4,492.86 \, \text{slugs} \times 0.15 \, \text{ft/s}^2 = 673.93 \, \text{lb} \]
05

Calculate Net Force Required

Since the coal is being discharged downward at the rate of 20,000 lb/s, it does not add or subtract force in the horizontal (forward) direction. Hence, the net force required to achieve the acceleration accounts only for friction and inertial force:\[ P = 673.93 \, \text{lb} + 289.2 \, \text{lb} = 963.13 \, \text{lb} \]
06

Determine the Coupler Force

The coupler force required to achieve the desired acceleration is:\[ P \approx 963.13 \, \text{lb} \] after summing up the inertial and frictional forces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental concept in dynamics that describes the relationship between an object's mass, the force applied to it, and the resulting acceleration. It is mathematically expressed as \( F = ma \), where \( F \) is the net force applied to the object, \( m \) is the mass of the object, and \( a \) is the acceleration produced by the force. This law is crucial in understanding how forces influence the movement of objects and is applied in many fields including engineering and physics. In the context of the railroad coal car, the law helps determine the amount of force needed not only to overcome inertia but also to achieve a given acceleration when part of the coal has been dumped. By assessing the total mass at any given time, which includes the remaining coal and the car itself, we can calculate how much force, in this case, the coupler force, is necessary to move the car forward under the given conditions.
Frictional Resistance
Frictional resistance refers to the force that opposes the motion of an object. It arises when two surfaces are in contact and move against each other. This resistance is dependent on the nature of the surfaces in contact as well as the normal force pressing them together. In this exercise, we specifically consider the frictional resistance that the railroad coal car experiences due to its weight pressing against the rails.
  • The frictional resistance is calculated at 4 lb per ton of the car's total remaining weight.
  • After converting the weight from pounds to tons, the frictional force can be found by multiplying by this friction factor.
The role of friction is crucial as it determines how much additional force is needed to mobilize the car aside from the inertial force. Understanding frictional resistance is key to figuring out the total net force and subsequently the coupler force required to move the car.
Inertial Force
The concept of inertial force is directly tied to an object's mass and its resistance to changes in motion, as outlined by Newton's First Law of Motion. In our railroad example, inertial force represents the force necessary to accelerate the car and its remaining load.
  • To calculate inertia-related force, first, the mass is derived by dividing the total weight of the system by gravitational acceleration (\( g = 32.2 \, \text{ft/s}^2 \)).
  • Applying Newton's second law, multiplying this mass by the desired acceleration provides the inertial force.
This force component is critical as it indicates the effort needed solely to change the car's state of motion without considering external resistances such as friction. Understanding inertial force helps clarify the contributions of mass and acceleration to overall dynamics.
Railroad Mechanics
Railroad mechanics involve understanding the forces and dynamics acting on a rail vehicle, such as a coal car, during movement. This field encompasses the principles of mechanics applied specifically to rail systems, dealing with factors like weight distribution, friction, and forces at play during acceleration and deceleration.
  • One significant aspect in the exercise is how rail mechanics inform the calculation of coupler force needed for a specific acceleration without shedding light on unnecessary horizontal forces from coal discharge.
  • The overall mass, influenced by the distributed weight of the coal and car, requires careful consideration in balancing force requirements for smooth rail operations.
By understanding the unique factors within railroad mechanics, such as the specific rate of coal discharge or the friction between car wheels and rails, it's possible to accurately solve problems involving rail dynamics using systematic approaches as demonstrated in this problem.

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