/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 In the design of a space station... [FREE SOLUTION] | 91Ó°ÊÓ

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In the design of a space station to operate outside the earth's gravitational field, it is desired to give the structure a rotational speed \(N\) which will simulate the effect of the earth's gravity for members of the crew. If the centers of the crew's quarters are to be located \(12 \mathrm{m}\) from the axis of rotation, calculate the necessary rotational speed \(N\) of the space station in revolutions per minute.

Short Answer

Expert verified
The required rotational speed \(N\) is approximately 4.56 RPM.

Step by step solution

01

Understand the Problem

We need to simulate Earth's gravity by having the centripetal acceleration due to rotation equal to gravitational acceleration on Earth, which is approximately \(9.81 \text{ m/s}^2\). The crew's quarters are \(12 \text{ m}\) from the rotation axis.
02

Use the Formula for Centripetal Acceleration

Recall the formula for centripetal acceleration: \(a_c = r \omega^2\), where \(r\) is the radius of rotation (\(12 \text{ m}\) in our case), and \(\omega\) is the angular velocity in radians per second.
03

Set Centripetal Acceleration Equal to Gravitational Acceleration

Set the centripetal acceleration (\(r\omega^2\)) equal to gravitational acceleration: \(r\omega^2 = 9.81\). Substitute \(r = 12\): \(12\omega^2 = 9.81\).
04

Solve for Angular Velocity \(\omega\)

Solve \(12\omega^2 = 9.81\) for \(\omega\). This gives \(\omega^2 = \frac{9.81}{12}\). Calculate \(\omega = \sqrt{\frac{9.81}{12}}\).
05

Convert \(\omega\) to Rotational Speed \(N\)

Convert the angular velocity \(\omega\) from radians per second to revolutions per minute. Use the relation \(N = \frac{\omega}{2\pi} \times 60\).
06

Calculate and Confirm \(N\)

Calculate \(N\) using the previously derived value of \(\omega\). This will give us the rotational speed in revolutions per minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Speed
When thinking about how fast something spins, you might have heard the term "rotational speed." Rotational speed refers to how many rotations or revolutions an object completes in a given amount of time. In our space station design, this is crucial because the rotational speed will determine the artificial gravity experienced by those onboard.
To simulate Earth's gravity, we aim for a centripetal acceleration that matches the force of gravity on Earth. Given that Earth's gravity is approximately \(9.81 \text{ m/s}^2\), we need to adjust our rotational speed to achieve this exact pull.
  • First, identify the measurements. Here, the crew is positioned \(12 \text{ m}\) away from the rotation axis.
  • Next, using the centripetal acceleration formula \(a_c = r \omega^2\), we substitute the desired acceleration (\(9.81 \text{ m/s}^2\)).
  • Solving \(r\omega^2 = 9.81\) provides \(\omega\colon\) the angular velocity, which is pivotal to finding the rotational speed.
Finally, convert this angular velocity into revolutions per minute (rpm) for a practical understanding of how fast the space station should spin.
Gravitational Simulation
Human bodies are adapted to Earth's gravity, so spending time in environments without gravity can lead to health issues. That's why in designing a space station, creating a space where the effects of gravity are simulated is vital.
Gravity on Earth gives us a constant gravitational pull of \(9.81 \text{ m/s}^2\). By rotating a space station, we use what's known as "centripetal force" to act like gravity would on Earth. The idea is simple: as the space station spins, those inside it are pushed outwards against the station's walls by this force.
This push needs to match the familiar gravitational pull for it to feel natural. Here’s how the simulation is achieved:
  • The centripetal force is generated based on the distance from the rotation axis and the speed of rotation.
  • Controlled rotation ensures that the walls act like a "floor," thanks to the centrifugal effect.
  • This concept allows astronauts to experience Earth-like walking, balance, and body functions.
In summary, gravitational simulation is about creating an environment in space similar enough to Earth to keep astronauts healthy and comfortable.
Space Station Design
Designing a space station is not just about its appearance; it's about ensuring it can sustain life and provide comfort similar to living on Earth. The design includes multiple considerations, especially when it comes to simulating gravity.
First, the size and structure of the space station matter. In this exercise, we calculated the rotational speed needed by focusing on the crew’s quarters placed \(12 \text{ m}\) from the center of the station. This distance impacts how we design the station's rotation system.
Other design aspects include:
  • Ensuring the distribution of equipment and living spaces to support balanced rotation.
  • Incorporating systems that can maintain this rotational movement smoothly and efficiently.
  • Designing facilities inside the station that accommodate the artificial gravity – like gym equipment placed correctly to maximize the gravitational effect.
The spinning design not only aids in gravitational simulation but also plays a crucial role in the station's structural stability and energy use as it moves through space. This holistic approach helps achieve a viable space station design that supports long-term space living.

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Most popular questions from this chapter

A "drag-free" satellite is one which carries a small mass inside a chamber as shown. If the satellite speed decreases because of drag, the mass speed will not, and so the mass moves relative to the chamber as indicated. Sensors detect this change in the position of the mass within the chamber and the satellite thruster is periodically fired to recenter the mass. In this manner, compensation is made for drag. If the satellite is in a circular earth orbit of 200 -km altitude and a total thruster burn time of 300 seconds occurs during 10 orbits, determine the drag force \(D\) acting on the 100 -kg satellite. The thruster force \(T\) is 2 N.

The 0.5 -kg cylinder \(A\) is released from rest from the position shown and drops the distance \(h_{1}=\) \(0.6 \mathrm{m} .\) It then collides with the 0.4 -kg block \(B ;\) the coefficient of restitution is \(e=0.8 .\) Determine the maximum downward displacement \(h_{2}\) of block \(B\) Neglect all friction and assume that block \(B\) is initially held in place by a hidden mechanism until the collision begins. The two springs of modulus \(k=500 \mathrm{N} / \mathrm{m}\) are initially unstretched, and the distance \(d=0.8 \mathrm{m}\).

Two 425,000 -lb locomotives pull fifty \(200,000-1 b\) coal hoppers. The train starts from rest and accelerates uniformly to a speed of \(40 \mathrm{mi} / \mathrm{hr}\) over a distance of \(8000 \mathrm{ft}\) on a level track. The constant rolling resistance of each car is 0.005 times its weight. Neglect all other retarding forces and assume that each locomotive contributes equally to the tractive force. Determine \((a)\) the tractive force exerted by each locomotive at \(20 \mathrm{mi} / \mathrm{hr}\) (b) the power required from each locomotive at \(20 \mathrm{mi} / \mathrm{hr},(c)\) the power required from each locomotive as the train speed approaches \(40 \mathrm{mi} / \mathrm{hr},\) and \((d)\) the power required from each locomotive if the train cruises at a steady \(40 \mathrm{mi} / \mathrm{hr}\).

A spacecraft \(m\) is heading toward the center of the moon with a velocity of \(2000 \mathrm{mi} / \mathrm{hr}\) at a distance from the moon's surface equal to the radius \(R\) of the moon. Compute the impact velocity \(v\) with the surface of the moon if the spacecraft is unable to fire its retro-rockets. Consider the moon fixed in space. The radius \(R\) of the moon is \(1080 \mathrm{mi}\), and the acceleration due to gravity at its surface is \(5.32 \mathrm{ft} / \mathrm{sec}^{2}\).

The slotted arm revolves in the horizontal plane about the fixed vertical axis through point \(O .\) The 3-lb slider \(C\) is drawn toward \(O\) at the constant rate of 2 in./sec by pulling the cord \(S\). At the instant for which \(r=9\) in., the arm has a counterclockwise angular velocity \(\omega=6\) rad/sec and is slowing down at the rate of 2 rad \(/\) sec \(^{2}\). For this instant, determine the tension \(T\) in the cord and the magnitude \(N\) of the force exerted on the slider by the sides of the smooth radial slot. Indicate which side, \(A\) or \(B\), of the slot contacts the slider.

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