/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A bicyclist finds that she desce... [FREE SOLUTION] | 91Ó°ÊÓ

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A bicyclist finds that she descends the slope \(\theta_{1}=\) \(3^{\circ}\) at a certain constant speed with no braking or pedaling required. The slope changes fairly abruptly to \(\theta_{2}\) at point \(A\). If the bicyclist takes no action but continues to coast, determine the acceleration \(a\) of the bike just after it passes point \(A\) for the conditions \((a) \theta_{2}=5^{\circ}\) and \((b) \theta_{2}=0\).

Short Answer

Expert verified
For \( \theta_2 = 5^{\circ} \), \( a \approx 0.857 \text{ m/s}^2 \). For \( \theta_2 = 0^{\circ} \), \( a = 0 \text{ m/s}^2 \).

Step by step solution

01

Identify Forces Acting on the Bicycle

The main forces acting on the bicycle include gravity, normal force, and any frictional forces. Since it's coasting down a hill with no pedaling, we focus on the gravitational component parallel to the slope, which causes acceleration.
02

Calculate Gravitational Force Component

For a slope inclined at an angle \( \theta \), the gravitational force component acting parallel to the slope, which is responsible for acceleration, is given by \( mg \sin(\theta) \), where \( m \) is the mass of the bicycle and rider, and \( g \) is the acceleration due to gravity.
03

Find the Acceleration Formula

The net force acting on the bicyclist along the slope is \( F = mg \sin(\theta) \). Using Newton's second law, \( F = ma \), the acceleration \( a \) is given by \( a = g \sin(\theta) \).
04

Calculate Acceleration for \( \theta_2 = 5^{\circ} \)

Substitute \( \theta_2 = 5^{\circ} \) into the acceleration formula: \( a = g \sin(5^{\circ}) \). Assuming \( g = 9.81 \, \text{m/s}^2 \), the acceleration is \( a = 9.81 \, \text{m/s}^2 \times \sin(5^{\circ}) \).
05

Calculate Acceleration for \( \theta_2 = 0^{\circ} \)

Substitute \( \theta_2 = 0^{\circ} \) into the acceleration formula: \( a = g \sin(0^{\circ}) \). Since \( \sin(0^{\circ}) = 0 \), the acceleration is \( a = 0 \, \text{m/s}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is a fundamental principle in physics that explains how the motion of an object changes when a force is applied. The law is expressed mathematically as \( F = ma \), where \( F \) is the net external force acting on an object, \( m \) is the mass of the object, and \( a \) is the acceleration produced. This equation tells us that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

In simpler terms:
  • If you push an object harder (increase \( F \)), it accelerates more.
  • If you try to push a heavier object with the same force, it accelerates less (increase in \( m \) leads to decrease in \( a \)).
In the context of the bicyclist descending a slope, the slope's angle affects the gravitational component of the force acting parallel to the slope. This demonstrates Newton's Second Law as the slope's angle changes the net force and consequently the acceleration. Understanding this principle helps explain why the bicyclist accelerates differently on varying slopes.
Gravitational Force
Gravitational force is the attractive force that exists between any two masses, such as the Earth and the objects on it. It can be quantified by the equation \( F = mg \), where \( F \) is the force of gravity, \( m \) is the mass, and \( g \) is the gravitational acceleration, which on Earth is approximately \( 9.81 \text{ m/s}^2 \).

When dealing with objects on an inclined plane:
  • The gravitational force can be split into two components: one parallel to the slope and one perpendicular to it.
  • The parallel component, \( mg \sin(\theta) \), is responsible for pulling the object down the slope and causing acceleration.
  • The perpendicular component, \( mg \cos(\theta) \), contributes to the normal force but does not affect the object's motion along the slope.
In the bicycle scenario, the gravitational force's parallel component drives the bike down the slope. This is why calculating \( mg \sin(\theta) \) is crucial for finding out how the bike's speed changes when descending.
Inclined Plane Motion
An inclined plane is a flat surface tilted at an angle, compared to the horizontal. This simple machine makes it easier to move objects to a different height. When an object moves along an inclined plane, its motion is influenced by the angle of inclination and the forces acting upon it.

Key points about inclined plane motion include:
  • The steeper the incline (larger \( \theta \)), the more the gravitational force component drives motion along the plane.
  • The motion can be described by Newton's Second Law, where the net force parallel to the plane is \( mg \sin(\theta) \) and the corresponding acceleration is \( a = g \sin(\theta) \).
  • A zero angle of inclination (\( \theta = 0 \)) implies no acceleration as there is no component of gravitational force along the plane.
The bike example illustrates inclined plane motion effectively. As the slope changes, the component of gravitational force and resulting acceleration adjust accordingly, highlighting how motion on slopes functions.

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Most popular questions from this chapter

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