/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 197 The pilot of a 90,000 -lb airpla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The pilot of a 90,000 -lb airplane which is originally flying horizontally at a speed of \(400 \mathrm{mi} / \mathrm{hr}\) cuts off all engine power and enters a \(5^{\circ}\) glide path as shown. After 120 seconds the airspeed is \(360 \mathrm{mi} / \mathrm{hr} .\) Calculate the time-average drag force \(D(\) air resistance to motion along the flight path)

Short Answer

Expert verified
The time-average drag force is approximately -2278 lb.

Step by step solution

01

Calculate Initial and Final Velocities in Feet per Second

First, convert the initial (\(400 \text{ mi/hr} \) to feet per second. There are \(5280\) feet in a mile and \(3600\) seconds in an hour. \[V_i = 400 \frac{\text{mi}}{\text{hr}} \times \frac{5280 \text{ ft}}{1 \text{ mi}} \times \frac{1 \text{ hr}}{3600 \text{ s}} = 586.67 \text{ ft/s} \] Now convert the final speed (\(360 \ ext{ mi/hr} \)):\[V_f = 360 \frac{\text{mi}}{\text{hr}} \times \frac{5280 \text{ ft}}{1 \text{ mi}} \times \frac{1 \text{ hr}}{3600 \text{ s}} = 528 \text{ ft/s}\]
02

Determine Change in Kinetic Energy

The change in kinetic energy of the airplane is calculated using the initial and final velocities. The mass of the airplane is given as 90,000 lb, which we convert to slugs by dividing by the acceleration due to gravity (\(32.2 \text{ ft/s}^2\)).\[m = \frac{90,000 \text{ lb}}{32.2 \text{ ft/s}^2} = 2795.65 \text{ slugs} \]The initial and final kinetic energies are:\[KE_i = \frac{1}{2} \times 2795.65 \times (586.67)^2 \]\[KE_f = \frac{1}{2} \times 2795.65 \times (528)^2 \]The change in kinetic energy \(\Delta KE\) is:\[\Delta KE = KE_f - KE_i\]
03

Calculate Work Done by Drag Force

The work done by the drag force is equal to the change in kinetic energy. From the previous step: \[\Delta KE = 2795.65 \times \left( \frac{1}{2} \times 528^2 - \frac{1}{2} \times 586.67^2 \right)\]
04

Calculate Time-Averaged Drag Force

The work done by drag is also expressed as the product of the drag force and the distance traveled along the glide path. First, calculate the distance using the average velocity in feet per second during the 120 seconds.\[\text{Average Velocity (V_avg)} = \frac{586.67 + 528}{2} = 557.335 \text{ ft/s}\]\[\text{Distance} = \text{V_avg} \times \text{Time} = 557.335 \times 120 = 66880.2 \text{ ft}\]The work done by the drag force also equals:\[D \times \text{Distance}\]Equate the work done by drag to the change in kinetic energy and solve for the drag force:\[D = \frac{\Delta KE}{\text{Distance}}\]
05

Solve for Drag Force

Use the equation for drag force from the previous step and compute the value:\[D = \frac{-152408138.5}{66880.2} \]Compute the value.The negative sign represents the work done against the motion, indicating the direction of the drag force opposite to motion direction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy Change
Kinetic energy is the energy that an object possesses due to its motion. For this problem, we calculate the change in kinetic energy of the airplane as it decelerates. To do this, we first note that the airplane's initial speed was faster compared to when it later slowed down. This speed reduction happens because kinetic energy, which depends on velocity, changes with the flight conditions.

To find the kinetic energy at different speeds, we use the formula:\[ KE = \frac{1}{2} mv^2 \]
where \( m \) is the mass of the airplane, and \( v \) is its velocity. We convert the airplane's weight from pounds to slugs because mass in the formula is considered in slugs in the aerodynamics field.

Ultimately, the change in kinetic energy, \( \Delta KE \), is found by subtracting the final kinetic energy from the initial kinetic energy, illustrating the energy lost due to drag during the glide.
Glide Path Analysis
In aerodynamics, a glide path refers to the trajectory an aircraft follows when descending without engine power. When the engine power is reduced significantly, as in a "glide", the pilot might angle the plane at, for instance, a \(5^{\circ}\) descent angle as seen in this exercise.

Analyzing the glide path involves understanding how changes in velocity and aircraft orientation affect flight characteristics. In this scenario, by examining the plane’s motion along the glide path, we can assess how external forces like drag work against the airflow to slow the airplane's descent. The glide path analysis provides insights into the airplane's efficiency in descent, showcasing how it continues forward motion while losing altitude.

Studying glide paths involves examining parameters such as airspeed change and energy conservation, which are essential for enhancing safety and performance during engine-off conditions.
Average Velocity Calculation
When calculating average velocity during the glide, we need an understanding of how the speed varies from its initial to its final state over a given time span. Average velocity is crucial because it represents the average speed throughout the flight path and influences drag force calculations.

The formula for average velocity here is simple. It is the mean of the initial and final speed velocities, which can be calculated as follows:\[ V_{\text{avg}} = \frac{V_i + V_f}{2} \]
This formula gives the airplane's average speed as it glides, providing a straightforward way to approximate the motion characteristics over the course of 120 seconds.

Recognizing the average speed supports the calculations required to determine the effect of the drag force and estimate how far the aircraft traveled during the glide.
Aerodynamics Problem Solving
Addressing aerodynamics problems like this one involves understanding how different forces affect a flying object. One key aspect of resolving this exercise is calculating the drag force, which is the resistive force acting opposite to the aircraft's direction of motion along the flight path.

In this exercise, drag force is determined based on the kinetic energy change and the distance traveled during the glide. To solve for it, we relate the work done by the drag force to the change in kinetic energy. Mathematically, this can be expressed as:\[ D \times \text{Distance} = \Delta KE \]

By rearranging this equation, the drag force \( D \) can be isolated and calculated. The approach highlights both the importance of comprehensive aerodynamic analysis and the use of systematic mathematical steps to solve real-world flight dynamics problems.

Understanding these principles equips students with the tools to approach similar problems, paving the way for better understanding of the fundamental aerodynamic concepts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The two spheres of equal mass \(m\) are able to slide along the horizontal rotating rod. If they are initially latched in position a distance \(r\) from the rotating axis with the assembly rotating freely with an angular velocity \(\omega_{0},\) determine the new angular velocity \(\omega\) after the spheres are released and finally assume positions at the ends of the rod at a radial distance of \(2 r\). Also find the fraction \(n\) of the initial kinetic energy of the system which is lost. Neglect the small mass of the rod and shaft.

A rocket launches an unpowered space capsule at point \(A\) with an absolute velocity \(v_{A}=8000 \mathrm{mi} / \mathrm{hr}\) at an altitude of 25 mi. After the capsule has traveled a distance of 250 mi measured along its absolute space trajectory, its velocity at \(B\) is \(7600 \mathrm{mi} / \mathrm{hr}\) and its altitude is \(50 \mathrm{mi}\). Determine the average resistance \(P\) to motion in the rarified atmosphere. The earth weight of the capsule is \(48 \mathrm{lb}\), and the mean radius of the earth is 3959 mi. Consider the center of the earth fixed in space.

The slider \(A\) has a mass of \(2 \mathrm{kg}\) and moves with negligible friction in the \(30^{\circ}\) slot in the vertical sliding plate. What horizontal acceleration \(a_{0}\) should be given to the plate so that the absolute acceleration of the slider will be vertically down? What is the value of the corresponding force \(R\) exerted on the slider by the slot?

Freight car \(A\) of mass \(m_{A}\) is rolling to the right when it collides with freight car \(B\) of mass \(m_{B}\) initially at rest. If the two cars are coupled together at impact, show that the fractional loss of energy equals \(m_{B} /\left(m_{A}+m_{B}\right)\).

The slider of mass \(m_{1}=0.4 \mathrm{kg}\) moves along the smooth support surface with velocity \(v_{1}=5 \mathrm{m} / \mathrm{s}\) when in the position shown. After negotiating the curved portion, it moves onto the inclined face of an initially stationary block of mass \(m_{2}=2 \mathrm{kg}\) The coefficient of kinetic friction between the slider and the block is \(\mu_{k}=0.30 .\) Determine the velocity \(v^{\prime}\) of the system after the slider has come to rest relative to the block. Neglect friction at the small wheels, and neglect any effects associated with the transition.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.