/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 183 Rapid-transit trains \(A\) and \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Rapid-transit trains \(A\) and \(B\) travel on parallel tracks. Train \(A\) has a speed of \(80 \mathrm{km} / \mathrm{h}\) and is slowing at the rate of \(2 \mathrm{m} / \mathrm{s}^{2},\) while train \(B\) has a constant speed of \(40 \mathrm{km} / \mathrm{h}\). Determine the velocity and acceleration of train \(B\) relative to train \(A\)

Short Answer

Expert verified
Relative velocity of train B to train A is \(-40 \mathrm{km}/\mathrm{h}\) and relative acceleration is \(7.2 \mathrm{km}/\mathrm{h}^2\).

Step by step solution

01

Convert Train A's Deceleration

Train A is slowing at a rate of \(2 \mathrm{m}/\mathrm{s}^2\). We need to convert this deceleration into kilometers per hour squared for consistency with the speed units. Since \(1 \mathrm{m}/\mathrm{s}^2\) is equal to \(3.6 \mathrm{km}/\mathrm{h}^2\), the deceleration becomes \(2 \times 3.6 = 7.2 \mathrm{km}/\mathrm{h}^2\).
02

Define Relative Velocity

The velocity of train B relative to train A is the difference in their velocities. Train A is moving at \(80 \mathrm{km}/\mathrm{h}\) and train B at \(40 \mathrm{km}/\mathrm{h}\). Therefore, the relative velocity \(v_{B/A}\) is calculated as \(v_{B/A} = v_B - v_A = 40 - 80 = -40 \mathrm{km}/\mathrm{h}\). Train B is moving slower compared to train A.
03

Calculate Relative Acceleration

The relative acceleration is the difference in accelerations. Train B has a constant speed, hence zero acceleration. Train A is decelerating at \(7.2 \mathrm{km}/\mathrm{h}^2\). The relative acceleration \(a_{B/A}\) is \(a_{B/A} = 0 - (-7.2) = 7.2 \mathrm{km}/\mathrm{h}^2\). This means train B is effectively accelerating at \(7.2 \mathrm{km}/\mathrm{h}^2\) relative to train A as train A slows down.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
Imagine standing still as a car zooms past you. To figure out how fast the car appears to be moving from your perspective, we use the concept of relative velocity. In dynamics, relative velocity examines the speed of one object from the viewpoint of another moving or stationary object.
For example, if Train A is moving at 80 km/h and Train B at 40 km/h, like in the exercise, the velocity of Train B relative to Train A is seen as:
  • Subtract B's velocity from A's:
  • Speed difference: 40 km/h - 80 km/h = -40 km/h.
The negative sign indicates Train B moves slower compared to Train A. Understanding relative velocity helps in comprehending how objects interact within a moving frame. This is crucial in fields like aerodynamics, where the movement of aircraft is assessed against the wind or other moving objects.
Relative Acceleration
Just as velocity can be relative, so can acceleration. The idea of relative acceleration is about comparing the rate of change of velocities between two objects. When examining relative acceleration, like with trains A and B, you look at how one train's speed changes while considering the other train's rate of speed alteration.
  • In this exercise, Train A decelerates at 7.2 km/h².
  • Train B travels at a constant speed, meaning its acceleration is 0 km/h².
The relative acceleration is thus calculated by finding the difference:
  • 0 - (-7.2) = 7.2 km/h².
The negative sign in the deceleration (or slowing down) makes the math show that Train B seems to be accelerating relative to Train A. This concept helps one comprehend how fast an object seems to move compared to another, especially when one is decelerating or accelerating.
Kinematic Equations
Kinematic equations are fundamental tools used to analyze the motion of objects, describing how objects move in terms of velocity, acceleration, time, and displacement. These equations help quantify the motion, allowing for predictions and analysis in dynamics.
There are a few key kinematic equations, but the primary ones involve:
  • Initial velocity and final velocity
  • Acceleration
  • Time
  • Displacement
In our train scenario, kinematic equations assist in determining Train A's deceleration over time. Suppose Train A needs to stop, we could use these equations to calculate how long it would take or how far it would travel before coming to a halt, given its initial speed and rate of deceleration. Using these formulas makes analyzing complex motion problems more straightforward by breaking them down into measurable units. Overall, these equations underpin much of classical mechanics, helping solve various practical and theoretical problems in physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A small airplane flying horizontally with a speed of \(180 \mathrm{mi} / \mathrm{hr}\) at an altitude of \(400 \mathrm{ft}\) above a remote valley drops an emergency medical package at \(A\) The package has a parachute which deploys at \(B\) and allows the package to descend vertically at the constant rate of 6 ft/sec. If the drop is designed so that the package is to reach the ground 37 seconds after release at \(A,\) determine the horizontal lead \(L\) so that the package hits the target. Neglect atmospheric resistance from \(A\) to \(B\)

The acceleration of a particle is given by \(a=2 t-10\) where \(a\) is in meters per second squared and \(t\) is in seconds. Determine the velocity and displacement as functions of time. The initial displacement at \(t=0\) is \(s_{0}=-4 \mathrm{m},\) and the initial velocity is \(v_{0}=3 \mathrm{m} / \mathrm{s}\)

At time \(t=0\) a small ball is projected from point \(A\) with a velocity of \(200 \mathrm{ft} / \mathrm{sec}\) at the \(60^{\circ}\) angle. Neglect atmospheric resistance and determine the two times \(t_{1}\) and \(t_{2}\) when the velocity of the ball makes an angle of \(45^{\circ}\) with the horizontal \(x\) -axis.

A meteor \(P\) is tracked by a radar observatory on the earth at \(O .\) When the meteor is directly overhead \(\left(\theta=90^{\circ}\right),\) the following observations are recorded: \(r=80 \mathrm{km}, \dot{r}=-20 \mathrm{km} / \mathrm{s},\) and \(\dot{\theta}=0.4\) \(\operatorname{rad} / \mathrm{s}\) (a) Determine the speed \(v\) of the meteor and the angle \(\beta\) which its velocity vector makes with the horizontal. Neglect any effects due to the earth's rotation. (b) Repeat with all given quantities remaining the same, except that \(\theta=75^{\circ}\)

A bicyclist rides along the hard-packed sand beach with a speed \(v_{B}=16 \mathrm{mi} / \mathrm{hr}\) as indicated. The wind speed is \(v_{w}=20 \mathrm{mi} / \mathrm{hr} .(a)\) Determine the velocity of the wind relative to the bicyclist. (b) At what speed \(v_{B}\) would the bicyclist feel the wind coming directly from her left (perpendicular to her path)? What would be this relative speed?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.