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A meteor \(P\) is tracked by a radar observatory on the earth at \(O .\) When the meteor is directly overhead \(\left(\theta=90^{\circ}\right),\) the following observations are recorded: \(r=80 \mathrm{km}, \dot{r}=-20 \mathrm{km} / \mathrm{s},\) and \(\dot{\theta}=0.4\) \(\operatorname{rad} / \mathrm{s}\) (a) Determine the speed \(v\) of the meteor and the angle \(\beta\) which its velocity vector makes with the horizontal. Neglect any effects due to the earth's rotation. (b) Repeat with all given quantities remaining the same, except that \(\theta=75^{\circ}\)

Short Answer

Expert verified
Speed \( v = 37.7 \text{ km/s} \); Angle \( \beta = -58.0^\circ \) in both cases.

Step by step solution

01

Understand the Given Information

We have a meteor tracked by radar. At \( \theta = 90^\circ \), the following quantities are given: \( r = 80 \text{ km} \), \( \dot{r} = -20 \text{ km/s} \) (indicating the meteor is moving closer to the observer), and \( \dot{\theta} = 0.4 \text{ rad/s} \). We must find the speed \( v \) of the meteor and the angle \( \beta \) it makes with the horizontal.
02

Determine Speed (Part (a))

The total speed \( v \) of the meteor at \( \theta = 90^\circ \) can be computed using the velocity in polar coordinates, which is given by: \[ v = \sqrt{\dot{r}^2 + (r \dot{\theta})^2} \] Substituting the known values: \( \dot{r} = -20 \text{ km/s} \), \( r = 80 \text{ km} \), and \( \dot{\theta} = 0.4 \text{ rad/s} \), we get: \[ v = \sqrt{(-20)^2 + (80 \times 0.4)^2} = \sqrt{400 + 1024} = \sqrt{1424} \approx 37.7 \text{ km/s} \]
03

Calculate Angle (Part (a))

The angle \( \beta \) made by the velocity vector with the horizontal (or tangential velocity component) is given by \( \tan \beta = \frac{r \dot{\theta}}{\dot{r}} \). Using the values, \( \tan \beta = \frac{80 \times 0.4}{-20} = -1.6 \). This results in \( \beta = \tan^{-1}(-1.6) \approx -58.0^\circ \), indicating the direction below the horizontal.
04

Update Given Angle for Part (b)

For part (b), the only change in the conditions is that the angle \( \theta \) is now \( 75^\circ \) instead of \( 90^\circ \). Recalculate the terms that involve \( \theta \), keeping all other values same: \( r = 80 \text{ km} \), \( \dot{r} = -20 \text{ km/s} \), and \( \dot{\theta} = 0.4 \text{ rad/s} \).
05

Determine Speed (Part (b))

The speed is computed the same way as before since \( \dot{r} \) and \( \dot{\theta} \) don't depend on \( \theta \). Hence, \( v = \sqrt{(-20)^2 + (80 \times 0.4)^2} = \sqrt{1424} \approx 37.7 \text{ km/s} \).
06

Calculate Angle (Part (b))

For the angle \( \beta \) with \( \theta = 75^\circ \), use the same method: \( \tan \beta = \frac{r\dot{\theta}}{\dot{r}} = -1.6 \), resulting in \( \beta \approx -58.0^\circ \). The change in \( \theta \) does not impact the value of \( \beta \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar coordinates
Polar coordinates are a unique way of representing the position of a point in a plane using two values: the radial distance from a fixed origin and the angle from a reference direction. This is particularly useful in problems involving circular or rotational motion.

The origin, often referred to as the pole, is the fixed point from which distances (denoted as \( r \)) are measured. The angle \( \theta \) is measured from a horizontal reference line, typically aligned with the positive x-axis.

In dynamics, polar coordinates provide an excellent way to analyze objects moving along curved paths. For instance, when a meteor is tracked by a radar, its position relative to the radar station on Earth is conveniently described using polar coordinates. This allows us to use the radial distance \( r \) and the angle \( \theta \) to track changes in its position over time.
Velocity vector
The velocity vector in polar coordinates is a critical concept when analyzing the motion of an object. It shows both the speed and the direction of movement in the plane.

In polar coordinates, velocity has two components - one radial and one angular. The radial component \( \dot{r} \) describes how fast the object moves towards or away from the origin. The angular component, expressed as \( r \dot{\theta} \), reflects movement along the angular direction, effectively wrapping around the circle's circumference.

This summary leads us to the speed of an object in polar coordinates. We can find it using the formula:
  • \[ v = \sqrt{\dot{r}^2 + (r \dot{\theta})^2} \]
This equation combines the radial and angular components to determine the overall speed, as demonstrated when calculating the meteor's speed in this example.
Angular motion
Angular motion refers to the movement of an object around a central point or axis. It's a fundamental aspect of dynamics, particularly when dealing with objects on curved paths.

Using the angle \( \theta \), we can track how an object rotates around the origin. This angular displacement changes with time and can be described by the angular velocity \( \dot{\theta} \), which indicates how fast the angle is changing.

The angular component of velocity is calculated as \( r \dot{\theta} \). This aspect of motion captures how quickly the object is moving along its circular path, independent of its radial component. In our example, by knowing \( \dot{\theta} \), we were able to determine how the meteor moves tangent to its path, ultimately helping in calculating its speed and trajectory angle.
Radar tracking
Radar tracking is a technique used to determine the position and velocity of objects at a distance by transmitting a radio wave signal and capturing its reflection upon hitting the object.

This method is invaluable for observing celestial bodies, such as meteors, where traditional tracking methods may not be feasible. Leveraging radar technology, the exact radial distance \( r \) and angular data \( \theta \) about a meteor can be effectively gathered. This data, when processed, reveals not just where the object is now, but in combination with angular motion concepts, predicts where it will be.

The integration of polar coordinates and radar tracking enables meteorologists and astronomers to calculate detailed velocity vectors, taking the mystery out of tracking fast-moving objects in space.

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