Chapter 18: Problem 5
A function, \(x(t)\), satisfies the equation $$ \dot{x}=x+\sqrt{t+1} \quad x(0)=2 $$ (a) Estimate \(x(0.2)\) using a first-order Taylor polynomial. (b) Differentiate the equation w.r.t. \(t\) and hence obtain an expression for \(x\). (c) Estimate \(x(0.2)\) using a second-order Taylor polynomial.
Short Answer
Step by step solution
Understanding the Equation
First-order Taylor Polynomial
Differentiate with Respect to t
Solving for x
Second-order Taylor Polynomial
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Polynomial
- It can approximate functions to various degrees of precision.
- The approximation depends on the order of the polynomial. Higher-order polynomials tend to give more accurate approximations.
- Most importantly, Taylor Polynomials are centered around a point, often where the function is known.
First-order Approximation
\[ x(t) \approx x(0) + x'(0) \cdot t \]This means we're taking the initial value of the function, adding the derivative of the function at that initial point, and multiplying by the small change in t (in this case, 0.2).
- The main advantage of this approximation is its simplicity.
- It's fairly accurate for very small intervals.
Second-order Approximation
\[ x(t) \approx x(0) + x'(0) \cdot t + \frac{x''(0)}{2} \cdot t^2 \]In the exercise, the second derivative, \( x''(0) \), was found to be 3.5. Thus, when factoring in the quadratic term:
- We see a more refined estimation: 2.67 for \( x(0.2) \).
- This shows that second-order approximations usually provide a better fit for the actual behavior of the function near the point of interest.
Initial Value Problem
\[ x(0) = 2 \]This means that at time t = 0, the value of the function x(t) is known to be 2.
- This knowledge is crucial as it forms the basis for calculating subsequent values.
- The action revolves around using this initial condition to unwrap future behavior of x(t).