Chapter 18: Problem 4
A function, \(y(x)\), satisfies the equation $$ y^{\prime}=y^{2}+x \quad y(1)=2 $$ (a) Estimate \(y(1.3)\) using a first-order Taylor polynomial. (b) By differentiating the equation with respect to \(x\), obtain an expression for \(y^{\prime \prime}\). Hence evaluate \(y^{\prime \prime}(1)\) (c) Estimate \(y(1.3)\) using a second-order Taylor polynomial.
Short Answer
Step by step solution
Understand the Initial Problem
Compute the Taylor Polynomial Coefficients—First Order
Estimate y(1.3) with First-Order Taylor Polynomial
Differentiate to Find y''
Evaluate y'' at x = 1
Use Second-Order Taylor Polynomial to Estimate y(1.3)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differential Equations
- \( y' = y^2 + x \)
By solving such equations, we can explore how various systems evolve over time, solve for unknown functions, and predict future states.
Function Approximation
This exercise involves creating both first-order and second-order Taylor polynomials to estimate the function \( y(x) \) at \( x = 1.3 \).
- First-order approximation: This involves using the function's value and its first derivative at a point, \( x_0 \). For \( y(x) \), the first-order Taylor polynomial is: \[ T_1(x) = y(x_0) + y'(x_0)(x-x_0) \] Using the initial condition \( y(1) = 2 \) and \( y'(1) = 5 \), we approximated \( y(1.3) \) by substituting these values into the polynomial result.
- Second-order approximation: Uses the second derivative as well, providing a more accurate estimate. The polynomial becomes: \[ T_2(x) = y(x_0) + y'(x_0)(x-x_0) + \frac{y''(x_0)}{2!}(x-x_0)^2 \] Here, with \( y''(1) = 21 \), the estimate at \( x = 1.3 \) is more precise than the first-order one.
Second-Order Derivatives
In our exercise, we differentiated the given equation to find \( y'' \):
- \( y'' = 2y \, y' + 1 \)
This calculation was essential for constructing the second-order Taylor polynomial. Estimating \( y(1.3) \) with second-order accuracy gives a more refined approximation compared to the first-order polynomial.
Understanding second-order derivatives enhances our ability to predict and analyze complex dynamical systems in fields like physics, engineering, and finance.