/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 The period of oscillation for a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The period of oscillation for a pendulum on Earth is 2 seconds. If the given pendulum oscillates with a period of \(4.9\) seconds on the surface of the Moon, what is the acceleration due to gravity on the Moon's surface? Express your answer in both SI and U.S. Customary units.

Short Answer

Expert verified
The acceleration due to gravity on the Moon's surface is \(1.62 \, m/s^2\) or \(5.31 \, ft/s^2\).

Step by step solution

01

Identify Known and Unknown Variables

The period of oscillation for a pendulum on Earth is 2 seconds, and on the moon is 4.9 seconds. We have to find the acceleration due to gravity on the moon.
02

Apply the pendulum period formula

The formula for the period of a pendulum is given by: \(T = 2\pi\sqrt{\frac{l}{g}}\). Here, \(g\) on Earth is known, also the periods \(T\) on Earth and on moon are known. We want to find \(g_{moon}\). We can start by rearranging the formula for \(g\): \(g = \frac{4\pi^2l}{T^2}\).
03

Using Ratio of Moon and Earth Periods

Next, we take ratio of \(g_{moon}\) to \(g_{earth}\), because the length of pendulum remains same. We get: \(\frac{g_{moon}}{g_{earth}} = \frac{T_{earth}^2}{T_{moon}^2}\). Now we substitute known values: \(\frac{g_{moon}}{9.8 \, m/s^2 or 32.2 \, ft/s^2} = \frac{(2 \, s)^2}{(4.9 \, s)^2}\).
04

Calculate Acceleration due to Gravity on Moon

Solving the equation we get \(g_{moon}\) in SI units as well as U.S. Customary units. \(g_{moon} = 1.62 \, m/s^2 or 5.31 \, ft/s^2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Pendulum
A simple pendulum is a fundamental concept in the study of physics, particularly in the field of mechanics. It consists of a weight, called a bob, attached to a string or rod of negligible mass. The pendulum is suspended from a fixed point and when it is displaced to an initial angle and released, it swings back and forth in a regular periodic motion.

The motion of a simple pendulum is a classic example of harmonic motion, where the restoring force is proportional to the displacement and acts towards the equilibrium position. This simplicity allows us to study the properties of oscillatory motion and gain insights into the forces at play, including gravitational acceleration. It's important to understand that air resistance and the pendulum's amplitude's changes are usually considered negligible in this ideal model.
Oscillation Period
The oscillation period, often simply called the period, is the duration of time it takes for a pendulum to complete one full swing, from its starting point to one side, back through the centre, to the other side, and then returning to the start.

For a simple pendulum, this period is determined mathematically by the formula: \[T = 2\pi\sqrt{\frac{l}{g}}\], where \(T\) is the period, \(l\) is the length of the pendulum, and \(g\) is the acceleration due to gravity. The period is independent of the mass of the bob and, for small amplitudes, is also independent of the amplitude of the swing. This period is a valuable aspect as it allows scientists to infer details about the local gravitational field.
Gravitational Acceleration
Gravitational acceleration is key to understanding how the motion of the pendulum is affected by the force of gravity. On Earth's surface, this value is approximately \(9.8\, m/s^2\) - a figure derived by observing the acceleration of objects in freefall.

However, it's critical to note that this acceleration is not constant across different celestial bodies, being influenced by factors such as the mass of the planet or moon and the distance from its centre. Therefore, understanding the gravitational acceleration is crucial for comparative studies in physics, and pendulum experiments offer a straightforward method for estimating this value on various planetary bodies.
Comparative Gravitational Study
By comparing the period of a pendulum on Earth to that on another celestial body, like the Moon, one can conduct a comparative gravitational study. The ratio of periods squared gives us the ratio of the gravitational accelerations, assuming the pendulum length stays constant across both environments.

This ratio approach is a prime example of how pendulums can be used in practical applications to measure or compare gravitational pulls. The formula \[\frac{g_{moon}}{g_{earth}} = \frac{T_{earth}^2}{T_{moon}^2}\] provides a direct comparison between the two gravitational forces and gives insights into not only the physics of the pendulum but the nature of gravity itself across different environments in space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Within the next 10 to 15 years, wind turbines with rotor diameters of \(180 \mathrm{~m}\) are anticipated to be developed and installed in Europe. If the blades of such turbines turn at a rate of 5 revolutions per minute, what is the speed of a point located at a tip of a blade? Express your answer in \(\mathrm{ft} / \mathrm{s}, \mathrm{m} / \mathrm{s}, \mathrm{km} / \mathrm{h}\), and \(\mathrm{mph}\).

In this problem you are asked to investigate how much water a leaky faucet wastes in one week, one month, and one year. Perform an experiment by placing a container under a leaky faucet and actually measure the amount of water accumulated in an hour (you can simulate a leaky faucet by just partially closing the faucet). You are to design the experiment. Think about the parameters that you need to measure. Express and project your findings in gallons/day, gallons/week, gallons/month, and gallons/year. At this rate, how much water is wasted by \(10,000,000\) households with leaky faucets. Write a brief report to discuss your findings.

A plugged dishwasher sink with the dimensions of \(2 \mathrm{ft}\) \(\times 1.5 \mathrm{ft} \times 1 \mathrm{ft}\) is being filled with water from a faucet with an inner diameter of \(1 \mathrm{in}\). If it takes 35 seconds to fill the sink to its rim, estimate the volumetric flow of water coming out of the faucet. What is the average velocity of water coming out of the faucet?

Chinook, a military helicopter, has two three-blade rotor systems, each turning in opposite directions. Each blade has a diameter of approximaterly \(41 \mathrm{ft}\). The blades can spin at angular speeds of up to \(225 \mathrm{rpm}\). Determine the translational speed of a particle located at the tip of a blade. Express your answer in \(\mathrm{ft} / \mathrm{s}, \mathrm{mph}\), \(\mathrm{m} / \mathrm{s}\), and \(\mathrm{km} / \mathrm{h}\).

The 2009 World Record for the \(100-\mathrm{m}\) sprint is \(9.58\) seconds and belongs to a Jamaican runner named Usain Bolt. Assuming constant acceleration, determine the speed of Mr. Bolt at distances of \(10 \mathrm{~m}, 20 \mathrm{~m}, 30 \mathrm{~m}\), \(\ldots, 80 \mathrm{~m}, 90 \mathrm{~m}\), and \(100 \mathrm{~m}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.