/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 On a gusty windy day, the blades... [FREE SOLUTION] | 91Ó°ÊÓ

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On a gusty windy day, the blades of a wind turbine are turning at a rate of 200 revolutions per minute when suddenly the brakes are applied to stop the turbine to avoid failure. If the brakes cause a deceleration of 2 \(\mathrm{rad} / \mathrm{s}^{2}\), how long would it take for the blades of the wind turbine to come to rest?

Short Answer

Expert verified
The time it would take for the blades of the wind turbine to come to rest would be \( \frac{10\pi}{3} \) seconds

Step by step solution

01

Convert initial rotational speed

First, convert the 200 revolutions per minute (rpm) to radian per second. We know that 1 revolution is \( 2\pi \) radians, and 1 minute is 60 seconds. Therefore, \( \omega_{0} = 200 \times 2\pi / 60 = \frac{20\pi}{3} \) rad/s.
02

Apply the rotational equivalent of Newton's second law

The acceleration is given by \( \omega - \omega_{0} / t \), where \( \omega \) is the final angular speed, \( \omega_{0} \) is the initial angular speed, and \( t \) is the time. As the blades come to rest, the final angular speed \( \omega \) will be 0. Switching around, we can write \( t = \omega_{0} / a \).
03

Solve for the time

Substituting the values into the equation gives us \( t = \frac{20\pi}{3} / 2 = \frac{10\pi}{3} \) seconds. This is the time it would take for the blades of the wind turbine to come to rest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Deceleration
In the problem of the wind turbine, we encounter the concept of angular deceleration, which is a measure of how quickly a rotating object slows down. It's analogous to linear deceleration, but for rotational motion. A key point to understand is that angular deceleration is considered a negative angular acceleration since it represents a decrease in angular velocity over time.

In the case of the wind turbine with brakes applied, the deceleration is given as 2 \( \mathrm{rad} / \mathrm{s}^{2} \), which means for every second, the angular speed of the turbine’s blades decreases by 2 radians per second. It is vital to note that angular deceleration is consistent across the entire body, meaning each point on the blades experiences the same change in angular velocity at any instant, notwithstanding its distance from the pivot. This uniformity is what makes calculations involving angular deceleration straightforward, similar to linear motion but in a rotational context.
Rotational Kinematics
Rotational kinematics is the branch of physics that describes the motion of rotating objects without the need to understand the forces that cause the motion. Similarly to how linear kinematics involves displacement, velocity, and acceleration, rotational kinematics involves angular displacement, angular velocity, and angular acceleration.

In our example, we use rotational kinematics to describe how the angular velocity of the wind turbine changes with time due to angular deceleration. One of the fundamental equations used is \( \omega = \omega_{0} + \alpha t \), which shows the relationship between the initial angular velocity \( \omega_{0} \), the angular acceleration \( \alpha \), and time \( t \). As we know the final angular velocity is zero (when it comes to rest), we can rearrange to solve for the time taken to stop, represented by \( t = \frac{\omega_{0}}{\alpha} \). This equation is derived from the principles of rotational kinematics and is an essential tool for solving problems related to angular motion.
Newton's Second Law for Rotation
When discussing the halting of a wind turbine's blades, Newton's second law for rotation becomes highly relevant. This law states that the rate of change of angular momentum of a body is directly proportional to the torque applied to it and occurs in the direction of the applied torque. For a constant moment of inertia, the law simplifies to \( \tau = I\alpha \), where \( \tau \) is the torque, \( I \) is the moment of inertia, and \( \alpha \) is the angular acceleration.

Applying this law to our braking turbine, the deceleration provided by the brakes is essentially a torque applied in the opposite direction of the rotation, causing the turbine to slow down and eventually stop. Even though the problem may not require us to calculate the applied torque explicitly, Newton's second law for rotation underlies the rotational kinematics equations we use to solve for the time taken for the wind turbine blades to stop. It's the rotational form of the familiar \( F = ma \), linking torque (rotational force) to angular acceleration (rotational change in motion).

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