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Two charges and a plane A positive point charge \(Q\) is fixed a distance \(\ell\) above a horizontal conducting plane. An equal negative charge \(-Q\) is to be located somewhere along the perpendicular dropped from \(Q\) to the plane. Where can \(-Q\) be placed so that the total force on it will be zero?

Short Answer

Expert verified
The negative charge can be placed at two positions where the total forces acting on it will be zero. One above the plane & one between the plane and the positive charge. These positions can be obtained by solving the force balance equations.

Step by step solution

01

Understanding the Electric Force

The negative charge is under the influence of two forces: the force exerted by the positive charge Q and the force exerted by the induced charge on the plane. The induced charge on the plane is because of presence of point charges Q and -Q. As per Coulomb's Law, the electric force \(F\) is given by \(F = k \cdot \frac{|Q1 \cdot Q2|}{r^2}\), where Q1 and Q2 are charges and r is the distance between them and k is Coulomb's constant. These forces are additive in vector space.
02

Identifying the Conditions for Zero Force

For the total force on -Q to be zero, the force from positive charge must equal and opposite to the force due to induced charges on the plane. Therefore \(F_{Q} = F_{plane}\). Considering the direction of forces, charges Q and -Q attract each other along the perpendicular line, while the induced charges on the plane repel -Q, also along the line.
03

Calculating the Possible Positions

The possible positions are those where the sum of forces are zero. For -Q above the plane, it means the position where the force from the positive charge equals the force from the plane. For -Q between plane and positive charge, the forces must add up to zero. Both scenarios involve solving the equation \(F_{Q} = F_{plane}\) for the corresponding positions which gives us two solutions for location of -Q.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law defines the magnitude of the electric force between two point charges. It's an inverse-square law expressing that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In formula terms, it's described by
\[ F = k \cdot \frac{|Q_1 \cdot Q_2|}{r^2} \],
where \(F\) is the electric force, \(Q_1\) and \(Q_2\) are the magnitudes of the charges, \(r\) is the distance separating them, and \(k\) is Coulomb's constant, approximately equal to \(8.9875 \times 10^9 \: N m^2/C^2\). This equation is crucial for understanding interactions between charges, including attractions and repulsions.
When applying Columb's Law to homework problems, it's important to also factor in direction since force is a vector quantity. So, remember to consider the line along which the charges interact and whether they attract or repel each other.
Electric Field Due to Induced Charges
The concept of an electric field due to induced charges arises when a charge causes the redistribution of charges on a nearby conductor. Imagine our charge \(Q\) near the conducting plane. The charge induces a distribution of opposite charge on the surface of the conductor, creating an electric field.
This induced electric field opposes the original electric field of the point charge \(Q\). The closer the negative charge \(-Q\) gets to the plane, the stronger the induced field becomes, reaching a maximum when it's very close to the plane's surface. The field from induced charges is calculated using the method of images, a principle that replaces the conducting plane with an imaginary charge that mirrors the real one.
For our problem-solving scenario, you'd visualize an image charge equal and opposite to our point charge, located symmetrically below the plane. This method simplifies complex boundary conditions that the conducting plane represents, allowing for easy calculation of forces.
Equilibrium Position in Electrostatics
In electrostatics, an equilibrium position for a charge occurs when the net electric force acting on it is zero. In layman's terms, it's like finding the perfect spot where the electric tug-of-war between charges cancels out.
In the case of our exercise, the negative charge \(-Q\) will reach equilibrium when the attractive force due to the positive charge \(Q\) exactly balances the repulsive force from the induced charges on the plane. Remember, the equilibrium position is not necessarily at the midpoint between the charges or the plane. It could be anywhere along the line of action, depending on the relative magnitudes of the forces involved.
To find this equilibrium position, you would typically set up an equation where the magnitudes of the forces from the point charge and the induced charges are equal and solve for the distance from the charge to the plane. As with all physics problems, be meticulous with units and direction to ensure accuracy. In summary, the equilibrium position is where the charge experiences a delicate balance and hence remains at rest.

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