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Capacitance coefficients for shells : ? A capacitor consists of two concentric spherical shells. Label the inner shell, of radius \(b\), as conductor 1 ; and label the outer shell, of radius \(a\), as conductor \(2 .\) For this two-conductor system, find \(C_{11}\), \(C_{22}\), and \(C_{12}\)

Short Answer

Expert verified
The self-capacitance of the inner shell (\(C_{11}\)) is \(4 \pi \varepsilon_0 b\), that of the outer shell (\(C_{22}\)) is \(4 \pi \varepsilon_0 a\), and the mutual capacitance between the shells (\(C_{12} = C_{21}\)) is \(4 \pi \varepsilon_0 \frac{ab}{a-b}\)

Step by step solution

01

Identifying variables and constants

Let's denote the radii of the inner and outer spherical shells as b and a respectively. The electric constant \(\varepsilon_0\) is a fundamental constant.
02

Formulate the equations for the coefficients

We need to use the definitions of the capacitance coefficients. \(C_{11}\) represents the self-capacitance of conductor 1 (the inner shell) and is defined as the charge it would hold if it were isolated and raised to a unit potential (while conductor 2 is grounded). Similarly, \(C_{22}\) is the self-capacitance of conductor 2 (the outer shell). \(C_{12}\) represents the mutual capacitance between the conductors, which is given by the total charge induced on conductor 2 when conductor 1 is raised to a unit potential.
03

Calculate \(C_{11}\) (Self capacitance of inner shell)

The self-capacitance of an isolated spherical conductor of radius r (in this case, the inner shell of radius b), is given by \(C = 4 \pi \varepsilon_0 r\). So, for the inner shell (conductor 1), we have: \(C_{11} = 4 \pi \varepsilon_0 b\)
04

Calculate \(C_{22}\) (Self capacitance of outer shell)

The formula to calculate the self-capacitance of a spherical conductor applies also to the outer shell (conductor 2), therefore the self-capacitance of the outer shell is: \(C_{22} = 4 \pi \varepsilon_0 a\)
05

Calculate \(C_{12}\) (Mutual capacitance between the shells)

For a two spherical shell system, the mutual capacitance is given by the equation \(C_{12} = C_{21} = 4 \pi \varepsilon_0 \frac{ab}{a-b}\). Substituting the values of a and b, we can find the mutual capacitance \(C_{12}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Capacitor
A spherical capacitor is an electrical device that consists of two concentric spherical conductive shells. These shells act as the electrodes of the capacitor. The inner shell, often called the core, is surrounded by another layer of metallic material which is the outer shell. This configuration is rather unique because the shells are perfectly symmetric around each other, leading to a straightforward calculation of electrical properties.
The purpose of a spherical capacitor is to store electrical energy in the electric field between the two shells. Unlike parallel-plate capacitors, spherical capacitors can provide a large capacitance because of their 3D structure. They are less commonly seen in practical applications but are crucial in learning and understanding how charge distribution works in electrostatics.
The capacitance of these capacitors can be influenced by factors such as the radii of the inner and outer shells and the permittivity of the medium between them, often air or vacuum.
Self Capacitance
Self capacitance is the ability of an isolated conductor to hold a charge. It's an intrinsic property determined by its shape and size. When we deal with capacitors, self capacitance is crucial for understanding how much charge a single conductor can store at a given potential without influence from other conductors nearby.
For spherical conductors, this is given by the formula for a spherical capacitor: \[ C = 4 \, \pi \, \varepsilon_0 \times \text{radius} \] where \( \varepsilon_0 \) is the permittivity of free space, a constant. This means for a larger sphere, the self capacitance increases, enabling it to hold more charge at a unit potential. This is important for determining the individual contribution of each spherical shell in a capacitor setup to the total storage capacity.
The self capacitance of each shell can be analyzed by thinking of them as being isolated in space, even though they interact in the real system.
Mutual Capacitance
Mutual capacitance refers to the capacitance between two separate conductors. For concentric spherical shells, this is the measure of charge induced on one sphere due to the potential on the other.
The concept of mutual capacitance is essential because it reflects the interaction between different parts of a capacitor. In the case of concentric shells, it captures how the presence of one shell at a particular potential can affect the distribution of charge on the other shell.
The mutual capacitance in a spherical capacitor is determined by the equation: \[ C_{12} = 4 \, \pi \, \varepsilon_0 \frac{ab}{a-b} \] where \( a \) and \( b \) are the radii of the outer and inner shells respectively. This formula emphasizes that the mutual capacitance is affected by the relative sizes of the shells and the space between them. It's key to understanding coupling in multi-conductor systems in electrostatics.
Electrostatics
Electrostatics is the field of physics that studies electric charges at rest. It investigates the forces, fields, and potentials associated with static electric charges. In the context of capacitors, electrostatics explains how conductors interact with electrical fields.
In a spherical capacitor, electrostatics governs how charges are distributed on the surfaces of the shells and how they generate an electric field in the space between them. It uses the principles of superposition to understand how fields from multiple sources add together.
  • Electric Field: In such systems, the electric field exists radially between the shells, calculated using Gauss's Law.
  • Potential Difference: The potential difference between the shells is related to the work needed to move a charge in the field.
Understanding these concepts is crucial to analyze how energy is stored and transferred in spherical capacitors. Electrostatics answers these questions mathematically with precision, allowing engineers and scientists to design efficient capacitors for various applications.
Concentric Spherical Shells
Concentric spherical shells are a classic arrangement in electrostatics used to simplify the study of capacitance and electric fields. This structure consists of two or more spherical conductors that share a common center, which results in symmetric, predictable field lines and properties. It is a favored configuration for theoretical studies because the symmetry can often make calculations more straightforward.
In practice, concentric shells are not only limited to capacitors. They appear in other technologies and models, like satellite structures and shielding systems, due to their balanced distribution of stress and pressure. When analyzing the concentric spherical shell capacitor, one deals with multiple parameters:
  • Radii Sizes: These determine not only the volume and surface area but also the field strength between the shells.
  • Permittivity of Medium: This influences how electrical fields behave within the medium separating the shells, affecting the overall capacitance.
Being familiar with concentric structures deepens your comprehension of how the geometry of a system influences physics, making it possible to tailor designs to fulfill specific capacitive and field requirements.

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Most popular questions from this chapter

Force, and potential squared * (a) In Gaussian units, show that the square of a potential difference \(\left(\phi_{2}-\phi_{1}\right)^{2}\) has the same dimensions as force. (In SI units, \(\epsilon_{0}\left(\phi_{2}-\phi_{1}\right)^{2}\) has the same units as force.) This tells us that the electrostatic forces between bodies will largely be determined, as to order of magnitude, by the potential differences involved. Dimensions will enter only in ratios, and there may be some constants like \(4 \pi\). What is the order of magnitude of force youexpect with 1 statvolt potential difference between something and something else? Practically achievable potential differences are rather severely limited, for reasons having to do with the structure of matter. The highest man-made difference of electric potential is about \(10^{7}\) volts, achieved by a Van de Graaff electrostatic generator operating under high pressure. (Billion-volt accelerators do not involve potential differences that large.) How many pounds force are you likely to find associated with a "square megavolt"? These considerations may suggest why electrostatic motors have not found much application.

Capacitance-coefficient symmetry Here are some suggestions that should enable you to construct a proof that \(C_{12}\) must always equal \(C_{21}\). We know that, when an element of charge \(d Q\) is transferred from zero potential to a conductor at potential \(\phi\), some external agency has to supply an amount of energy \(\phi d Q\). Consider a two-conductor system in which the twoconductors have been charged so that their potentials are, respectively, \(\phi_{1 \mathrm{f}}\) and \(\phi_{2 \mathrm{f}}\) ("f' for "final"). This condition might have been brought about, starting from a state with all charges and potentials zero, in many different ways. Two possible ways are of particular interest. (a) Keep \(\phi_{2}\) at zero while raising \(\phi_{1}\) gradually from zero to \(\phi_{\text {If }}\) Then raise \(\phi_{2}\) from zero to \(\phi_{2 \mathrm{f}}\) while holding \(\phi_{1}\) constant at \(\phi_{1 \mathrm{f}}\). (b) Carry out a similar program with the roles of 1 and 2 exchanged, that is, raise \(\phi_{2}\) from zero to \(\phi_{2 f}\) first, and so on. Compute the total work done by external agencies, for each of the two charging programs. Then complete the argument.

A capacitor consists of two coaxial cylinders of length \(L\), with outer and inner radii \(a\) and \(b .\) Assume \(L \gg a-b\), so that end corrections may be neglected. Show that the capacitance is \(C=\) \(2 \pi \epsilon_{0} L / \ln (a / b)\). Verify that if the gap between the cylinders, \(a-b\), is very small compared with the radius, this result reduces to onethat could have been obtained by using the formula for the parallelplate capacitor.

Synchrotron current * In a 6 gigaelectron-volt \(\left(1 \mathrm{GeV}=10^{9} \mathrm{eV}\right)\) electron synchrotron, electrons travel around the machine in an approximately circular path 240 meters long. It is normal to have about \(10^{11}\) electrons circling on this path during a cycle of acceleration. The speed of the electrons is practically that of light. What is the current? We give this very simple problem to emphasize that nothing in our definition of current as rate of transport requires the velocities of the charge carriers to be nonrelativistic and that there is no rule against a given charged particle getting counted many times during a second as part of the current.

Moving perpendicular to a wire At the end of Section \(5.9\) we discussed the case where a charge \(q\) moves perpendicular to a wire. Figures \(5.25\) and \(5.26\) show qualtatively why there is a nonzero force on the charge, pointing in the positive \(x\) direction. Carry out the calculation to show that the force at a distance \(\ell\) from the wire equals \(q v l / 2 \pi \epsilon_{0} \ell c^{2}\). That is, use Eq. (5.15) to calculate the force on the charge in its own frame, and then divide by \(\gamma\) to transform back to the lab frame. Notes: You can use the fact that in the charge \(q\) 's frame, the speed of the electrons in the \(x\) direction is \(v_{0} / \gamma\) (this comes from the transverse-velocity-addition formula). Remember that the \(\beta\) in Eq. \((5.15)\) is the velocity of the electrons in the charge's frame, and this velocity has two components. Be careful with the transverse distance involved. There are many things to keep track of in this problem, but the integration itself is easy if you use a computer (or Appendix K).

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