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Amplifier \(A\) has an input resistance of \(1 \mathrm{M} \Omega\) an output resistance of \(200 \Omega\), and an open-circuit trans resistance gain of \(100 \mathrm{M} \Omega\) Amplifier \(B\) has an input resistance of \(50 \Omega\), an output impedance of \(500 \mathrm{k} \Omega\), and a short-circuit current gain of \(100 .\) Find the voltage amplifier model for the cascade of \(A\) followed by \(B\). Then, determine the corresponding trans conductance amplifier model.

Short Answer

Expert verified
The voltage amplifier model is initially calculated using individual gains of A and B, focusing on resistance relations. Converting to transconductance for output current from input voltage is achieved by adjusting for the cascade results.

Step by step solution

01

Analyze Amplifier A

Amplifier A has an open-circuit trans resistance gain of 100 MΩ, input resistance of 1 MΩ, and output resistance of 200 Ω. The open-circuit trans resistance gain means that for a given input current, the output voltage is potential increased by this factor.
02

Analyze Amplifier B

Amplifier B has a short-circuit current gain of 100, input resistance of 50 Ω, and output impedance of 500 kΩ. A short-circuit current gain implies that for a given input current, the output current is amplified 100 times while maintaining a constant input impedance.
03

Find Voltage Amplifier Equivalent of A

The output voltage of amplifier A can be formulated as a product of its trans resistance gain and the input current. Here, convert this model to a voltage amplifier model by evaluating potential differences due to the given resistance values. The voltage gain can be simply the open-circuit trans resistance divided by A's output and practical load impedance.
04

Find Voltage Amplifier Equivalent of B

Considering amplifier B's current gain and input/output resistances, it can be designed as a voltage amplifier at output by stepping up from the current input, using the resistances as voltage scaled parameters to understand the voltage gain relation.
05

Cascade A and B for Voltage Amplifier Model

In a cascade, the output of A connects to the input of B. Manage interaction of resistances, considering the voltage gain from A affects B. Calculate the total voltage gain as the product of individual voltage gains of A and B while adjusting for internal resistance pairs.
06

Convert to Transconductance Model

Switch the model perspective. A transconductance amplifier relies on converting input voltage to output current. Analyze how the voltage amplifier maps to this perspective. Adjust the cascade result from voltage amplifier calculations to show the relationship in terms of output current per input voltage, calculating joint transconductance of A and B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trans resistance gain
Trans resistance gain is a critical concept when working with amplifiers, especially in cascade analysis. It refers to the amplification factor in which input current is converted into an output voltage. This type of gain is especially useful in understanding how much an amplifier can boost a signal. In the case of Amplifier A, the trans resistance gain is given as 100 MΩ. This means that for every ampere of input current, the output voltage is increased by 100 million ohms. This property is important when designing amplifier systems as it gives insight into signal strength and functionality.
Engineers often use trans resistance gain to estimate how efficiently a signal can be processed and transmitted from one stage to another. It simply pictures the relationship between current variations at the input and voltage variations at the output.
By understanding this ratio, you can determine how an incoming weak current signal can be turned into a robust voltage signal, crucial in high-precision electronics which require stability and high gain.
Voltage amplifier model
The voltage amplifier model is another important character in amplifier systems. It describes the transformation of the amplifier’s function from one that deals primarily with currents to one that amplifies voltage levels.
The goal is to convert the characteristics of an amplifier in terms of its trans resistance gain or current gain into a representation of how it amplifies voltage. For example, in Amplifier A, the voltage amplifier model would be determined by dividing the open-circuit trans resistance gain by the sum of its output and load impedance.
  • This transformation allows engineers to better understand how the amplifier will behave in a variety of practical circuits.
  • It provides a framework for predicting the output voltage level given a particular input.
By considering the equivalent resistances, engineers can model the voltage amplifier to portray the device’s efficiency in producing higher output voltages from given input signals, ultimately guiding design improvements and application-specific amplifier configurations.
Transconductance amplifier
The transconductance amplifier is a different breed, distinct from the voltage and trans resistance amplifiers, and it’s greatly used in applications where converting an input voltage to an output current is necessary.
Transconductance refers to the parameter that translates voltage changes at the input to proportional current changes at the output. Its unit is Siemens (S), indicating how many amperes of output current is produced per volt of input.
A transconductance model provides insight into how efficiently an amplifier converts voltage to current, a crucial property when driving loads that require precise current control.
When switching from a voltage amplifier model to a transconductance model in a cascade connection like amplifier A and B, it means translating the output of the voltage amplifier to reflect a desired current output. This involves examining how the voltage gain previously calculated can be understood as an output current using the joint transconductance of both stages. Thus, transconductance amplifiers are ideal in applications like operational amplifiers (op-amps), driving capacitive loads, and various communication devices where current control is paramount.
Short-circuit current gain
Short-circuit current gain is a parameter exclusive to current amplifiers, defining how input current is scaled up to become the output current.
This key concept implies directly how much the input current is multiplied while maintaining the input as a constant. In Amplifier B, the short-circuit current gain is 100, meaning the input current is 100-fold at the output under ideal conditions.
  • This gain provides insights into the amplifier's ability to strengthen a current, just like trans resistance provides insights for voltage.
  • The short-circuit condition assumes zero load resistance, focusing on the pure current multiplication aspect of the amplifier.
Understanding this allows one to tailor amplifiers for specific applications, ensuring the desired current levels are met for specific purposes, like driving low-resistance loads effectively. Analyzing short-circuit current gain helps in ensuring that systems are designed for optimal current delivery and efficiency, crucial in environments where current rather than voltage is the primary concern.

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Most popular questions from this chapter

In recording automotive emissions, we need to sense the short-circuit current of a chemical sensor that has a variable Thevenin impedance. A voltage that is proportional to the current must be applied to the input of a data-acquisition module. What type of ideal amplifier is needed? Justify your answer.

An amplifier is needed as a part of a system for documentation of voltages in the earth created by an electrical power distribution system, Voltage waveform occurring between probes to be placed in the earth are to be amplified before being applied to the analog-to-digital converter (ADC) inputs of laptop computers. The internal impedance of the probe can be as high as \(10 \mathrm{k} \Omega\) in dry sand or as low as \(10 \Omega\) in muck. Because several different models of ADCs are to be used in the project, the load impedance for the amplifier varies from \(10 \mathrm{k} \Omega\) to \(1 \mathrm{M} \Omega\) Nominally, the voltage applied to the ADC is required to be 1000 times the open-circuit voltage of the probe ±3 percent. What type of ideal amplifier is best suited for this application? Using your best judgment, find the specifications for the impedance and gain parameter of this amplifier.

An amplifier has an input resistance of \(1 \mathrm{k} \Omega,\) an output resistance of \(200 \Omega,\) and a short-circuit trans conductance gain of \(0.5 \mathrm{S}\) Determine the open-circuit voltage gain, the short-circuit current gain, and the open circuit trans resistance gain.

An amplifier with \(R_{i}=12 \mathrm{k} \Omega, R_{o}=1 \mathrm{k} \Omega\) and \(A_{y x}=-10\) is operated with a \(1-k \Omega\) load. A source having a Thevenin resistance of \(4 \mathrm{k} \Omega\) and a short-circuit current of \(2 \cos (200 x t)\) mA is connected to the input terminals. Determine the output voltage as a function of time and the power gain.

We need an amplifier to supply a constant signal to each of a variable number of loads connected in parallel. What output impedance is needed in this situation? Why? What if the loads are connected in series?

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