/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A 0.145 kg baseball is travellin... [FREE SOLUTION] | 91Ó°ÊÓ

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A 0.145 kg baseball is travelling at 40 \(\mathrm{m} / \mathrm{s}\) horizontally when it is struck by a baseball bat. The baseball leaves the bat at 50 \(\mathrm{m} / \mathrm{s}\) back in the direction it came from, but at an angle of \(40^{\circ}\) above the horizontal. What is the magnitude of the impulse imparted to the baseball? (A) 1.45 \(\mathrm{N} \cdot \mathrm{s}\) (B) 4.66 \(\mathrm{N} \cdot \mathrm{s}\) (C) 12.3 \(\mathrm{N} \cdot \mathrm{S}\) (D) 13.1 \(\mathrm{N} \cdot \mathrm{s}\)

Short Answer

Expert verified
The magnitude of the impulse imparted to the baseball is 11.6 \(\mathrm{N \cdot s}\). The correct choice is (B) 11.6 \(\mathrm{N \cdot s}\).

Step by step solution

01

Compute Initial Momentum

The initial momentum of the baseball can be calculated by multiplying its mass and initial velocity. This will be \(0.145 \mathrm{kg} \times 40 \mathrm{m} / \mathrm{s} = 5.8 \mathrm{kg·m/s}\). Note that momentum is a vector quantity and the direction is towards the direction of the initial velocity.
02

Compute Final Momentum

The final momentum is the product of the mass of the baseball and its final velocity. First, convert the final velocity vector into its horizontal and vertical components using the given angle. The horizontal component will be \(50 \mathrm{m/s} \times \cos(40^{\circ}) = 38.3 \mathrm{m/s}\). The vertical component will be \(50 \mathrm{m/s} \times \sin(40^{\circ}) = 32.1 \mathrm{m/s}\). Now, the final momentum will be \(0.145 \mathrm{kg} \times \sqrt{(38.3)^2 + (32.1)^2} = 5.8 \mathrm{kg·m/s}\) directed 40 degrees above the opposite direction of the initial velocity.
03

Calculate Impulse

Impulse is the change in momentum. Here, both initial and final momentum have the same magnitude but opposite direction. Therefore, the total change in momentum (or impulse) will be given by the addition of the magnitudes of the initial and final momentum, which is \(5.8 \mathrm{kg·m/s} + 5.8 \mathrm{kg·m/s} = 11.6 \mathrm{kg·m/s}\), or in terms of Newton-second \(11.6 \mathrm{N·s}\), directed 40 degrees above the opposite direction of the initial velocity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Quantities
In physics, many physical quantities are considered vectors. This means they have both magnitude and direction. Take momentum, for example. Momentum is defined as the product of an object's mass and velocity. Since velocity is a vector, momentum becomes a vector too.
For the baseball problem, when we say its initial momentum is 5.8 kg·m/s in a specific direction, it implies both the speed and the path of travel. It’s crucial to remember that vector quantities are influenced by changes in direction, not just speed or magnitude. This is why when the ball's path changes after being hit by a bat, its momentum changes even if the overall speed remains the same.
Understanding vector quantities like momentum helps in predicting and analyzing the results of various interactions, such as collisions or rebounds in baseball.
Momentum Change
When discussing momentum change, it's directly related to another important concept: impulse. Impulse is defined as the change in momentum of an object. Mathematically represented, it is \( \Delta p = p_{final} - p_{initial} \).
In cases like the baseball scenario, impulse results from the force applied by the bat and is represented over the time it acts on the baseball. Initially, the ball moves in one direction with a certain momentum. After the bat exerts a force, the ball not only changes speed but also direction—resulting in a new momentum vector opposite the previous one.
Even if the magnitudes of the initial and final momentum seem identical, the fact that the direction changes means there is a genuine momentum change. Therefore, the total momentum change results from accounting for both direction and magnitude changes.
Horizontal and Vertical Components
To fully understand the baseball's momentum after being hit, we need to break its final velocity into horizontal and vertical components. This process is essential whenever a motion involves angles, as it allows you to see how motion divides between moving forward (horizontally) and upward (vertically).
Using trigonometric functions, the horizontal component of the final velocity is calculated as \( 50 \mathrm{m/s} \times \cos(40^{\circ}) = 38.3 \mathrm{m/s} \), and similarly, the vertical component is \( 50 \mathrm{m/s} \times \sin(40^{\circ}) = 32.1 \mathrm{m/s} \). These calculations help determine the overall direction and extent of the baseball's momentum after impact.
Understanding both components is vital for solving more complex problems involving projectile motion or objects moving at angles. It reinforces how momentum is a vector and that its effects are multi-dimensional.

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Most popular questions from this chapter

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