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A student launched a small rocket with a mass of 50 kg into the air with an initial velocity of 10 m/s in the positive vertical direction. The student then turns on the secondary engines of the rocket to apply a constant upwards force that increases the velocity of the rocket to 15 m/s. If the force provided by the secondary engines did 2,000 J of work, how much work did the force of gravity do on the rocket? (A) –500 J (B) –750 J (C) –1,250 J (D) –1,500 J

Short Answer

Expert verified
The work done by the force of gravity on the rocket is -1,125 J. Therefore, none of the presented options (A, B, C, D) is correct.

Step by step solution

01

Identify the Type of Work Done by Different Forces

Recognize that the work done by the secondary engines of the rocket is positive work (since the force and displacement are in the same direction), whilst the work done by the force of gravity is negative work (since the force of gravity and the displacement of the rocket are in opposite directions).
02

Calculate the Initial and Final Kinetic Energy

Use the formula for kinetic energy \( KE = \frac{1}{2} m v^2 \) to calculate the initial kinetic energy when the velocity is 10 m/s and the final kinetic energy when the velocity is 15 m/s. Given are: mass m = 50 kg, initial velocity \( v_i = 10 \, m/s \), and final velocity \( v_f = 15 \, m/s \). So, the initial kinetic energy is \( KE_{initial} = \frac{1}{2} m v_i^2 = \frac{1}{2} * 50 * 10^2 = 2,500 \, J \) and the final kinetic energy is \( KE_{final} = \frac{1}{2} m v_f^2 = \frac{1}{2} * 50 * 15^2 = 5,625 \, J \).
03

Apply the Work-Energy Theorem

According to the work-energy theorem, the work done on the rocket is equal to the change in its kinetic energy. The total work done \( W_{total} \) is given by: \( W_{total} = KE_{final} - KE_{initial} = 5,625 \, J - 2,500 \, J = 3,125 \, J \). We know that the secondary engines did 2,000 J of work.
04

Calculate the Work Done by Gravity

The work done by the force of gravity will be the difference between the total work and the work done by the secondary engines of the rocket. So, \( W_{gravity} = W_{total} - W_{engine} = 3,125 \, J - 2,000 \, J = -1,125 \, J \). The negative sign indicates that the work is done against the direction of motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy Calculations
Kinetic energy is a term we often hear in physics, especially when an object is in motion. It's essentially the energy that an object possesses due to its movement. To calculate the kinetic energy (\textbf{KE}) of an object, we use the formula:
\( KE = \frac{1}{2} mv^2 \)
where \( m \) is the mass of the object, and \( v \) is the velocity at which it's moving. In the context of our rocket exercise, calculating kinetic energy involves just plugging the mass and the velocities into this equation. Initially, when the rocket is launched at 10 m/s, its kinetic energy can be computed as being 2,500 Joules. Later, when the velocity increases to 15 m/s, the kinetic energy elevates to 5,625 Joules. Understanding these calculations is crucial, as they play a key role in applying the work-energy theorem to determine the work done by various forces.
Work Done by Forces
When we say 'work done by forces,' we are referring to a specific physical concept. In physics, work (\textbf{W}) is defined when a force (\textbf{F}) causes a displacement (\textbf{d}) and is calculated using the formula:
\( W = Fd \cos(\theta) \)
Here, \( \theta \) is the angle between the force and the displacement. Work has both magnitude and direction, which is why the concept of positive and negative work arises. In our rocket example, the secondary engines exert a force in the same direction as the displacement, thereby doing positive work which adds energy to the rocket. However, when it comes to gravity, it does negative work because gravitational force and the displacement of the rocket are in opposite directions. This distinction is key to solving problems involving multiple forces acting on an object, as we see with the work done to change the rocket's kinetic energy.
Gravitational Work
Gravitational work may sound a bit daunting, but it's straightforward when broken down. It refers to the work done by the gravitational force (the weight of the object) as it moves through a distance. Since gravity always acts downward, any motion opposing it (like our rocket moving upwards) results in negative work. In our scenario, the gravitational work can be calculated by taking the total work needed to change the kinetic energy and subtracting the work done by the engines. Essentially, we identify the energy added by the engines and then see what’s left over—that’s the work gravity has done, slowing the ascent of the rocket. In the given exercise, the gravitational work comes out to be -1,125 Joules (negative indicating work done against the motion of the rocket), which is crucial for a thorough understanding of energy changes in physics problems involving gravity.

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