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If you put four times more current through a solenoid, how many times more energy is stored in its magnetic field?(answer check available at lightandmatter.com)

Short Answer

Expert verified
The energy stored is 16 times greater.

Step by step solution

01

Understanding the Solenoid Energy Formula

The energy stored in the magnetic field of a solenoid is given by the formula: \( E = \frac{1}{2} L I^2 \), where \( E \) is the energy, \( L \) is the inductance of the solenoid, and \( I \) is the current passing through the solenoid.
02

Analyzing the Problem Change

We are increasing the current through the solenoid by a factor of four, so the new current \( I' = 4I \).
03

Calculating the New Energy Stored

Substitute \( I' = 4I \) into the energy formula: \( E' = \frac{1}{2} L (4I)^2 \). Simplifying this gives \( E' = \frac{1}{2} L \times 16I^2 = 16 \left( \frac{1}{2} L I^2 \right) \).
04

Comparing the New and Original Energy

The new energy stored \( E' = 16E \), which indicates that the energy stored in the magnetic field becomes 16 times greater when the current is quadrupled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
A solenoid is a long coil of wire, and when electric current flows through it, a magnetic field is created around it. Understanding this concept is fundamental when discussing the energy stored within the solenoid's magnetic field. The strength and direction of the magnetic field depend on the current flowing through the solenoid and the number of turns per unit length of the coil. Essentially:
  • A stronger current will produce a stronger magnetic field.
  • The magnetic field inside a solenoid is uniform and strong, while outside it is weak and spread out.
This magnetic field results from the alignment of magnetic moments of the atoms inside the solenoid's wire. Hence, the solenoid behaves like a bar magnet, with the magnetic field lines running parallel to each other inside the coil, forming a closed loop. This concept is crucial as it directly relates to how the energy is stored within the field, as expressed in the energy formula of the solenoid, \( E = \frac{1}{2} L I^2 \). Here, \( L \) is the inductance, which signifies how effectively the solenoid can convert electrical current into stored magnetic energy.
Current Increase
Increasing the current flowing through a solenoid has a significant effect on its magnetic field and the energy it stores. When the initial current \( I \) is increased by four times, resulting in a new current \( I' = 4I \), several things happen:
  • The magnetic field strength inside the solenoid increases substantially. This is because the magnetic field is directly proportional to the amount of current flowing.
  • The increase in current results in a larger amount of energy being stored in the magnetic field of the solenoid.
The relationship between current and energy is clearly expressed in the formula \( E = \frac{1}{2} L I^2 \). When the current is quadrupled, the energy stored, \( E' = \frac{1}{2} L (4I)^2 \), can be simplified to \( 16 \times \frac{1}{2} L I^2 \), meaning the energy storage has increased by a factor of sixteen. This significant increase highlights the quadratic relation between current and magnetic energy storage.
Inductance
Inductance, symbolized by \( L \), is a crucial attribute of a solenoid that measures its capability to store energy in its magnetic field for a given current. The greater the inductance, the more energy the solenoid can store. Inductance depends on several factors:
  • The number of turns of the coil: More turns increase the inductance.
  • The core material: Materials with higher permeability increase inductance.
  • The geometry of the coil, such as length and cross-sectional area.
In the energy formula \( E = \frac{1}{2} L I^2 \), inductance \( L \) is a constant for a given solenoid unless its construction or properties are changed. It's important to grasp that while inductance remains constant with the same physical setup, changing the current has a non-linear effect on energy storage due to the \( I^2 \) term. Thus, induction is key to efficiently storing energy in a magnetic field, and understanding this can help in designing electronic circuits that use coils or inductors effectively for energy savings.

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Most popular questions from this chapter

(a) A long, skinny solenoid consists of \(N\) turns of wire wrapped uniformly around a hollow cylinder of length \(\ell\) and crosssectional area \(A\). Find its inductance.(answer check available at lightandmatter.com) (b) Show that your answer has the right units to be an inductance.

A charged particle of mass \(m\) and charge \(q\) moves in a circle due to a uniform magnetic field of magnitude \(B\), which points perpendicular to the plane of the circle. a. Assume the particle is positively charged. Make a sketch showing the direction of motion and the direction of the field, and show that the resulting force is in the right direction to produce circular motion. b. Find the radius, \(r\), of the circle, in terms of \(m\), \(q\), \(v\), and \(B\).(answer check available at lightandmatter.com) c. Show that your result from part b has the right units. d. Discuss all four variables occurring on the right-hand side of your answer from part b. Do they make sense? For instance, what should happen to the radius when the magnetic field is made stronger? Does your equation behave this way? e. Restate your result so that it gives the particle's angular frequency, \(\omega\), in terms of the other variables, and show that \(v\) drops out.(answer check available at lightandmatter.com)

A certain region of space has a magnetic field given by \(\mathbf{B}=b x \hat{\mathbf{y}}\). Find the electric current flowing through the square defined by \(z=0,0 \leq x \leq a\), and \(0 \leq y \leq a\).(answer check available at lightandmatter.com)

A particle with a charge of \(1.0 \mathrm{C}\) and a mass of \(1.0 \mathrm{~kg}\) is observed moving past point \(\mathrm{P}\) with a velocity \((1.0 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{x}}\). The electric field at point \(\mathrm{P}\) is \((1.0 \mathrm{~V} / \mathrm{m}) \hat{\mathbf{y}}\), and the magnetic field is \((2.0 \mathrm{~T}) \hat{\mathbf{y}}\). Find the force experienced by the particle.(answer check available at lightandmatter.com)

A charged particle is released from rest. We see it start to move, and as it gets going, we notice that its path starts to curve. Can we tell whether this region of space has \(\mathbf{E} \neq 0\), or \(\mathbf{B} \neq 0\), or both? Assume that no other forces are present besides the possible electrical and magnetic ones, and that the fields, if they are present, are uniform.

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