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(a) A long, skinny solenoid consists of \(N\) turns of wire wrapped uniformly around a hollow cylinder of length \(\ell\) and crosssectional area \(A\). Find its inductance.(answer check available at lightandmatter.com) (b) Show that your answer has the right units to be an inductance.

Short Answer

Expert verified
The solenoid's inductance is \(L = \mu_0 \frac{N^2 A}{\ell}\), confirming this formula has units of inductance.

Step by step solution

01

Understanding the Solenoid Structure

A solenoid is a coil of wire that generates a magnetic field when an electric current passes through it. In this problem, the solenoid consists of \(N\) turns of wire, and it is uniformly wrapped over a hollow cylindrical shape having a length \(\ell\) and a cross-sectional area \(A\).
02

Finding the Magnetic Field Inside the Solenoid

The magnetic field inside the solenoid is given by the formula \( B = \mu_0 n I \) where \(\mu_0\) is the permeability of free space, \(n\) is the number of turns per unit length (\(n = \frac{N}{\ell}\)), and \(I\) is the current. Thus, \(B = \mu_0 \frac{N}{\ell} I\).
03

Calculating the Magnetic Flux

The magnetic flux \(\Phi\) through a single turn is found by multiplying the magnetic field \(B\) and the cross-sectional area \(A\). Therefore, \(\Phi = B A = \mu_0 \frac{N}{\ell} I A\).
04

Finding Total Magnetic Flux Linkage

The total magnetic flux linkage through the solenoid, accounting for all \(N\) turns, is \(\lambda = N \Phi = N \left( \mu_0 \frac{N}{\ell} I A \right) = \mu_0 \frac{N^2}{\ell} I A\).
05

Deriving the Inductance Formula

The inductance \(L\) of the solenoid is defined by \(\lambda = L I\). Substituting the expression for \(\lambda\), we get \(L I = \mu_0 \frac{N^2}{\ell} I A\). Solving for \(L\), we find \(L = \mu_0 \frac{N^2 A}{\ell}\).
06

Verifying Unit Consistency for Inductance

The formula for inductance is \(L = \mu_0 \frac{N^2 A}{\ell}\). Checking dimensions: Units of \(\mu_0\) are \(\text{T}\cdot\text{m/A}\), \(A\) is \(\text{m}^2\), and dividing by length \(\ell\) gives \(\text{m}^{-1}\). Thus, inductance \(L\) has units of \(\text{T}\cdot\text{m}^2/\text{A} = \text{H} (\text{henrys})\), consistent with an inductance unit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solenoid
A solenoid is an intriguing electromagnetic structure. Imagine it as a long coil of wire, designed to create a magnetic field whenever an electric current passes through it. Think of a solenoid like a tightly wound spring of wire, which in this exercise, is wrapped around a hollow cylinder.
This cylinder has particular characteristics: it has a length \( \ell \) and a cross-sectional area \( A \). These parameters significantly affect the behavior and properties of the solenoid. Typically, solenoids are used in devices where a controlled magnetic field is necessary. For instance, in electromagnets, actuators, and inductors.
Key things to remember about solenoids:
  • They consist of multiple turns or loops of wire.
  • They generate a magnetic field when current flows through them.
  • The field strength depends on the number of wire turns and the current's magnitude.
Magnetic Flux
Magnetic flux is a concept that describes the total magnetic field passing through a certain area. Imagine you're standing in a stream with water flowing around you; the water represents magnetic lines, and the area of your net catching them represents magnetic flux.
In mathematical terms, the magnetic flux \( \Phi \) is obtained by multiplying the magnetic field \( B \) with the area \( A \) it travels through, specifically: \( \Phi = B \times A \). In the context of a solenoid, this area is the cross-sectional area of the solenoid's cylinder.
Understanding magnetic flux helps you determine how much magnetic field is 'flowing' through a specific area. It's crucial because:
  • Higher flux means a stronger magnetic effect.
  • It helps in calculating the induced electromotive force (emf) in loops or coils.
Inductance
Inductance is a property of an electrical component that defines its ability to store energy in a magnetic field. When a current flows through a coil, like a solenoid, an induced magnetic field is created. Inductance measures how effectively this field is maintained against changes in current.
The formula for inductance \( L \) in a solenoid relates directly to factors like the number of turns of the coil \( N \), the solenoid's cross-sectional area \( A \), the length \( \ell \) of the solenoid, and the permeability \( \mu_0 \). In short: \( L = \mu_0 \frac{N^2 A}{\ell} \).
When a current in the solenoid changes, the inductance quantifies the resulting change in magnetic flux. Key points about inductance include:
  • It is measured in henrys (H).
  • Higher inductance means better energy storage in the magnetic field.
Magnetic Field
A magnetic field is an invisible field around a magnetic object, such as a solenoid, that exerts a magnetic force on other magnetic or susceptible objects.
For a solenoid, a crucial formula is \( B = \mu_0 \frac{N}{\ell} I \), where \( B \) is the magnetic field inside the solenoid. The strength of the magnetic field depends on:
  • The number of turns, \( N \).
  • The current, \( I \).
  • The solenoid's length, \( \ell \).

By increasing the number of turns or the current, you can increase the magnetic field inside the solenoid. This concept is vital in creating devices that require controlled magnetic environments like MRI machines or electric motors.
The magnetic field is powerful because:
  • It can attract or repel other magnetic objects.
  • It is essential for the operation of various electromagnetic devices.
Permeability
Permeability is a measure of how easy it is for a magnetic field to pass through a material. It greatly influences the magnetic field within materials like those making up a solenoid. The intrinsic permeability of a material is denoted by \( \mu_0 \), the permeability of free space.
In simpler terms, permeability determines the efficiency of a magnetic field in a material. Higher permeability means a material can support stronger magnetic fields. For instance, in our solenoid exercise, \( \mu_0 \) helps determine the magnetic field's strength inside the solenoid.
To summarize:
  • If the material's permeability is high, it will enhance the magnetic field within the solenoid.
  • \

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Most popular questions from this chapter

A charged particle is released from rest. We see it start to move, and as it gets going, we notice that its path starts to curve. Can we tell whether this region of space has \(\mathbf{E} \neq 0\), or \(\mathbf{B} \neq 0\), or both? Assume that no other forces are present besides the possible electrical and magnetic ones, and that the fields, if they are present, are uniform.

Two long, parallel strips of thin metal foil form a configuration like a long, narrow sandwich. The air gap between them has height \(h\), the width of each strip is \(w\), and their length is \(\ell\). Each strip carries current \(I\), and we assume for concreteness that the currents are in opposite directions, so that the magnetic force, \(F\), between the strips is repulsive. (a) Find the force in the limit of \(w \gg h\).(answer check available at lightandmatter.com) (b) Find the force in the limit of \(w \ll h\), which is like two ordinary wires. (c) Discuss the relationship between the two results.

Electromagnetic waves are supposed to have their electric and magnetic fields perpendicular to each other. (Throughout this problem, assume we're talking about waves traveling through a vacuum, and that there is only a single sine wave traveling in a single direction, not a superposition of sine waves passing through each other.) Suppose someone claims they can make an electromagnetic wave in which the electric and magnetic fields lie in the same plane. Prove that this is impossible based on Maxwell's equations.

A charged particle of mass \(m\) and charge \(q\) moves in a circle due to a uniform magnetic field of magnitude \(B\), which points perpendicular to the plane of the circle. a. Assume the particle is positively charged. Make a sketch showing the direction of motion and the direction of the field, and show that the resulting force is in the right direction to produce circular motion. b. Find the radius, \(r\), of the circle, in terms of \(m\), \(q\), \(v\), and \(B\).(answer check available at lightandmatter.com) c. Show that your result from part b has the right units. d. Discuss all four variables occurring on the right-hand side of your answer from part b. Do they make sense? For instance, what should happen to the radius when the magnetic field is made stronger? Does your equation behave this way? e. Restate your result so that it gives the particle's angular frequency, \(\omega\), in terms of the other variables, and show that \(v\) drops out.(answer check available at lightandmatter.com)

Magnet coils are often wrapped in multiple layers. The figure shows the special case where the layers are all confined to a single plane, forming a spiral. Since the thickness of the wires (plus their insulation) is fixed, the spiral that results is a mathematical type known as an Archimedean spiral, in which the turns are evenly spaced. The equation of the spiral is \(r=w \theta\), where \(w\) is a constant. For a spiral that starts from \(r=a\) and ends at \(r=b\), show that the field at the center is given by \(\left(k I / c^{2} w\right) \ln b / a\).(solution in the pdf version of the book)

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