/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A sonometer wire having a length... [FREE SOLUTION] | 91Ó°ÊÓ

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A sonometer wire having a length of \(1 \cdot 50 \mathrm{~m}\) between the bridges vibrates in its second harmonic in resonance with a tuning fork of frequency \(256 \mathrm{~Hz}\). What is the speed of the transverse wave on the wire?

Short Answer

Expert verified
The speed of the transverse wave on the wire is 384 m/s.

Step by step solution

01

Understanding the Problem

We are given a sonometer wire vibrating in its second harmonic with a tuning fork at a frequency of 256 Hz. We need to calculate the speed of the wave on the wire.
02

Identifying the Formula

The frequency of a harmonic of a string (or wire), which is fixed at both ends, is given by the formula \( f = \frac{n \cdot v}{2L} \), where \( n \) is the harmonic number, \( v \) is the speed of the wave, and \( L \) is the length of the wire.
03

Substituting the Values

For the second harmonic, \( n = 2 \). Given that \( f = 256 \, \text{Hz} \) and \( L = 1.50 \, \text{m} \), substituting these values into the formula gives us \( 256 = \frac{2 \cdot v}{2 \cdot 1.5} \).
04

Simplifying the Equation

Simplify \( 256 = \frac{v}{1.5} \) to find \( v \). Multiply both sides by 1.5 to isolate \( v \): \( v = 256 \times 1.5 \).
05

Calculating the Speed

Perform the multiplication: \( v = 384 \, \text{m/s} \). This is the speed of the transverse wave on the wire.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonics
Harmonics are an essential concept in the study of waves and vibrations. When a string vibrates, it can do so in various modes called harmonics. Each harmonic represents a specific pattern of nodes and antinodes along the length of the string. The first harmonic is the simplest pattern, with only one antinode. It is often referred to as the fundamental frequency because it has the lowest frequency of all the harmonics for that string.

The second harmonic, which is relevant to our original exercise, is the next simplest mode and has two antinodes. This means the string vibrates in such a way that it forms one complete wave along its length, between the fixed ends. The number of complete waves vibrating between the fixed ends increases with each higher harmonic. These harmonics are integral multiples of the fundamental frequency, meaning that the frequency of the second harmonic is twice that of the first.

The importance of harmonics lies in their application, as they are fundamental to understanding how musical instruments work, how sound is produced, and even how electromagnetic waves behave.
Resonance
Resonance is another vital concept when dealing with wave phenomena. It occurs when a system vibrates with maximum amplitude at a particular frequency. This frequency is known as the resonant frequency. In the context of strings and wires, resonance can happen when an external force, like a tuning fork, is applied at a frequency that matches one of the natural frequencies of the string.

In our example with the sonometer wire, resonance was achieved with a tuning fork of 256 Hz, leading the wire to vibrate in its second harmonic. The energy from the tuning fork was efficiently transferred to the wire at this frequency because they were in resonance. When systems resonate, even small periodic forces can produce large amplitude vibrations, which is why bridges can dangerously sway and instruments produce loud sounds when in resonance.

Understanding resonance allows us to manipulate and utilize energy more efficiently, whether it is in engineering, music, or other fields.
Frequency
Frequency is a fundamental element of wave mechanics, describing how many waves pass a given point per second. It is measured in Hertz (Hz), where one Hz equals one cycle per second. In our exercise, the frequency of 256 Hz indicated the number of times the string completed a vibration cycle every second.

The frequency of a wave is determined by a combination of the wave's speed and the medium's properties through which it travels. When the frequency matches one of the natural frequencies of the system, as it did with the 256 Hz tuning fork and the sonometer wire, resonance occurs.

To calculate the speed of a wave on a string, we use the relationship between frequency, wave speed, and wavelength. This relationship is given by the formula \( f = \frac{v}{\lambda} \), where \( f \) is the frequency, \( v \) is the wave speed, and \( \lambda \) is the wavelength. For strings with fixed ends, the wavelength of the nth harmonic is given by \( \lambda = \frac{2L}{n} \), where \( L \) is the length of the string, and \( n \) is the harmonic number. Through understanding frequency, we can predict and calculate wave behaviors across various scenarios.

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Most popular questions from this chapter

Two waves, each having a frequency of \(100 \mathrm{~Hz}\) and a wavelength of \(2 \cdot 0 \mathrm{~cm}\), are travelling in the same direction on a string. What is the phase difference between the waves (a) if the second wave was produced \(0-015\) s later than the first one at the same place, \((b)\) if the two waves were produced at the same instant but the first one was produced a distance \(4 \cdot 0 \mathrm{~cm}\) behind the second one? (c) If each of the waves has an amplitude of \(2 \cdot 0 \mathrm{~mm}\), what would be the amplitudes of the resultant waves in part (a) and (b)?

A motorcycle has to move with a constant speed on an overbridge which is in the form of a circular arc of radius \(R\) and has a total length \(L\). Suppose the motorcycle starts from the highest point. (a) What can its maximum velocity be for which the contact with the road is not broken at the highest point ? (b) If the motorcycle goes at speed \(1 / \sqrt{2}\) times the maximum found in part (a), where will it lose the contact with the road ? (c) What maximum uniform speed can it maintain on the bridge if it does not lose contact anywhere on the bridge?

Suppose the amplitude of a simple pendulum having a bob of mass \(m\) is \(\theta_{0} .\) Find the tension in the string when the bob is at its extreme position.

A one-metre long stretched string having a mass of \(40 \mathrm{~g}\) is attached to a tuning fork. The fork vibrates at \(128 \mathrm{~Hz}\) in a direction perpendicular to the string. What should be the tension in the string if it is to vibrate in four loops?

A transverse wave described by $$ y=(0 \cdot 02 \mathrm{~m}) \sin \left[\left(1 \cdot 0 \mathrm{~m}^{-1}\right) x+\left(30 \mathrm{~s}^{-1}\right) t\right] $$ propagates on a stretched string having a linear mass density of \(1 \cdot 2 \times 10^{-4} \mathrm{~kg} \mathrm{~m}^{-1}\). Find the tension in the string.

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